Given volume of square pyramid V= 245in³
Height of pyramid h = 15 in
Let a is the base edge of pyramid.
So area of base A = a²
Volume of square pyramid = area of base × height/3
245= a²× 15/3
a²×5 = 245
a² = 245/5
a² = 49
a = √49
a = 7
Therefore base edge of pyramid = 7 in
Area of base = 49 in²