Mathematics: If f(x) = | x - 2 | then find f (-3)

If f(x) = | x - 2 | then find f (-3), №9534620, 27.03.2021 20:25

Mathematics

1: x - (-3) is the same as x + (-3). true false 2: a negative times a negative equals a positive. true false 3: evaluate -6^2 - 28 ÷ 4 + (-9). 52 -52 20 -20 4: solve -2x + 6 = -20. -13 13 -7 7 5: solve x - (-9) = -14. -23 23 -5 5: three times a number increased by eleven is seventeen translates to which of the following equations? 11x + 3 = 17 11x - 3 = 17 3x + 11 = 17 3x - 11 = 17 6: if f(x) = 2x - 9, then f(3) = -3. true false 7: domain, first element, and y-value all have the same meaning. true false 8: all functions are relations. true false

Step-by-step answer

P Answered by PhD

1

1. x-(-3) is not the same as x+(-3) , because the first statement is equal to x+3 and the second statement is equal to x-3 .

The first question is false.

2. The second statement is true, because when we multiply equal signs the result is always positive. In this case, both signs have the same nature, negative and negative, so the result is positive.

3. The expression is $-6^{2}-28 \div 4 + (-9)$

First, we solve powers and divisons: -36-7-9 (notice that the negative sign is outside the square power.

Then, we sum: -36-7-9=-52

Therefore, the right answer is -52.

4. The equation is -2x+6=-20

Solving for

$-2x=-20-6\\x=\frac{-26}{-2}\\ x=13$

So, the answer is 13.

5. The expression is x-(-9)=-14

So,

$x-(-9)=-14\\x+9=-14\\x=-14-9\\x=-23$

6. The function is f(x)=2x-9 , if x=3 , then f(3)=2(3)-9=6-9=-3 .

Therefore, the statement is true.

7. False, beacuse the domain refers to the input values and y-values refers to output values. So, they don't means the same thing.

8. This statement is true, because to function be a function, first it has to be a relation, because a function must relate two sets to be one.

Mathematics

1: x - (-3) is the same as x + (-3). true false 2: a negative times a negative equals a positive. true false 3: evaluate -6^2 - 28 ÷ 4 + (-9). 52 -52 20 -20 4: solve -2x + 6 = -20. -13 13 -7 7 5: solve x - (-9) = -14. -23 23 -5 5: three times a number increased by eleven is seventeen translates to which of the following equations? 11x + 3 = 17 11x - 3 = 17 3x + 11 = 17 3x - 11 = 17 6: if f(x) = 2x - 9, then f(3) = -3. true false 7: domain, first element, and y-value all have the same meaning. true false 8: all functions are relations. true false

Step-by-step answer

P Answered by PhD

1

1. x-(-3) is not the same as x+(-3) , because the first statement is equal to x+3 and the second statement is equal to x-3 .

The first question is false.

2. The second statement is true, because when we multiply equal signs the result is always positive. In this case, both signs have the same nature, negative and negative, so the result is positive.

3. The expression is $-6^{2}-28 \div 4 + (-9)$

First, we solve powers and divisons: -36-7-9 (notice that the negative sign is outside the square power.

Then, we sum: -36-7-9=-52

Therefore, the right answer is -52.

4. The equation is -2x+6=-20

Solving for

$-2x=-20-6\\x=\frac{-26}{-2}\\ x=13$

So, the answer is 13.

5. The expression is x-(-9)=-14

So,

$x-(-9)=-14\\x+9=-14\\x=-14-9\\x=-23$

6. The function is f(x)=2x-9 , if x=3 , then f(3)=2(3)-9=6-9=-3 .

Therefore, the statement is true.

7. False, beacuse the domain refers to the input values and y-values refers to output values. So, they don't means the same thing.

8. This statement is true, because to function be a function, first it has to be a relation, because a function must relate two sets to be one.

Mathematics

Find all the zeros of the polynomial function f(x) = x + 2x² - 9x - 18 a) (-3) b) (-3. -2,3) c) (-2) d) (-3.2.3) e) none

Step-by-step answer

P Answered by PhD

x=-3,-2,3

Step-by-step explanation:

Given equation of polynomial is

$x^{3}+2x^2-9x-18=0$

taking x^3 and -9x together and remaining together we get

x^3-9x+2x^2-18=0

$x\left ( x^2-9\right )+2\left ( x^2-9\right )$

$x\left ( \left ( x+3\right )\left ( x-3\right )\right )+2\left ( \left ( x+3\right )\left ( x-3\right )\right )$

$taking \left ( x+3\right )\left ( x-3\right ) as common$

$\left ( x+2\right )\left ( x+3\right )\left ( x-3\right )=0$

therefore

x=-3,-2,3

Mathematics

Question 1 (multiple choice worth 1 points) let f(x) = x2 - 3x - 7. find f(-3). 11 8 -7 -10 question 2 (multiple choice worth 1 points) let f(x) = x2 - 16. find f-1(x). 4square root of x ±square root of x plus 16 x squared over 16 1 over quantity of x squared minus 16 question 3 (multiple choice worth 1 points) let f(x) = 2x - 6 solve f-1(x) when x = 2. -5 4 -2 7 question 4 (multiple choice worth 1 points) let f(x) = 2x + 2. solve f-1(x) when x = 4. 1 3 4 10

Step-by-step answer

P Answered by PhD

11

Let f(x) = x^2 - 3x - 7. Find f(-3).

-7

Let f(x) = x2 - 16. Find f-1(x).

1 over quantity of x squared minus 16

Let f(x) = 2x - 6 Solve f-1(x) when x = 2.

4

Let f(x) = 2x + 2. Solve f-1(x) when x = 4.

1

Mathematics

Find all the zeros of the polynomial function f(x) = x + 2x² - 9x - 18 a) (-3) b) (-3. -2,3) c) (-2) d) (-3.2.3) e) none

Step-by-step answer

P Answered by PhD

x=-3,-2,3

Step-by-step explanation:

Given equation of polynomial is

$x^{3}+2x^2-9x-18=0$

taking x^3 and -9x together and remaining together we get

x^3-9x+2x^2-18=0

$x\left ( x^2-9\right )+2\left ( x^2-9\right )$

$x\left ( \left ( x+3\right )\left ( x-3\right )\right )+2\left ( \left ( x+3\right )\left ( x-3\right )\right )$

$taking \left ( x+3\right )\left ( x-3\right ) as common$

$\left ( x+2\right )\left ( x+3\right )\left ( x-3\right )=0$

therefore

x=-3,-2,3

Mathematics

Question 1 (multiple choice worth 1 points) let f(x) = x2 - 3x - 7. find f(-3). 11 8 -7 -10 question 2 (multiple choice worth 1 points) let f(x) = x2 - 16. find f-1(x). 4square root of x ±square root of x plus 16 x squared over 16 1 over quantity of x squared minus 16 question 3 (multiple choice worth 1 points) let f(x) = 2x - 6 solve f-1(x) when x = 2. -5 4 -2 7 question 4 (multiple choice worth 1 points) let f(x) = 2x + 2. solve f-1(x) when x = 4. 1 3 4 10

Step-by-step answer

P Answered by PhD

11

Let f(x) = x^2 - 3x - 7. Find f(-3).

-7

Let f(x) = x2 - 16. Find f-1(x).

1 over quantity of x squared minus 16

Let f(x) = 2x - 6 Solve f-1(x) when x = 2.

4

Let f(x) = 2x + 2. Solve f-1(x) when x = 4.

1

Mathematics

F(x) = x^2 - 5x - 14 g(x) = x - 7 (f + g)(-3) = (f - g)(-3) = (g - f)(-2) =

Step-by-step answer

P Answered by Master

See attached image.

Step-by-step explanation:

Calculate the vales of each function (f and g) for the value of x as indicated. Then perform the arithmetic operation on the results. For example:

f(-3) = 10

g(-3) = -10

Then (f+g)(-3) is 10 - 10 = 0

(f-g)(-3) is 10 -(-10) = 20

and so on, as shown.

Mathematics

F(x) = x^2 - 5x - 14 g(x) = x - 7 (f + g)(-3) = (f - g)(-3) = (g - f)(-2) =

Step-by-step answer

P Answered by Specialist

See attached image.

Step-by-step explanation:

Calculate the vales of each function (f and g) for the value of x as indicated. Then perform the arithmetic operation on the results. For example:

f(-3) = 10

g(-3) = -10

Then (f+g)(-3) is 10 - 10 = 0

(f-g)(-3) is 10 -(-10) = 20

and so on, as shown.

Mathematics

Find the difference of functions at x= - 3, (g - f)(-3), given f(x) and g(x): g(x) = x^2−15, and f(x) =2x

Step-by-step answer

P Answered by Master

1

0

Step-by-step explanation:

Solution:-

We are given two functions as follows:

$f ( x ) = x^2 - 15\\\\g ( x ) = 2x$

We need to determine the composite function defined as ( g - f ) ( x ). To determine this function we need to make sure that both function exist for all real positive value of x.

The function f ( x ) is a quadratic function which has real values for all values of x. Similarly, function g ( x ) is a linear line that starts from the origin. Hence, both functions are defined over the domain ( -∞, ∞ )

We will perform arithmetic operation of subtracting function f ( x ) from g ( x ) as follows:

$[ g - f ] ( x ) = g ( x ) - f ( x )\\\\\\( g - f ) ( x ) = x^2 - 15 - 2x\\\\$

Now evaluate the above determined function at x = -3 as follows:

$( g - f ) ( -3 ) = ( -3 )^2 - 2 ( -3 ) - 15\\\\( g - f ) ( -3 ) = 9 + 6 - 15\\\\( g - f ) ( -3 ) = 0$

Mathematics

Find the difference of functions at x= - 3, (g - f)(-3), given f(x) and g(x): g(x) = x^2−15, and f(x) =2x

Step-by-step answer

P Answered by Master

1

0

Step-by-step explanation:

Solution:-

We are given two functions as follows:

$f ( x ) = x^2 - 15\\\\g ( x ) = 2x$

We need to determine the composite function defined as ( g - f ) ( x ). To determine this function we need to make sure that both function exist for all real positive value of x.

The function f ( x ) is a quadratic function which has real values for all values of x. Similarly, function g ( x ) is a linear line that starts from the origin. Hence, both functions are defined over the domain ( -∞, ∞ )

We will perform arithmetic operation of subtracting function f ( x ) from g ( x ) as follows:

$[ g - f ] ( x ) = g ( x ) - f ( x )\\\\\\( g - f ) ( x ) = x^2 - 15 - 2x\\\\$

Now evaluate the above determined function at x = -3 as follows:

$( g - f ) ( -3 ) = ( -3 )^2 - 2 ( -3 ) - 15\\\\( g - f ) ( -3 ) = 9 + 6 - 15\\\\( g - f ) ( -3 ) = 0$

If f(x) = | x - 2 | then find f (-3)

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