Question:
Match its group with its percentage or mean using the table below.
Answer:
(1)
Mean length of all fish in the sample -
Mean = (Sum of observations)/(Number of observations)
= (12 + 5 + 3 + 5 + 8 + 2 + 10 + 9 + 4 + 4)/(10)
= 62/10
= 6.2
(2)
Mean length of adult fish in the sample -
Mean = (Sum of observations)/(Number of observations)
= (12 + 5 + 8 + 10)/(4)
= 35/4
= 8.75
(3)
Mean length of juvenile fish in the sample -
Mean = (Sum of observations)/(Number of observations)
= (5 + 3 + 2 + 9 + 4 + 4)/(6)
= 27/6
= 4.5
(4)
Percentage of sample that were adult fish -
Percentage = (No. of adult fishes)/(Total no. of fishes) × 100
% = (4/10) × 100
% = 40
(5)
Percentage of sample that were juvenile fish -
Percentage = (No. of juvenile fishes)/(Total no. of fishes) × 100
% = (6/10) × 100
% = 60
(6)
Percentage of sample that were juveniles over 8 inches long -
Percentage = (No. of juveniles over 8 inches)/(Total no. of fishes) × 100
% = (1/10) × 100
% = 10