16.11.2020

1. Use estimation to choose the correct value for each expression.

. 5

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Mathematics
Step-by-step answer
P Answered by Specialist

Reject the null hypothesis. There is sufficient evidence to prove that the mean life is different from 7463 hours.

95% confidence interval also supports this result.

Step-by-step explanation:

Let mu be the population mean life of a large shipment of CFLs.

The hypotheses are:

H_{0}: mu=7463 hours

H_{a}: mu≠7463 hours

Test statistic can be calculated using the equation:

z=\frac{X-M}{\frac{s}{\sqrt{N} } } where

X is the sample mean life of CFLs (7163 hours) M is the mean life assumed under null hypothesis. (7463 hours) s is the population standard deviation (1080 hours)N is the sample size (81)

Then z=\frac{7163-7463}{\frac{1080}{\sqrt{81} } } = -2.5

p-value is  0.0124, critical values at 0.05 significance are ±1.96

At the 0.05 level of significance, the the result is significant because 0.0124<0.05. There is significant evidence that mean life of light bulbs is different than 7463 hours.

95% Confidence Interval can be calculated using M±ME where

M is the sample mean  life of a large shipment of CFLs (7163 hours)ME is the margin of error from the mean

margin of error (ME) from the mean can be calculated using the formula

ME=\frac{z*s}{\sqrt{N} } where

z is the corresponding statistic in the 95% confidence level (1.96)s is the standard deviation of the sample (1080 hours)N is the sample size (81)

Then ME=\frac{1.96*1080}{\sqrt{81} } =235.2

Thus 95% confidence interval estimate of the population mean life of the light bulbs is 7163±235.2 hours. That is between 6927.8 and 7398.2 hours.

Mathematics
Step-by-step answer
P Answered by Specialist

Reject the null hypothesis. There is sufficient evidence to prove that the mean life is different from 7463 hours.

95% confidence interval also supports this result.

Step-by-step explanation:

Let mu be the population mean life of a large shipment of CFLs.

The hypotheses are:

H_{0}: mu=7463 hours

H_{a}: mu≠7463 hours

Test statistic can be calculated using the equation:

z=\frac{X-M}{\frac{s}{\sqrt{N} } } where

X is the sample mean life of CFLs (7163 hours) M is the mean life assumed under null hypothesis. (7463 hours) s is the population standard deviation (1080 hours)N is the sample size (81)

Then z=\frac{7163-7463}{\frac{1080}{\sqrt{81} } } = -2.5

p-value is  0.0124, critical values at 0.05 significance are ±1.96

At the 0.05 level of significance, the the result is significant because 0.0124<0.05. There is significant evidence that mean life of light bulbs is different than 7463 hours.

95% Confidence Interval can be calculated using M±ME where

M is the sample mean  life of a large shipment of CFLs (7163 hours)ME is the margin of error from the mean

margin of error (ME) from the mean can be calculated using the formula

ME=\frac{z*s}{\sqrt{N} } where

z is the corresponding statistic in the 95% confidence level (1.96)s is the standard deviation of the sample (1080 hours)N is the sample size (81)

Then ME=\frac{1.96*1080}{\sqrt{81} } =235.2

Thus 95% confidence interval estimate of the population mean life of the light bulbs is 7163±235.2 hours. That is between 6927.8 and 7398.2 hours.

Mathematics
Step-by-step answer
P Answered by Specialist

Let the length of the side of the square being cut out equal x

The length of the box would be 4.5 - 2x

The width of the box would be 3 -2x

Volume = (4.5 -2x) * (3-2x) * x

Simplify to:

V = 4x^3 - 15x^2 + 13.5x

B See picture: The greatest volume would be the point of the highest curve.

x = 0.589 y = 3.565, Rounded to the nearest tenth x = 0.6

Process: entered the equation from A into Desmos. The Y value would be the volume, so found where the volume was the highest and then found the related x value.

C) X is the side length of the corner squares being cut out, which would also be the height of the box. The Y value is the volume of the box.


50 POINTS HELP PLEASE MATH BE RIGHT

A box without a top is to be made to hold copious bags of cand
Mathematics
Step-by-step answer
P Answered by Specialist

Let the length of the side of the square being cut out equal x

The length of the box would be 4.5 - 2x

The width of the box would be 3 -2x

Volume = (4.5 -2x) * (3-2x) * x

Simplify to:

V = 4x^3 - 15x^2 + 13.5x

B See picture: The greatest volume would be the point of the highest curve.

x = 0.589 y = 3.565, Rounded to the nearest tenth x = 0.6

Process: entered the equation from A into Desmos. The Y value would be the volume, so found where the volume was the highest and then found the related x value.

C) X is the side length of the corner squares being cut out, which would also be the height of the box. The Y value is the volume of the box.


50 POINTS HELP PLEASE MATH BE RIGHT

A box without a top is to be made to hold copious bags of cand
Mathematics
Step-by-step answer
P Answered by Master

Step-by-step explanation:

Give that hypothesis testing is done using independent samples.

A) The confidence interval estimate of µ 1-µ 2 is ( x 1 - x 2 ) - E < ( µ 1 - µ 2 ) < ( x 1 - x 2 ) + E.

This is true.  because margin of error is subtracted and added to get lower/upper bounds.

B) When making an inference about the two means, the P-value and traditional methods of hypothesis testing result in the same conclusion as the confidence interval method. True

C) False  because Var(X-Y) = Var(x)+Var(Y) when independent

D) True.  

Mathematics
Step-by-step answer
P Answered by Specialist

Step-by-step explanation:

Give that hypothesis testing is done using independent samples.

A) The confidence interval estimate of µ 1-µ 2 is ( x 1 - x 2 ) - E < ( µ 1 - µ 2 ) < ( x 1 - x 2 ) + E.

This is true.  because margin of error is subtracted and added to get lower/upper bounds.

B) When making an inference about the two means, the P-value and traditional methods of hypothesis testing result in the same conclusion as the confidence interval method. True

C) False  because Var(X-Y) = Var(x)+Var(Y) when independent

D) True.  

Mathematics
Step-by-step answer
P Answered by Master

Step-by-step explanation:

Hello!

The variable of interest is

X: Number of people that feel vulnerable to identity theft in a sample of 929.

This variable is discrete and has a binomial distribution. X~Bi(n;p)

The parameter of interest is the population proportion of people that feel vulnerable to identity theft.

To calculate the 99% CI for the population proportion you have to use the approximate distribution to normal for the sample proportion p'≈N(p; \frac{p(1-p)}{n})

a. The best point estimate for p is the sample proportion p' you calculate it as:

p'= x/n= 523/929= 0.56

b. The formula for the confidence interval is

p' ± Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }

Where Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} } is the margin of error

In this case Z_{1-\alpha /2}= Z_{0.995}= 2.586

Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }= 2.586*\sqrt{\frac{0.56*0.44}{929} }= 0.04

c. Then the interval is

0.56 ± 0.04

[0.52;0.6]

d.

With a 99% confidence level, you can expect that the interval [0.52;0.6] will include the true value of the proportion of people that feel vulnerable to identity theft.

The correct answer is

3. there is a 99% chance that the true value of the population proportion will fall between the lower bound and the upper bound.

I hope this helps!

Mathematics
Step-by-step answer
P Answered by Master

Step-by-step explanation:

Hello!

The variable of interest is

X: Number of people that feel vulnerable to identity theft in a sample of 929.

This variable is discrete and has a binomial distribution. X~Bi(n;p)

The parameter of interest is the population proportion of people that feel vulnerable to identity theft.

To calculate the 99% CI for the population proportion you have to use the approximate distribution to normal for the sample proportion p'≈N(p; \frac{p(1-p)}{n})

a. The best point estimate for p is the sample proportion p' you calculate it as:

p'= x/n= 523/929= 0.56

b. The formula for the confidence interval is

p' ± Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }

Where Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} } is the margin of error

In this case Z_{1-\alpha /2}= Z_{0.995}= 2.586

Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }= 2.586*\sqrt{\frac{0.56*0.44}{929} }= 0.04

c. Then the interval is

0.56 ± 0.04

[0.52;0.6]

d.

With a 99% confidence level, you can expect that the interval [0.52;0.6] will include the true value of the proportion of people that feel vulnerable to identity theft.

The correct answer is

3. there is a 99% chance that the true value of the population proportion will fall between the lower bound and the upper bound.

I hope this helps!

Business
Step-by-step answer
P Answered by Master

Option 3 & 4

Explanation:

A firm's market value can be computed by multiplying it's earnings per share with P/E Ratio of a similar firm.

Earnings per share = \frac{Earnings\ attributable\ to\ stockholders}{No.\ of\ shares\ outstanding}

Price Earnings Ratio = \frac{Market\ Price\ per\ share}{Earnings\ per\ share}

The product of the above two would be the market price per share of the firm.

Similarly, Market/Book ratio = Total Market Capitalization/Book Value

Also, known as price to book ratio, the product of Market/Book ratio of a similar company and Book value of a company yields Market value of the company.

Mathematics
Step-by-step answer
P Answered by Specialist

I am slightly confused ,but -1/4 x^2 +3x+10 I think. Letter wise F. ?

Step-by-step explanation:

x = 0 ; y = 10 ; 10 = a(0) + b(0) + c

c = 10

x=2 ; y = 15 ; 15 = a(4) + b(2) + 10 ; 5 = 4a+2b

x=4 ; y=18 ; 18 = a(16) + b(4) + 10 ; 8 = 16a + 4b 

2(5) = (4a+2b)2-

8 = 16a + 4b

   2 = -8a

a = -0.25

b = 2

y = (1/4)x^2 + 2x + 10 ; 4y = x^2 + 8x + 40

Hope this helped!

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