01.01.2021

Tyler went to the supermarket to buy food for a food pantry. he has $36, and can carry up to 20 pounds of food in his backpack. pasta costs $1 for a 1-pound package. pasta sauce costs $3 for a 1.5 pound jar. let x = the number of packages of pasta and y = the number of jars of pasta sauce. identify each point as either a solution to the system or not a solution to the system of inequalities. which ones are a solution or not to this problem? asap (1, 12) solution or non solution? (2, 10) solution or non solution? (4, 5) solution or non solution? (6, 8.25) solution or non solution? (12, 8) solution or non solution? (18, 6)solution or non solution?

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Faq

Mathematics
Step-by-step answer
P Answered by Master

8 packages

8 jars of sauce

Step-by-step explanation:

As you need just the same amount of pasta and sauce, you only need to create an equation, you can represent the sauce with an x and the pasta with a Y, so your equation would be:

3x + 1y= 36

since X=Y in number your new equation would be:

3x+ 1x=36

4x=36

x=\frac{36}{9}

x=9

The other equation would be:

1.5x + 1y= 20

Since x equals y the equation will end up like this:

1.5x+1x=20

2.5x=20

x=8

Since 8 is the number that best suits the needs for the carying capacities, and you´ll end up with 3 extra bucks, but you cant buy the 9 and 9 and then can´t carry them in the backpack.

Mathematics
Step-by-step answer
P Answered by PhD
You start of with $36... & you can only hold 20 lbs...
1+3=4 ($32 left)
1+1.5=2.5 (Can still hold 17.5 lbs.)
1+3=4 ($28 left)
1+1.5=2.5 (Can still hold 15 lbs.)
1+3=4 ($24 left)
1+1.5=2.5 (Can still hold 12.5 lbs.)
1+3=4 ($20 left)
1+1.5=2.5 (Can still hold 10 lbs.)
1+3=4 ($16 left)
1+1.5=2.5 (Can still hold 7.5 lbs.)
1+3=4 ($12 left)
1+1.5=2.5 (Can still hold 5 lbs.)
1+3=4 ($8 left)
1+1.5=2.5 (Can still hold 2.5 lbs.)
1+3=4 ($4 left)
1+1.5=2.5 (You've reached the limit that the back-bag can hold)

So the answer would be 8 packages of pasta & 8 jars of pasta sauce
Mathematics
Step-by-step answer
P Answered by Specialist

8 packages

8 jars of sauce

Step-by-step explanation:

As you need just the same amount of pasta and sauce, you only need to create an equation, you can represent the sauce with an x and the pasta with a Y, so your equation would be:

3x + 1y= 36

since X=Y in number your new equation would be:

3x+ 1x=36

4x=36

x=\frac{36}{9}

x=9

The other equation would be:

1.5x + 1y= 20

Since x equals y the equation will end up like this:

1.5x+1x=20

2.5x=20

x=8

Since 8 is the number that best suits the needs for the carying capacities, and you´ll end up with 3 extra bucks, but you cant buy the 9 and 9 and then can´t carry them in the backpack.

Mathematics
Step-by-step answer
P Answered by Master

option A: x + 1.5y ≤ 20

option C: x + 3y ≤ 36

option D: x ≥ 0

option H: y ≥ 0

Step-by-step explanation:

It says to assume x = the number of packages of pasta and y = the number of jars of pasta sauce.

Since the number of items can not be a negative number, we have x ≥ 0 and y ≥ 0.

Condition: He has $36, and can carry up to 20 pounds of food in his backpack.

Pasta costs $1 for a 1-pound package. Pasta sauce costs $3 for a 1.5 pound jar.

If he buys 'x' packs of pasta and 'y' jars of pasta sauce, then:-

Total cost = 1x + 3y ≤ 36 dollars.

and Total weight = 1x + 1.5y ≤ 20 pounds.

Hence, we have four inequalities:-

option A: x + 1.5y ≤ 20

option C: x + 3y ≤ 36

option D: x ≥ 0

option H: y ≥ 0

Mathematics
Step-by-step answer
P Answered by Master

option A: x + 1.5y ≤ 20

option C: x + 3y ≤ 36

option D: x ≥ 0

option H: y ≥ 0

Step-by-step explanation:

It says to assume x = the number of packages of pasta and y = the number of jars of pasta sauce.

Since the number of items can not be a negative number, we have x ≥ 0 and y ≥ 0.

Condition: He has $36, and can carry up to 20 pounds of food in his backpack.

Pasta costs $1 for a 1-pound package. Pasta sauce costs $3 for a 1.5 pound jar.

If he buys 'x' packs of pasta and 'y' jars of pasta sauce, then:-

Total cost = 1x + 3y ≤ 36 dollars.

and Total weight = 1x + 1.5y ≤ 20 pounds.

Hence, we have four inequalities:-

option A: x + 1.5y ≤ 20

option C: x + 3y ≤ 36

option D: x ≥ 0

option H: y ≥ 0

Mathematics
Step-by-step answer
P Answered by PhD

Solutions: (2,10), (4,5)

Not solutions: (1,12), (6,10), (12,8), (18,6)

Step-by-step explanation:

Let x be the number of packages of pasta and y be the number of jars of pasta sauce. If pasta costs $1 for a 1-pound package, then x packages of pasta cost $x and weigh x pounds. If pasta sauce costs $3 for a 1.5 pound jar, then y jars cost $3y and weigh 1.5y pounds.

1. Tyler has $36, then

x+3y\le 36.

2. Tyler can carry up to 20 pounds of food in his backpack, then

x+1.5y\le 20.

You get the following system of inequalities:

\left\{\begin{array}{l}x+3y\le 36\\ x+1.5y\le 20\end{array}\right.

Now substitute the coordinates of each point:

(1,12):

\left\{\begin{array}{l}1+3\cdot 12=37 36\\ 1+1.5\cdot 12=19\le 20\end{array}\right.

False, because first inequality doesn't hold.

(2,10):

\left\{\begin{array}{l}2+3\cdot 10=32\le 36\\ 2+1.5\cdot 10=17\le 20\end{array}\right.

True, both inequalities hold.

(4,5):

\left\{\begin{array}{l}4+3\cdot 5=19\le 36\\ 4+1.5\cdot 5=11.5\le 20\end{array}\right.

True, both inequalities hold.

(6,10):

\left\{\begin{array}{l}6+3\cdot 10=36\le 36\\ 6+1.5\cdot 10=21 20\end{array}\right.

False, because secondt inequality doesn't hold.

(12,8):

\left\{\begin{array}{l}12+3\cdot 8=36\le 36\\ 12+1.5\cdot 8=24 20\end{array}\right.

False, because second inequality doesn't hold.

(18,6):

\left\{\begin{array}{l}18+3\cdot 6=36\le 36\\ 18+1.5\cdot 6=27 20\end{array}\right.

False, because second inequality doesn't hold.

Mathematics
Step-by-step answer
P Answered by PhD
solutions: (2, 10), (4, 5)non-solutions: all other points

Step-by-step explanation:

It can be useful to graph the inequalities related to Tyler's limits of money and weight.

  1x +3y ≤ 36 . . . . . . the limit on the cost of the items Tyler can afford

  1x +1.5y ≤ 20 . . . . . the limit on the weight of the items Tyler can carry

Then plotting the given points shows that only (2, 10) and (4, 5) are in the doubly-shaded area that is the solution space. The other points are not a solution.


Tyler went to the supermarket to buy food for a food pantry. he has $36, and can carry up to 20 poun

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