04.02.2021

In which quadrant is the point (-3,5) located?

. 5

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Mathematics
Step-by-step answer
P Answered by Specialist
That would be quadrant III.

hope this helped
Mathematics
Step-by-step answer
P Answered by Specialist

quadrant 1 - (2,4)

quadrant 2 - (-3,4)

quadrant 3 - (-1, -5)

quadrant 4 - (6, -1)

Step-by-step explanation:

quadrant one consists of both x and y being positive.

quadrant two being the x is negative but the y is negative.

quadrant 3 has its x and y both negative.

finally, quadrant 4 has its x positive, but y is negative.

Mathematics
Step-by-step answer
P Answered by Specialist

(-3,4) is the right answer i think im not sure nvm im positive that this is the right answeri think

Mathematics
Step-by-step answer
P Answered by PhD

The correct answer is:


A) reflection across the y-axis followed by translation 10 units down


Explanation:


Reflecting across the y-axis negates the x-coordinate of each point. This maps our points as follows:


(-5, 3)→(5, 3)

(-3, 5)→(3, 5)

(-4, 8)→(4, 8)

(-6, 6)→(6, 6)


A translation 10 units down will subtract 7 from each y-coordinate. This maps our new points as follows:


(5, 3)→(5, 3-10) = (5, -7)

(3, 5)→(3, 5-10) = (3, -5)

(4, 8)→(4, 8-10) = (4, -2)

(6, 6)→(6, 6-10) = (6, -4)


This is the correct set of image points, so this is the correct set of transformations.

Mathematics
Step-by-step answer
P Answered by PhD

The correct answer is:


A) reflection across the y-axis followed by translation 10 units down


Explanation:


Reflecting across the y-axis negates the x-coordinate of each point. This maps our points as follows:


(-5, 3)→(5, 3)

(-3, 5)→(3, 5)

(-4, 8)→(4, 8)

(-6, 6)→(6, 6)


A translation 10 units down will subtract 7 from each y-coordinate. This maps our new points as follows:


(5, 3)→(5, 3-10) = (5, -7)

(3, 5)→(3, 5-10) = (3, -5)

(4, 8)→(4, 8-10) = (4, -2)

(6, 6)→(6, 6-10) = (6, -4)


This is the correct set of image points, so this is the correct set of transformations.

Mathematics
Step-by-step answer
P Answered by Specialist
Hi

Quadrant I ⇒ x>0 and y>0
Quadrant II ⇒ x<0 and y>0
Quadrant III ⇒ x<0 and y<0
Quadrant IV ⇒ x>0 and y<0

x = -3 ⇒ x<0
y = 5 ⇒ y>0

 Quadrant II

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