26.06.2022

Factor this expression completely. x2 - r2

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30.05.2023, solved by verified expert
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This can be factored as a difference of two squares. When you have a difference of two squares (a² - b²), it will factor out into (a + b) (a - b).

(x² - r²)
(x + r)(x - r)

You can multiply the two groups to double check it.

(x + r)(x - r)
x² - rx + rx - r²
x² - r²
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Mathematics
Step-by-step answer
P Answered by Master
This can be factored as a difference of two squares. When you have a difference of two squares (a² - b²), it will factor out into (a + b) (a - b).

(x² - r²)
(x + r)(x - r)

You can multiply the two groups to double check it.

(x + r)(x - r)
x² - rx + rx - r²
x² - r²
Mathematics
Step-by-step answer
P Answered by PhD

2 ( 2x-3) (2x+3)

Step-by-step explanation:

8x^2 - 18

Factor out a 2

2(4x^2 -9)

Inside the parentheses is the difference of squares

2 ((2x)^2 - 3^2)

We know the difference of squares is (a^2 -b^2) = (a-b)(a+b)

2 ( 2x-3) (2x+3)

Mathematics
Step-by-step answer
P Answered by PhD

2 ( 2x-3) (2x+3)

Step-by-step explanation:

8x^2 - 18

Factor out a 2

2(4x^2 -9)

Inside the parentheses is the difference of squares

2 ((2x)^2 - 3^2)

We know the difference of squares is (a^2 -b^2) = (a-b)(a+b)

2 ( 2x-3) (2x+3)

Mathematics
Step-by-step answer
P Answered by PhD
(2x - 3)(2x - 3)
the answer to the question
Mathematics
Step-by-step answer
P Answered by Master

4(16x^2 - 1)

Step-by-step explanation:

You mean 64x^2 - 4? If so, we can take out a factor of 4 to get 4(16x^2 - 1)

Mathematics
Step-by-step answer
P Answered by PhD
(2x - 3)(2x - 3)
the answer to the question
Mathematics
Step-by-step answer
P Answered by Master

4(16x^2 - 1)

Step-by-step explanation:

You mean 64x^2 - 4? If so, we can take out a factor of 4 to get 4(16x^2 - 1)

Mathematics
Step-by-step answer
P Answered by PhD

28

Step-by-step explanation:

You must multiply first using BODMAS oe BIDMAS, then add on.

18x2= 36

36-8= 28

Mathematics
Step-by-step answer
P Answered by PhD

x(7 - x)

Step-by-step explanation:

Given

7x - x² ← factor out x from both terms

= x(7 - x) ← in factored form

Mathematics
Step-by-step answer
P Answered by PhD

Following are the calculation to the given points:

For point 1:

\bold{8x^2+26x+15}\\\\\bold{8x^2+(20+6)x+15}\\\\\bold{8x^2+20x+6x+15}\\\\\bold{4x(2x+5)+3(2x+5)}\\\\\bold{(2x+5)(4x+3)}\\\\

Therefore, the answer is "Option D".

For point 2:

\bold{x^2 + 5x - 24}\\\\\bold{x^2 + (8-3)x - 24}\\\\\bold{x^2 + 8x-3x - 24}\\\\\bold{x(x + 8)-3(x +8)}\\\\\bold{(x + 8) (x-3)}\\\\

Therefore, the answer is "Option A".

For point 3:

\bold{8x2 - 50}\\\\\bold{2(4x2 - 25)}\\\\\bold{2((2x)^2 - 5^2)}\\\\\therefore \ \ x^2-y^2=(x+y) (x-y)\\\\\bold{2((2x - 5)(2x+5)}\\\\

Therefore, the answer is "Option D".

For point 4:

\bold{3x^2 + 7x + 2}\\\\\bold{3x^2 +(6+1)x + 2}\\\\\bold{3x^2 +6x+1x + 2}\\\\\bold{3x(x +2)+1(x + 2)}\\\\\bold{(x +2) (3x+1)}\\\\

Therefore, the answer is "Option D".

For point 5:

\bold{x^2 - 5x = 14}\\\\\bold{x^2 - 5x -14= 0}\\\\\bold{x^2 - (7-2)x -14= 0}\\\\\bold{x^2 -7x+2x -14= 0}\\\\\bold{x(x -7)+2(x -7)= 0}\\\\\bold{(x -7) (x+2)= 0}\\\\\bold{x -7=0\ \ \ \ \ \ \ \ \ \ \ \  \ \ \ \ \ \ \ x+2= 0}\\\\\bold{x =7\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x= -2}\\\\

Therefore, the answer is "Option D".

For point 6:

\bold{x^2 + 5x - 50}\\\\\bold{x^2 + (10-5)x - 50}\\\\\bold{x^2 + 10x-5x - 50}\\\\\bold{x(x+ 10)-5(x +10)}\\\\\bold{(x+ 10)(x -5)}\\\\

Therefore, the answer is "Option B".

For point 7:

\bold{16x^2 + 24x + 9}\\\\\bold{16x^2 + (12+12)x + 9}\\\\\bold{16x^2 + 12x+12x + 9}\\\\\bold{4x(4x +3)+3(4x + 3)}\\\\\bold{(4x +3)(4x + 3)}\\\\\bold{(4x +3)^2}\\\\

Therefore, the answer is "Option A".

For point 8:

\bold{32x^2 - 50}\\\\\bold{2(16x^2 - 25)}\\\\\bold{2((4x)^2 - (5)^2)}\\\\\bold{2((4x-5)(4x+5))}\\\\

Therefore, the answer is "Option B".

For point 9:

\bold{x^2 + 7x - 18}\\\\\bold{x^2 + (9-2)x - 18}\\\\\bold{x^2 + 9x-2x - 18}\\\\\bold{x(x+ 9)-2(x +9)}\\\\\bold{(x+ 9)(x-2)}\\\\

Therefore, the answer is "Option C".

For point 10:

\bold{x^2 + 5x - 14}\\\\\bold{x^2 + (7-2)x - 14}\\\\\bold{x^2 + 7x-2x - 14}\\\\\bold{x(x+7)-2(x +7)}\\\\\bold{(x+7)(x -2)}\\\\

Therefore, the answer is "Option C".

For point 11:

\bold{25x^2 - 64}\\\\\bold{(5x)^2 - (8)^2}\\\\\bold{(5x-8)(5x+8)}\\\\

Therefore, the answer is "Option C".

For point 12:

\bold{x^2 - 81}\\\\\bold{x^2 - 9^2}\\\\\bold{(x - 9)(x+9)}\\\\

Therefore, the answer is "Option A".

For point 13:

\bold{8x^2 + 16x + 8 = 0}\\\\\bold{8(x^2 + 2x + 1) = 0}\\\\\bold{(x^2 + 2x + 1) = 0}\\\\\bold{(x^2 + x+x + 1) = 0}\\\\\bold{(x(x +1)1(x + 1)) = 0}\\\\\bold{(x +1)(x + 1) = 0}\\\\\bold{(x +1)^2 = 0}\\\\\bold{x +1 = 0}\\\\\bold{x=-1}\\\\

Therefore, the answer is "Option B".

For point 14:

\bold{x^2 -x -12 = 0}\\\\\bold{x^2 -(4-3)x -12 = 0}\\\\\bold{x^2 -4x+3x -12 = 0}\\\\\bold{x(x -4)+3(x -4) = 0}\\\\\bold{(x -4) (x+3) = 0}\\\\\bold{(x -4)=0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (x+3) = 0}\\\\\bold{x =4\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = -3}\\\\

Therefore, the answer is "Option C".

For point 15:

\bold{6x^2 + 8x - 28 = 2x^2 + 4}\\\\\bold{6x^2 + 8x - 28 - 2x^2 - 4=0}\\\\\bold{4x^2 + 8x - 32=0}\\\\\bold{4(x^2 + 2x - 8)=0}\\\\\bold{(x^2 + 2x - 8)=0}\\\\\bold{(x^2 + (4-2)x - 8)=0}\\\\\bold{(x^2 + 4x-2x - 8)=0}\\\\\bold{(x(x + 4)-2(x +4))=0}\\\\\bold{(x + 4)(x -2)=0}\\\\\bold{(x + 4)=0\ \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (x -2)=0}\\\\\bold{x =-4\ \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x =2}\\\\

Therefore, the answer is "Option B".

For point 14:

\bold{6z^2 + 18z}\\\\\bold{6z(z + 3)}\\\\

Therefore, the answer is "Option B".

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1) Which is a binomial factor of 8x2 + 26x + 15? A) x − 5  B) 2x − 5  C) 2x + 3  D) 4x + 3  2) Facto
1) Which is a binomial factor of 8x2 + 26x + 15? A) x − 5  B) 2x − 5  C) 2x + 3  D) 4x + 3  2) Facto

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