Explain why the graphing calculator cannot be used to solve or approximate solutions to all polynomial equations.

0.02381

Step-by-step explanation:

As we know that

We have 10 digits i.e 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 0 out of these 5 are odd digits 1, 3, 5, 7, 9.

A security alarm needs a code of four digits that includes only odd values

In the first position of the code is 1 digit from 5 odd digits.

In the second position of the code is 1 digit from 4 digits left.

In the third place it is 1 from 3 digits left

And the last fourth position is 1 from 2 odd digits left

Now we can generate 5: 4: 3: 2 = 120 distinct four-digit code only with odd different numbers in total.

Likewise we can count how much of different codes you can generated from all digits

In the first position of the code it is 1 digit from 10 digits,

In the second position of the code it is 1 digit from 9 digits left,

In the third place it is 8 digits left

And the last fourth position it is 7 digits left.

Now overall you can generate 10:9:8:7 = 5040 that contains different four-digit code by considering different digits.

So, the probability is

Probability = 0.2381

Step-by-step explanation:

A security alarm requires a four digit code by using 0 - 9 and the digits cannot be repeated.

First we calculate how many codes can be made.

Combination =

Where n = 10 and r = 4

=

         =

         = 10 × 9 × 8 × 7

        = 5,040 combinations.

Now we have to find the probability that the code contains only odd numbers. So in 0-9 the odd numbers are = 1, 3, 5, 7, 9

There are 5 odd numbers and we have to make a code of 4 numbers.

Therefore, On first place there are 5 options and in second place 4 options, in third place there are 3 options and in fourth place we have only 2 options.

5 × 4 × 3 × 2  = 120 combinations.

Total combinations of odd numbers are 120.

Then the probability that the code contains only odd numbers is

= 0.0238095 ≈  0.02381

Probability = 0.2381

Step-by-step explanation:

Given that there are 19 digits.  Out of these, a three digit personal identification number is chosen.  There is no repitition of digits.

Total number of digits that can be selected out of 19 digits without repitition

=19P3

=19(18)(17)

Total number of digits that can be selected with 6 as first digit

= Number of selecting 2 digits from the remaining 18 digits without repitition

=18(17)

Hence required probability

= probability that the first digit will be 6

=

C

Step-by-step explanation:it’s the 3rd ans on edge

0.02381

Step-by-step explanation:

Given: The number of digits from which a security code is made (0-9) = 10

The number of odd digits (1, 3, 5, 7, 9 )= 5

By using Permutations , the number of ways to make a four digit number such that no digit is repeated :-

The number total number of ways of making four digit number from the 10 digits such that no digit is repeated:-

The probability that the code only contains odd number is given by :-

Hence, the approximate probability that the code only contains odd number = 0.02381

Step-by-step explanation:

Given: A three-digit personal identification number is chosen using the digits 1-9.

The total ways to create a hree-digit personal identification number is chosen using the digits 1-9 is given by :-

The number of  ways to create a three-digit personal identification number is chosen using the digits 1-9 such that the first digit will be 6 (only two digit's place left to fill) is given by :-

Now, the approximate probability that the first digit will be 6=

0.02381

Step-by-step explanation:

As we know that

We have 10 digits i.e 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 0 out of these 5 are odd digits 1, 3, 5, 7, 9.

A security alarm needs a code of four digits that includes only odd values

In the first position of the code is 1 digit from 5 odd digits.

In the second position of the code is 1 digit from 4 digits left.

In the third place it is 1 from 3 digits left

And the last fourth position is 1 from 2 odd digits left

Now we can generate 5: 4: 3: 2 = 120 distinct four-digit code only with odd different numbers in total.

Likewise we can count how much of different codes you can generated from all digits

In the first position of the code it is 1 digit from 10 digits,

In the second position of the code it is 1 digit from 9 digits left,

In the third place it is 8 digits left

And the last fourth position it is 7 digits left.

Now overall you can generate 10:9:8:7 = 5040 that contains different four-digit code by considering different digits.

So, the probability is

d00.02381 is the answer

Step-by-step explanation:

Given that there are 19 digits.  Out of these, a three digit personal identification number is chosen.  There is no repitition of digits.

Total number of digits that can be selected out of 19 digits without repitition

=19P3

=19(18)(17)

Total number of digits that can be selected with 6 as first digit

= Number of selecting 2 digits from the remaining 18 digits without repitition

=18(17)

Hence required probability

= probability that the first digit will be 6

=

The correct answer is:

C. 0.11111

The approximate probability that the first digit will be 6 is 0.11111.