Mathematics : asked on aiueo946
 19.04.2020

Given: ∠aob is a central angle and ∠acb is a circumscribed angle. prove: △aco ≅ △bco we are given that angle aob is a central angle of circle o and that angle acb is a circumscribed angle of circle o. we see that ao ≅ bo because we also know that ac ≅ bc since using the reflexive property, we see that therefore, we conclude that △aco is congruent to △bco by the

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17.02.2022, solved by verified expert
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Given: Given: ∠aob is a central angle and ∠acb is a, №15221371, 19.04.2020 05:11 is a central angle and Given: ∠aob is a central angle and ∠acb is a, №15221371, 19.04.2020 05:11 is a circumscribed angle.  (where, AC and CB are two tangent lines from an external point C.)

Prove: Given: ∠aob is a central angle and ∠acb is a, №15221371, 19.04.2020 05:11


We are given that angle AOB is a central angle of circle O and that angle ACB is a circumscribed angle of circle O. We see thatGiven: ∠aob is a central angle and ∠acb is a, №15221371, 19.04.2020 05:11 because both OA and OB make the radius of the circle O. (Since,  A and B are points on the circumference of circle O So, they are equally far from the center O


We also know that Given: ∠aob is a central angle and ∠acb is a, №15221371, 19.04.2020 05:11 since both are the tangent line from a common point C So, they must be equal.(By the property of tangent line)


Using the reflexive property, we see that Given: ∠aob is a central angle and ∠acb is a, №15221371, 19.04.2020 05:11


Therefore, we conclude that Given: ∠aob is a central angle and ∠acb is a, №15221371, 19.04.2020 05:11 by the SSS postulate.


Given: ∠aob is a central angle and ∠acb is a, №15221371, 19.04.2020 05:11
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