Mathematics: i need help because its hardn bjh

i need help because its hardn bjh, №8758481, 28.09.2022 23:26

Biology

Read the descriptions of two experiments below. experiment 1: a student did a test to see if the hardness of the soil affects the growth of sunflowers. she used a control group and experimental groups. she repeated her experiment several times and found each time that the hardness of the soil did not affect the growth. experiment 2: a student did a test to see if the temperature of water affects the growth of cacti. she used a control group and experimental groups. her data supported her hypothesis. which experiment is more likely to be reliable,

Step-by-step answer

P Answered by Master

12

B. Experiment 1, because it gave the same results every time

Biology

Read the descriptions of two experiments below. experiment 1: a student did a test to see if the hardness of the soil affects the growth of sunflowers. she used a control group and experimental groups. she repeated her experiment several times and found each time that the hardness of the soil did not affect the growth. experiment 2: a student did a test to see if the temperature of water affects the growth of cacti. she used a control group and experimental groups. her data supported her hypothesis. which experiment is more likely to be reliable,

Step-by-step answer

P Answered by Specialist

26

B. Experiment 1, because it gave the same results every time

Biology

Read the descriptions of two experiments below. experiment 1: a student did a test to see if the hardness of the soil affects the growth of sunflowers. she used a control group and experimental groups. she repeated her experiment several times and found each time that the hardness of the soil did not affect the growth. experiment 2: a student did a test to see if the temperature of water affects the growth of cacti. she used a control group and experimental groups. her data supported her hypothesis. which experiment is more likely to be reliable,

Step-by-step answer

P Answered by Specialist

12

B. Experiment 1, because it gave the same results every time

Mathematics

The manufacturer of hardness testing equipment uses steel-ball indenters to penetrate metal that is being tested, however, the manufacturer thinks it would be better to use a diamond indenter so that all ypes of metal can be tested. because of differences between the two types of indenters, it is suspected that the two methods will produce different hardness readings. the metal speciments to be tested are large enough so that two indentions can be made. therefore, the manufacturer uses both indenters on each specimen and compares the hardness readings.

Step-by-step answer

P Answered by Master

$1.667-2.31\frac{1.803}{\sqrt{9}}=0.2789$

$1.667+2.31\frac{1.803}{\sqrt{9}}=3.055$

So on this case the 95% confidence interval would be given by (0.2789;3.055)

The 95% confidence interval to judge whether the two indeners result in different measurements is?

Yes the confidence interval not contains the value 0 so we can conclude that the values for Diamond are significantly higher than the values for Steel Ball at 5% of significance.

Step-by-step explanation:

We have the following dataset:

specimen 1 2 3 4 5 6 7 8 9

Steel Ball 51 57 61 70 68 54 65 51 53

Diamond 53 55 63 74 69 56 68 51 56

If we calculate the differences diamond-steel ball we have this datase:

d: 2, -2, 2, 4, 1, 2, 3, 0, 3

The second step is calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}=1.667$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =1.803$

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

df=n-1=9-1=8

Since the confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,9)".And we see that $t_{\alpha/2}=2.31$ .

Now we have everything in order to replace into formula (1):

$1.667-2.31\frac{1.803}{\sqrt{9}}=0.2789$

$1.667+2.31\frac{1.803}{\sqrt{9}}=3.055$

So on this case the 95% confidence interval would be given by (0.2789;3.055)

The 95% confidence interval to judge whether the two indeners result in different measurements is?

Yes the confidence interval not contains the value 0 so we can conclude that the values for Diamond are significantly higher than the values for Steel Ball at 5% of significance.

Mathematics

The manufacturer of hardness testing equipment uses steel-ball indenters to penetrate metal that is being tested. However, the manufacturer thinks it would be better to use a diamond indenter so that all types of metal can be tested. Because of differences between the two types of indenters, it is suspected that the two methods will produce different hardness readings. The metal specimens to be tested are large enough so that two indentions can be made. Therefore, the manufacturer uses both indenters on each specimen and compares the hardness readings.

Step-by-step answer

P Answered by Master

Check the explanation

Step-by-step explanation:

Let X denotes steel ball and Y denotes diamond

$\bar{x_1}$ = 1/9( 50+57+......+51+53)