Mathematics: which line is parellel to the line given below y=-5/2x-7

which line is parellel to the line given below, №9133541, 04.04.2020 09:02

Mathematics

Algebra 1a unit 6 lesson 6 1. write an equation in slope-intercept form of the line rhat passes through the given point and is parallele to the graph of the equation (2,-2); y=-x-2 2. (2,-1); y=-3/2x+6 3. (4,2); x=-3 4. (-2,3); y=1/2x-1 5. (5,0); y+1=2(x-3) 6. determine whether the graphs of the given equations are parellel, perpendicular, or neither y=x+11 y=-x+2 7. y=-2x+3 y=2x+y=7 8. y=4x-2 -x+4y=0 9. determine whether the statement is always, sometimes or never true two lines with positive slopes are parellel 10. two lines with the same slope

Step-by-step answer

P Answered by PhD

21

1. y = -x - 2...slope here is -1. A parallel line will have the same slope

y = mx + b
slope(m) = -1
(2,-2)...x = 2 and y = -2
now we sub and find b, the y int
-2 = -1(2) + b
-2 = -2 + b
-2 + 2 = b
0 = b

so ur parallel equation is : y = -x

2. -1 = -3/2(2) + b
-1 = -3 + b
-1 + 3 = b
2 = b
parallel equation is : y = -3/2x + 2

3. parallel equation is : x = 4

4. 3 = 1/2(-2) + b
3 = -1 + b
3 + 1 = b
4 = b
parallel equation is : y = 1/2x + 4

5. y + 0 = 2(x - 5)
y = 2x - 10 <== parallel line

6. neither

7. if ur second equation is : 2x + y = 7, then the lines are parallel

8. neither

9. sometimes

10. never

Mathematics

Algebra 1a unit 6 lesson 6 1. write an equation in slope-intercept form of the line rhat passes through the given point and is parallele to the graph of the equation (2,-2); y=-x-2 2. (2,-1); y=-3/2x+6 3. (4,2); x=-3 4. (-2,3); y=1/2x-1 5. (5,0); y+1=2(x-3) 6. determine whether the graphs of the given equations are parellel, perpendicular, or neither y=x+11 y=-x+2 7. y=-2x+3 y=2x+y=7 8. y=4x-2 -x+4y=0 9. determine whether the statement is always, sometimes or never true two lines with positive slopes are parellel 10. two lines with the same slope

Step-by-step answer

P Answered by PhD

21

1. y = -x - 2...slope here is -1. A parallel line will have the same slope

y = mx + b
slope(m) = -1
(2,-2)...x = 2 and y = -2
now we sub and find b, the y int
-2 = -1(2) + b
-2 = -2 + b
-2 + 2 = b
0 = b

so ur parallel equation is : y = -x

2. -1 = -3/2(2) + b
-1 = -3 + b
-1 + 3 = b
2 = b
parallel equation is : y = -3/2x + 2

3. parallel equation is : x = 4

4. 3 = 1/2(-2) + b
3 = -1 + b
3 + 1 = b
4 = b
parallel equation is : y = 1/2x + 4

5. y + 0 = 2(x - 5)
y = 2x - 10 <== parallel line

6. neither

7. if ur second equation is : 2x + y = 7, then the lines are parallel

8. neither

9. sometimes

10. never

Mathematics

Write the equation of a parellel to the given line that goes through the given point y=8x+3 (2,4)

Step-by-step answer

P Answered by PhD

1

The equation of a parallel to the given line that goes through the given point (2, 4) is:

y=8x-12

Step-by-step explanation:

Given the equation

y=8x+3

comparing the equation with the slope-intercept form

y=mx+b

Here,

m is the slope y is the intercept

so the slope of the line is m = 8.

We know that the slopes of parallel lines are equal.

so, the slope of the perpendicular line will be = 8

Therefore, the equation of a parallel to the given line that goes through the given point (2, 4) is:

$y-y_1=m\left(x-x_1\right)$

y-4 = 8 (x-2)

y-4 = 8x-16

y = 8x-16+4

y=8x-12

Mathematics

Write the equation of a parellel to the given line that goes through the given point y=8x+3 (2,4)

Step-by-step answer

P Answered by PhD

1

The equation of a parallel to the given line that goes through the given point (2, 4) is:

y=8x-12

Step-by-step explanation:

Given the equation

y=8x+3

comparing the equation with the slope-intercept form

y=mx+b

Here,

m is the slope y is the intercept

so the slope of the line is m = 8.

We know that the slopes of parallel lines are equal.

so, the slope of the perpendicular line will be = 8

Therefore, the equation of a parallel to the given line that goes through the given point (2, 4) is:

$y-y_1=m\left(x-x_1\right)$

y-4 = 8 (x-2)

y-4 = 8x-16

y = 8x-16+4

y=8x-12

Mathematics

Given C(x, 16), D(2,-4), E(-6 4), and F(-2, 4) find the value of x so that line CD is parellel to lin EF. please show work

Step-by-step answer

P Answered by PhD

1

The value of x = -6

Step-by-step explanation:

We know that if the line CD is parallel to line EF, then their slopes will be the same.

In other words:

slope = slope

As we know that the slope between two points will be:

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

Let's find the slope of CD

as

C(x, 16) D(2,-4)

$m\:\left(CD\right)=\frac{-4-16}{2-x}$

$=-\frac{20}{2-x}$

Now, let's find the slope of EF

as

E(-6, 14)F(-2, 4)

$m\left(EF\right)=\frac{4-14}{-2-\left(-6\right)}$

$=-\frac{10}{4}$

As we already pointed out that

$m\left(CD\right)=\:m\left(EF\right)$

$-\frac{20}{2-x}$ $=-\frac{10}{4}$

$-20\cdot \:4=-\left(2-x\right)\cdot \:10$

$\frac{-\left(2-x\right)\cdot \:10}{-10}=\frac{-80}{-10}$

2-x=8

x=-6

Therefore, the value of x = -6

Mathematics

Given m parellel to n find the value of x

Step-by-step answer

P Answered by Master

1

x = 13

Step-by-step explanation:

x + 167 = 180

- 167 - 167

x = 13

Mathematics

Given C(x, 16), D(2,-4), E(-6 4), and F(-2, 4) find the value of x so that line CD is parellel to lin EF. please show work

Step-by-step answer

P Answered by PhD

1

The value of x = -6

Step-by-step explanation:

We know that if the line CD is parallel to line EF, then their slopes will be the same.

In other words:

slope = slope

As we know that the slope between two points will be:

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

Let's find the slope of CD

as

C(x, 16) D(2,-4)

$m\:\left(CD\right)=\frac{-4-16}{2-x}$

$=-\frac{20}{2-x}$

Now, let's find the slope of EF

as

E(-6, 14)F(-2, 4)

$m\left(EF\right)=\frac{4-14}{-2-\left(-6\right)}$

$=-\frac{10}{4}$

As we already pointed out that

$m\left(CD\right)=\:m\left(EF\right)$

$-\frac{20}{2-x}$ $=-\frac{10}{4}$

$-20\cdot \:4=-\left(2-x\right)\cdot \:10$

$\frac{-\left(2-x\right)\cdot \:10}{-10}=\frac{-80}{-10}$

2-x=8

x=-6

Therefore, the value of x = -6

Mathematics

Given m parellel to n find the value of x

Step-by-step answer

P Answered by Master

1

x = 13

Step-by-step explanation:

x + 167 = 180

- 167 - 167

x = 13

Mathematics

Proving the Parallelogram Side Theorem Given: ABCD is a parellelogram. Prove: AB=CD and BC=DA

Step-by-step answer

P Answered by PhD

35

Statements Reasons

1. ABCD is a parallelogram 1. Given

2. Seg. AB is parallel to seg. CD 2. Def of parallelogram

3. Seg. AD is parallel to seg. BC 3. Def of parallelogram

4. Draw seg. BD 4. Between 2 pts there is 1 line

5. <ABD is congr <CDB 5. Alt. Int. < Theorem

6. <BDA is cong <DBC 6. Alt. Int. < Theorem

7. Seg. BD is congr seg. BD 7. Congr. of seg's is reflexive

8. Triangle BAD is congr tr. DCB 8. SAS Postulate

9. AB is congr CD 9. CPCTC

10. BC is congr DA 10. CPCTC

11. AB = CD; BC = DA 11. Def of congr. seg's

Mathematics

Given: ABCD is a parellelogram. Prove: AB=CD and BC=DA

Step-by-step answer

P Answered by Specialist

14

Parallelogram opposites side theorem which states that If a quadrilateral is a parallelogram , then it’s opposite sides are congruent

which line is parellel to the line given below y=-5/2x-7

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