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Mathematics : asked on bunnybuge4
 17.09.2022

Abasketball player is shooting a basketball toward the net. the height, in feet, of the ball t seconds after the shot is modeled by the equation h = 6 + 30t – 16t2. two-tenths of a second after the shot is launched, an opposing player leaps up to block the shot. the height of the shot blocker’s outstretched hands t seconds after he leaps is modeled by the equation h = 9 + 25t – 16t2. if the ball reaches the net 1.7 seconds after the shooter launches it, does the leaping player block the shot?
yes, exactly 0.6 seconds after the shot is launched.
yes, between 0.64 seconds and 0.65 seconds after the shot is launched
yes, between 0.84 seconds and 0.85 seconds after the shot is launched.
no, the shot is not blocked.

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Step-by-step answer

18.10.2022, solved by verified expert
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Rajat Thapa
s Specialist
Mathematics, DAV Post Graduate College
5 197 answers
4.9 . rating
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Answer: C. yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

Explanation:
The equation for ball height: 6+30*t-16*t^2;
The equation for shot blocker's height: 9+25*t-16*t^2.
But, the shot is made before two tenths of a second or 0.2 seconds therefore modified equation for ball height is :
6+30*(t-0.2)-16*(t-0.2)^2.
Now for the shot to be blocked,the height of shot blocker must be greater than the height of the ball which is shot before 0.2 seconds :
=> 9+25*t-16*t^2>6+30*(t-0.2)-16*(t-0.2)^2;
=> 9+25*t-16*t^2>6+30*t-6-16*(t^2-0.4*t+0.04);
=> 9+25*t-16*t^2>30*t-16*t^2+6.4*t-0.64;
=> 9.64>11.4*t.
=> t<9.64/11.4=0.846.
Hence, the shot was blocked between 0.84 and 0.85 seconds after the shot is launched.
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Rajat Thapa
s Specialist
Mathematics, DAV Post Graduate College
5 197 answers
4.9 . rating
Unlock the full answer

Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

Step-by-step explanation:

Abasketball player is shooting a basketball toward, №15237258, 17.09.2022 09:33

But, the shot is made before two tenths of a second or 0.2 seconds therefore modified equation for ball height is :

Abasketball player is shooting a basketball toward, №15237258, 17.09.2022 09:33

Now for the shot to be blocked,the height of shot blocker must be greater than the height of the ball which is shot before 0.2 seconds :

Abasketball player is shooting a basketball toward, №15237258, 17.09.2022 09:33

Hence, the shot was blocked between 0.84 and 0.85 seconds after the shot is launched.

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Faq

Mathematics
Abasketball player is shooting a basketball toward the net. the height, in feet, of the ball t seconds after the shot is modeled by the equation h = 6 + 30t – 16t2. two-tenths of a second after the shot is launched, an opposing player leaps up to block the shot. the height of the shot blocker s outstretched hands t seconds after he leaps is modeled by the equation h = 9 + 25t – 16t2. if the ball was on a path to reach the net 1.7 seconds after the shooter launches it, does the leaping player block the shot?
Step-by-step answer
P Answered by PhD
Answer: C. yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

Explanation:
The equation for ball height: 6+30*t-16*t^2;
The equation for shot blocker's height: 9+25*t-16*t^2.
But, the shot is made before two tenths of a second or 0.2 seconds therefore modified equation for ball height is :
6+30*(t-0.2)-16*(t-0.2)^2.
Now for the shot to be blocked,the height of shot blocker must be greater than the height of the ball which is shot before 0.2 seconds :
=> 9+25*t-16*t^2>6+30*(t-0.2)-16*(t-0.2)^2;
=> 9+25*t-16*t^2>6+30*t-6-16*(t^2-0.4*t+0.04);
=> 9+25*t-16*t^2>30*t-16*t^2+6.4*t-0.64;
=> 9.64>11.4*t.
=> t<9.64/11.4=0.846.
Hence, the shot was blocked between 0.84 and 0.85 seconds after the shot is launched.
Mathematics
A basketball player is shooting a basketball toward the net. The height, in feet, of the ball t seconds after the shot is modeled by the equation h = 6 + 30t – 16t2. Two-tenths of a second after the shot is launched, an opposing player leaps up to block the shot. The height of the shot blocker s outstretched hands t seconds after he leaps is modeled by the equation h = 9 + 25t – 16t2. If the ball was on a path to reach the net 1.7 seconds after the shooter launches it, does the leaping player block the shot?
Step-by-step answer
P Answered by Master
Answer: C. yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

Explanation:
The equation for ball height: 6+30*t-16*t^2;
The equation for shot blocker's height: 9+25*t-16*t^2.
But, the shot is made before two tenths of a second or 0.2 seconds therefore modified equation for ball height is :
6+30*(t-0.2)-16*(t-0.2)^2.
Now for the shot to be blocked,the height of shot blocker must be greater than the height of the ball which is shot before 0.2 seconds :
=> 9+25*t-16*t^2>6+30*(t-0.2)-16*(t-0.2)^2;
=> 9+25*t-16*t^2>6+30*t-6-16*(t^2-0.4*t+0.04);
=> 9+25*t-16*t^2>30*t-16*t^2+6.4*t-0.64;
=> 9.64>11.4*t.
=> t<9.64/11.4=0.846.
Hence, the shot was blocked between 0.84 and 0.85 seconds after the shot is launched.
Mathematics
Abasketball player is shooting a basketball toward the net. the height, in feet, of the ball t seconds after the shot is modeled by the equation h = 6 + 30t – 16t2. two-tenths of a second after the shot is launched, an opposing player leaps up to block the shot. the height of the shot blocker’s outstretched hands t seconds after he leaps is modeled by the equation h = 9 + 25t – 16t2. if the ball was on a path to reach the net 1.7 seconds after the shooter launches it, does the leaping player block the shot?
Step-by-step answer
P Answered by PhD
Answer: C. yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

Explanation:
The equation for ball height: 6+30*t-16*t^2;
The equation for shot blocker's height: 9+25*t-16*t^2.
But, the shot is made before two tenths of a second or 0.2 seconds therefore modified equation for ball height is :
6+30*(t-0.2)-16*(t-0.2)^2.
Now for the shot to be blocked,the height of shot blocker must be greater than the height of the ball which is shot before 0.2 seconds :
=> 9+25*t-16*t^2>6+30*(t-0.2)-16*(t-0.2)^2;
=> 9+25*t-16*t^2>6+30*t-6-16*(t^2-0.4*t+0.04);
=> 9+25*t-16*t^2>30*t-16*t^2+6.4*t-0.64;
=> 9.64>11.4*t.
=> t<9.64/11.4=0.846.
Hence, the shot was blocked between 0.84 and 0.85 seconds after the shot is launched.
Mathematics
An ice cream shop offers 5 different flavors of ice cream and 9 different toppings. How many choices are possible for a single serving of ice cream with one topping?
Step-by-step answer
P Answered by PhD

For 1 flavor there are 9 topping

Therefore, for 5 different flavors there will be 5*9 choices

No of choices= 5*9

=45 

Mathematics
A 4300-N force from a car s engines produces an acceleration of 3.3 m/s2. What is the mass of the car? A. 4300 kg B. 1300 kg C. 14,000 kg D. 390 kg
Step-by-step answer
P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Mathematics
Which number is the smallest? 4.4 ⋅ 10−5, 3.99 ⋅ 10−6, 2.6 ⋅ 102, 1.85 ⋅ 103
Step-by-step answer
P Answered by PhD

The answer is in the image 

The answer is in the image 
Mathematics
the surface area of a box is 232 square inches. the box is 4 inches wide and 8 inches long. what is the hight?
Step-by-step answer
P Answered by PhD

The solution is given in the image below

The solution is given in the image below
Mathematics
If a european swallow flies 15 meters every 1 second how many would kilometers would it fly in 15 minutes
Step-by-step answer
P Answered by PhD

Speed=Distance/time

Here,

distance=15m

time=1sec

speed=15/1=15m/sec

Distance=Speed*time

time=15min=15*60sec=900sec

Distance travelled in 15 min=15*900=13,500m

=13500/1000 km=13.5Km

Mathematics
Nick received an 82.5% on his math test. How many questions did he get right if there were a total of 40?
Step-by-step answer
P Answered by PhD

The answer is in the image 

The answer is in the image 
Mathematics
Of the 420 students enrolled in basic math, only 30% are first-year students. How many are first-year students? How many are not?
Step-by-step answer
P Answered by PhD

30% of 420 are first year students

first year students = (30/100 )*420

=126 students

Student who are not in first year = 420-126

=294 students  

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