a) The error is that, the initial value is n=1 NOT n=3
b) The sum is
c)The explicit formula is
The recursive formula is ,
Step-by-step explanation:
The given arithmetic series is 8 + 13 + ... + 43.
The first term is , the common difference is
The nth term is given by:
We substitute the values to get:
To find how many terms are in the sequence we solve the equation:
The summation notation is
The error the student made is in the initial value.
It should be n=1 NOT n=3
b) The sum of the arithmetic series is calculated using:
We substitute o get:
c) The explicit formula we already calculated in a), which is
The recursive formula is given as:
We substitute d=5 to get:
a) The error is that, the initial value is n=1 NOT n=3
b) The sum is
c)The explicit formula is
The recursive formula is ,
Step-by-step explanation:
The given arithmetic series is 8 + 13 + ... + 43.
The first term is , the common difference is
The nth term is given by:
We substitute the values to get:
To find how many terms are in the sequence we solve the equation:
The summation notation is
The error the student made is in the initial value.
It should be n=1 NOT n=3
b) The sum of the arithmetic series is calculated using:
We substitute o get:
c) The explicit formula we already calculated in a), which is
The recursive formula is given as:
We substitute d=5 to get:
Step-by-step explanation:
Occurrence Year seen Difference
1 1949 -
2 1956 1956 - 1949 = 7
3 1963 1963 - 1956 = 7
4 1970 1970 - 1963 = 7
Difference between each successive term of year seen = 7 years
Therefore, there is a common difference of 7 years between each successive term.
Function defining the year seen will be a linear function and will increase in the same pattern. (multiple of 7 years)
2017 - 1970 = 47 (It's not the multiple of 7)
2018 - 1970 = 48 (It's not the multiple of 7)
2019 - 1970 = 49 (multiple of 7)
2020 - 1970 = 50 (It's not the multiple of 7)
Therefore, comet will be seen next in 2019.
Option (C) will be the answer.
If a person is born in 2005
Then difference between 2005 and 1949 = 56 years
Number of times comet seen after 1949 = times
Total number of comet seen in the lifetime = 8 times
Step-by-step explanation:
Occurrence Year seen Difference
1 1949 -
2 1956 1956 - 1949 = 7
3 1963 1963 - 1956 = 7
4 1970 1970 - 1963 = 7
Difference between each successive term of year seen = 7 years
Therefore, there is a common difference of 7 years between each successive term.
Function defining the year seen will be a linear function and will increase in the same pattern. (multiple of 7 years)
2017 - 1970 = 47 (It's not the multiple of 7)
2018 - 1970 = 48 (It's not the multiple of 7)
2019 - 1970 = 49 (multiple of 7)
2020 - 1970 = 50 (It's not the multiple of 7)
Therefore, comet will be seen next in 2019.
Option (C) will be the answer.
If a person is born in 2005
Then difference between 2005 and 1949 = 56 years
Number of times comet seen after 1949 = times
Total number of comet seen in the lifetime = 8 times
Part A)AT=16x^2
Part B)AT=4b^2 +12x^2
Step-by-step explanation:
Part A:
length of each side of square in tile=x
length of each small base side of trapezoid in tile=x
length of each large base side of trapezoid in tile=2x
height of each trapezoid in tile=x
Area of each square in tile= x^2
Area of each trapezoid in tile= x(x+2x)/2
= (3x^2)/2
area of squares inside tile= 4(x^2)
area of trapezoids inside tile= 8[(3x^2)/2]
Area of tile, AT= area of squares inside tile+area of trapezoids in tile
AT= 4(x^2) + 8[(3x^2)/2]
= 4x^2 + 12x^2
= 16x^2
Part B)
if If the tile is a square with a length of b centimeters then AT
= 4b^2 +12x^2 !
Part A)AT=16x^2
Part B)AT=4b^2 +12x^2
Step-by-step explanation:
Part A:
length of each side of square in tile=x
length of each small base side of trapezoid in tile=x
length of each large base side of trapezoid in tile=2x
height of each trapezoid in tile=x
Area of each square in tile= x^2
Area of each trapezoid in tile= x(x+2x)/2
= (3x^2)/2
area of squares inside tile= 4(x^2)
area of trapezoids inside tile= 8[(3x^2)/2]
Area of tile, AT= area of squares inside tile+area of trapezoids in tile
AT= 4(x^2) + 8[(3x^2)/2]
= 4x^2 + 12x^2
= 16x^2
Part B)
if If the tile is a square with a length of b centimeters then AT
= 4b^2 +12x^2 !
It will provide an instant answer!