Mathematics: The graph shows the speed of Tony’s car as he drives to work

Mathematics : asked on musicismylove2340

05.05.2020

The graph shows the speed of Tony’s car as he drives to work

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Physics

When something is moving, it is in motion. pressing the gas pedal in a car will put the car in motion. two important properties of motion are speed and direction. speed is how fast an object is moving. if tony and tanya both run at the same speed and in the same direction, and they both run for the same amount of time, what can you say about the distance they travel? a) they will run an equal distance. b) tony will run a greater distance. c) tanya will run a greater distance. d) without knowing the exact speed, you can t say for sure.

Step-by-step answer

P Answered by PhD

If Tony and Tanya both run at the same speed and in the same direction,
and they both run for the same amount of time, there are a lot of things
you can say about them.

The thing you can say about the distance they travel is "They will both
run the same distance.". (A)

Physics

Step-by-step answer

P Answered by PhD

World Languages

Which word correctly completes this sentence? before i can start my speech, mary must her presentation. a. conclude b. persecute c. detect d. transport which word is an antonym of the word hospitality, as in when we visited my cousins, they showed us the sites, prepared great meals, and showed us great hospitality ? a. hostility b. generosity c. d. friendship which word correctly completes this sentence? x rays may small cavities a dentist cannot see. a. conclude b. persecute c. detect d. nomad which word correctly completes this sentence? margie

Step-by-step answer

P Answered by PhD

1.a

2.b

3.c

4.b

i dont know the rest

World Languages

Step-by-step answer

P Answered by PhD

1.a

2.b

3.c

4.b

i dont know the rest

Physics

2013 Indianapolis 500 champion Tony Kanaan holds his hand out of his IndyCar while driving through still air with standard atmospheric conditions. (a) For safety, the pit lane speed limit is 60 mph. At this speed, what is the maximum pressure on his hand? (b) Back on the race track, what is the maximum pressure when he is driving his IndyCar at 225 mph? (c) On the straightaways, the IndyCar reaches speeds in excess of 235 mph. For this speed, is your solution method for parts (a and (b) reasonable? Explain.

Step-by-step answer

P Answered by Master

(a). The pressure is 14.76 psi.

(b). The pressure is 15.59 psi.

(c). The pressure is 15.68 psi.

All answer are reasonable.

Explanation:

Given that,

Speed v₁= 60 mph

Speed v₂ = 225 mph

Speed v₃ = 235 mph

(a). We need to calculate the maximum pressure on his hand

Using equation of pressure

$P_{1}=P+\dfrac{1}{2}\rho v^2+\rho gh$

there, no vertical movement

So, on neglect of height term

$P_{1}=P+\dfrac{1}{2}\rho v_{1}^2$

Where, P= atmospheric pressure

$\rho$ = air density

v = speed

Put the value in the equation

$P_{1}=14.7\times144+\dfrac{1}{2}\times(0.002376\times(60\times1.4667)^2)$

$P_{1}=2126.0\ lb/ft^2$

$P_{1}=\dfrac{2126.0}{144}$

$P_{1}= 14.76\ psi$

(b). Speed v₂ = 225 mph

We need to calculate the maximum pressure on his hand

Using equation of pressure

$P_{2}=P+\dfrac{1}{2}\rho v_{2}^2$

Put the value in the equation

$P_{2}=14.7\times144+\dfrac{1}{2}\times(0.002376\times(225\times1.4667)^2)$

$P_{2}=2246.17\ lb/ft^2$

$P_{2}=\dfrac{2246.17}{144}$

$P_{2}= 15.59\ psi$

(c). Speed v₃ = 235 mph

We need to calculate the maximum pressure on his hand

Using equation of pressure

$P_{3}=P+\dfrac{1}{2}\rho v_{3}^2$

Put the value in the equation

$P_{3}=14.7\times144+\dfrac{1}{2}\times(0.002376\times(235\times1.4667)^2)$

$P_{3}=2257.93\ lb/ft^2$

$P_{3}=\dfrac{2257.93}{144}$

$P_{3}= 15.68\ psi$

According to bernoulli's equation,

If the car increases the velocity the the pressure on the surface of the driver's hand increases.

The pressure from P₁ to P₃ are all near the value of one atmosphere.

So, the pressure difference of one atmosphere is not enough to break the driver's hand.

Hence, (a). The pressure is 14.76 psi.

(b). The pressure is 15.59 psi.

(c). The pressure is 15.68 psi.

All answer are reasonable.

Physics

013 Indianapolis 500 champion Tony Kanaan holds his hand out of his IndyCar while driving through still air with standard atmospheric conditions. (a) For safety, the pit lane speed limit is 60 mph. At this speed, what is the maximum pressure on his hand? (b) Back on the race track, what is the maximum pressure when he is driving his IndyCar at 225 mph? (c) On the straightaways, the IndyCar reaches speeds in excess of 235 mph. For this speed, is your solution method for parts (a and (b) reasonable? Explain.

Step-by-step answer

P Answered by PhD

a) 14.76 psi

b) 15.59 psi

c) 15.68 psi

d) The solution method is reasonable

Explanation:

The formula for maximum pressure is given as using Bernoulli's Equation :

Pmax = p + 1/2ρV²

Where ρ = Density = 0.002376slug per cubic foot

p = Atmospheric pressure in pounds per cubic foot = 14.6959 pounds per square inch

Converting pounds per square inch to pounds per square foot

= 1 pounds per square inch = 144 pounds per square foot

14.6959 pounds per square inch =

14.6959 pounds per square inch × 144 pounds per square foot

= 2116.2096 pounds per square foot

V = Velocity of the flow = Speed limit.

(a) For safety, the pit lane speed limit is 60 mph. At this speed, what is the maximum pressure on his hand?

Our speed limit is 60 mph

We convert to ft/s

1 mph = 1.46667 ft/s

60 mph =

60 mph × 1.46667 ft/s = 88 ft/s

Pmax = p + 1/2ρV²

Pmax = 2116.2096 + (0.5 × 0.002376 × 88²)

Pmax = = 2125.409472 Ib/ft² =

Converting to psi.

= 2125.409472/144

= 14.759788 psi

≈ 14.76 psi

(b) Back on the race track, what is the maximum pressure when he is driving his IndyCar at 225 mph?

Our speed limit is 225 mph

We convert to ft/s

1 mph = 1.46667 ft/s

225 mph =

225 mph × 1.46667 ft/s = 330 ft/s

Pmax = p + 1/2ρV²

Pmax = 2116.2096 + (0.5 × 0.002376 × 330²)

Pmax = 2245.5828 Ib/ft² =

Converting to psi.

= 2245.5828/144

= 15.594325 psi

≈ 15.59 psi

Our speed limit is 235 mph

We convert to ft/s

1 mph = 1.46667 ft/s

235 mph =

235 mph × 1.46667 ft/s = 344.667 ft/s

Pmax = p + 1/2ρV²

Pmax = 2116.2096 + (0.5 × 0.002376 × 344.667²)

Pmax = = 2257.338465 Ib/ft² =

Converting to psi.

= 2257.3384654/144

= 15.675961562 psi

≈ 15.68 psi

d) For this speed, is your solution method for parts (a and (b) reasonable? Explain.

It is important to note that: the value of 1 atmosphere = 14.696 psi

If we look at the solution above, we can see that the maximum pressure of the speeds in question a, b, c which are: 14.76 psi, 15.59 psi, 15.68 psi respectfully are just a little bit outside the range of 1 atmosphere.

Hence, this is not significant enough to cause damage or harm the hands of Tony Kanaan therefore, my solution method for parts (a and (b) reasonable is reasonable.

Mathematics

Tony drives his car. he drives the first 13 miles in 13 minutes. he then drive at an average speed of 68 mph for 1 hour 24 minutes. use the information given on the table to find out how much petrol he uses. average speed miles traveled per gallon 65 mph or less 50 more than 65 mph 40

Step-by-step answer

P Answered by PhD

The total amounts of petrol used up by his car is 3.235 gallons.

Step-by-step explanation:

Tony drives his car and drives the first 13 miles in 13 minutes.

So, the average speed was $\frac{13}{13} \times 60 = 60$ mph.

which is less than 65 miles per hour, and the miles traveled per gallon is 50.

So, 50 miles of travel is done by 1 gallon of petrol.

Hence, 13 miles travel is done by $\frac{13}{50} = 0.26$ gallons of petrol.

Now, Tony then drives at an average speed of 68 mph > 65 mph for 1 hour and 24 minutes i.e. 1.75 hours.

Then he travels (68 × 1.75) = 119 miles and the miles traveled per gallon is 40.

So, 40 miles of travel is done by 1 gallon of petrol.

Hence, 119 miles travel is done by $\frac{119}{40} = 2.975$ gallons of petrol.

Therefore, the total amount of petrol used up by his car is (0.26 + 2.975) = 3.235 gallons. (Answer)

Mathematics

Tony drives his car he drives the first 13 miles in 13 minutes he then drives at an average speed of 68 mph for 1 hour 24 minutes use the information in the table to find out how much petrol he uses. average speed miles travelled per gallon 65 mph or less more than 65 mph 50 40 mph stands for miles per hour

Step-by-step answer

P Answered by PhD

2.64 gallons

Step-by-step explanation:

13 miles /13 minutes = 1 mile per minutes * 60 minutes/ hour = 60 miles per hour

The miles per gallon is 50 per the chart

13 miles ÷ 50 miles per gallon

Copy dot flip

13 * 1/50 gallons per mile = 13/50 gallons=.26 gallons

Now for the second leg we went 68 miles per hour

The miles per gallon is 40 per the chart

We need to find the distance

1 hour 24 minutes = 1 24/60 hours = 1.4 hours

1.4 hours * 68 mph = 95.2 miles

95.2 miles ÷ 40 miles per gallon

Copy dot flip

95.2 * 1/40 gallons per mile = 2.38 gallons

Add the number of gallons together

.26 + 2.38 = 2.64 gallons

Physics

Tony drives his car . He drives the first 13 miles in 13 minutes. He then drives at an average speed of 68mph for 1 hour 24 minutes .

Step-by-step answer

P Answered by PhD

Complete question :

Tony drives his car . He drives the first 13 miles in 13 minutes. He then drives at an average speed of 68mph for 1 hour 24 minutes . Find how much petrol he uses using the information in the table.

Requires table to answer question is attached below

2.64 gallons

Explanation:

Given that:

First 13 miles takes 13 minutes

Average rate = 13 miles / 13 minutes = 1mile/minute ; Average rate per hour = (1 mile /minute * 60) = 60 miles /hour

If average speed = 65mph or less ; 50 miles per gallon (it uses 1 gallon for 50 miles)

Hence, since first phase rate is 60 mph,; then miles per gallon is 50 miles

Therefore,gallon of petrol used for 13 miles will be :

13 miles / 50 mpg = 0.26 gallons

2nd phase:

Average rate of 68 mph for 1 hour 24 minutes (1.4 hours)

Here, miles per gallon = 40 (that is; 40 miles for 1 gallon).

Total distance covered = 68 * 1.4 = 95.2 miles

Petrol used = 95.2 miles / 40 mpg = 2.38 gallons

Hence,

Total petrol used : (0.26 + 2.38) = 2.64 gallons

Mathematics

Tony drives his car He drives the first 13 miles in 13 minutes,he then drives at an average speed of 68mph for 1 hour 24 minutes. How much petrol does he use

Step-by-step answer

P Answered by PhD

2.64 gallons

Step-by-step explanation:

Using the information in the table to find out how much petrol he uses. Average speed Miles travelled per gallon 65 mph or less More than 65 mph 50 40 mph stands for miles per hour

13 miles /13 minutes = 1 mile per minutes × 60 minutes/ hour = 60 miles per hour

The miles per gallon is 50 per the chart

13 miles ÷ 50 miles per gallon

13 × 1/50 gallons per mile = 13/50 gallons = 0.26 gallons

Now for the second leg we went 68 miles per hour

The miles per gallon is 40 per the chart

We need to find the distance

1 hour 24 minutes = 1 24/60 hours = 1.4 hours

1.4 hours × 68 mph = 95.2 miles

95.2 miles ÷ 40 miles per gallon

95.2 × 1/40 gallons per mile = 2.38 gallons

Add the number of gallons together