(1).copy and complete the following table of value for the relation y= 2x^2-7x-3. x value are (-2,-1,0,1,2,3,4,5). y value are ( (2).using 2cm to 1 unit on the x-axis and 2cm to 5units on the y-axis, draw the graph of y=2x^2-7x-3 for -2< /x< \5. (3). from your graph, find the minimum value of y, gradient of curve at x=1. (4). by drawing a suitable straight line, find the values of x for which 2x^2-7x-5=x+1.