28.07.2020

the flywheel on a steam engine rotates at 60 revolutions every 15 seconds what is the flywheels rate of revolutions per second (unit rate)?

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23.01.2022, solved by verified expert
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Answer : rate of revolutions per second = 15

Solution:

Number of revolution in 15 second = 60

By unitary method,

Number of revolution in 1 second = 60/15 = 4

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StudenGPT
Step-by-step answer
P Answered by Studen AI
To find the flywheel's rate of revolutions per second, we can use the concept of unit rates. The unit rate is a rate in which the denominator is 1 unit. Let's break down the problem step by step:

Given:
- The flywheel rotates 60 revolutions in 15 seconds.

Step 1: Find the rate of revolutions per second.
To do this, we can divide the total number of revolutions by the total number of seconds.

Rate = Total revolutions / Total seconds

In this case, the total revolutions is 60, and the total seconds is 15.

Rate = 60 revolutions / 15 seconds

Step 2: Simplify the rate.
To simplify the rate, we can divide both the numerator and denominator by their greatest common divisor (gcd), which is 15.

Rate = (60 / 15) revolutions / (15 / 15) seconds

Simplifying further, we have:

Rate = 4 revolutions / 1 second

Step 3: Identify the unit rate.
Since the denominator is now 1 unit, we can say that the unit rate is:

Unit rate = 4 revolutions per second

Step 4: Identify the rate unit.
The rate unit is the unit of measurement used in the rate. In this case, the rate unit is "revolutions per second."

So, the solutions are:
- The flywheel's rate of revolutions per second is 4 revolutions per second.
- The unit rate is 4 revolutions per second, with a rate unit of "revolutions per second."

Math Laws Used:
- Division: We divided the total revolutions by the total seconds to find the rate.
- Simplification: We simplified the rate by dividing both the numerator and denominator by their greatest common divisor (gcd).
Mathematics
Step-by-step answer
P Answered by Master

The flywheel rate of the flywheel is 4 revolutions per second.

Step-by-step explanation:

Mathematics
Step-by-step answer
P Answered by PhD

The flywheel rate of the flywheel is 4 revolutions per second.

Step-by-step explanation:

From Rotation Physics we understand that flywheel rotates at constant rate. In this case, angular speed (\dot n), measured in revolutions per second, is the number of revolutions done by the flywheel at a given interval of time. That is:

\dot n = \frac{n}{t}(Eq. 1)

Where:

n - Number of revolutions done, measured in revolutions.

t - Time, measured in seconds.

If we know that n = 60\,rev and t = 15\,s, then the angular speed of the flywheel is:

\dot n = \frac{60\,rev}{15\,s}

\dot n = 4\,\frac{rev}{s}

The flywheel rate of the flywheel is 4 revolutions per second.

Mathematics
Step-by-step answer
P Answered by Master

The flywheel rate of the flywheel is 4 revolutions per second.

Step-by-step explanation:

Mathematics
Step-by-step answer
P Answered by PhD

The flywheel rate of the flywheel is 4 revolutions per second.

Step-by-step explanation:

From Rotation Physics we understand that flywheel rotates at constant rate. In this case, angular speed (\dot n), measured in revolutions per second, is the number of revolutions done by the flywheel at a given interval of time. That is:

\dot n = \frac{n}{t}(Eq. 1)

Where:

n - Number of revolutions done, measured in revolutions.

t - Time, measured in seconds.

If we know that n = 60\,rev and t = 15\,s, then the angular speed of the flywheel is:

\dot n = \frac{60\,rev}{15\,s}

\dot n = 4\,\frac{rev}{s}

The flywheel rate of the flywheel is 4 revolutions per second.

Mathematics
Step-by-step answer
P Answered by PhD

SI=(P*R*T)/100

P=2000

R=1.5

T=6

SI=(2000*1.5*6)/100

=(2000*9)/100

=180

Neil will earn interest of 180

Mathematics
Step-by-step answer
P Answered by PhD

Cost of 7 gallons=$24.50

Cost of 1 gallon=24.50/7=3.5

Cost of 15 gallons=15*3.5=52.5

Cost of 15 gallons will be $52.5

Mathematics
Step-by-step answer
P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

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