y = -3x + 60
Step-by-step explanation:
For the answer to the question above,
let x = number of weeks let y = amount of waste.
The linear equation may be expressed as,y = mx + b
m and b are the slope and y - intercept, respectively. Substituting the corresponding values,
(Week 5) 45 = 5m + b
(Week 10) 30 = 10m + b
Solving for m and b gives the values as m = -3 and b = 60. Thus, the equation is
y = -3x + 60
y = -3x + 60
Step-by-step explanation:
For the answer to the question above,
let x = number of weeks let y = amount of waste.
The linear equation may be expressed as,y = mx + b
m and b are the slope and y - intercept, respectively. Substituting the corresponding values,
(Week 5) 45 = 5m + b
(Week 10) 30 = 10m + b
Solving for m and b gives the values as m = -3 and b = 60. Thus, the equation is
y = -3x + 60
f(x) = −2x + 50
Step-by-step explanation:
f(x) = −2x + 50
Step-by-step explanation:
y = -3x + 60, D: x ≥ 0, r: y ≥ 0
Step-by-step explanation:
1. Find the slope (x-axis is the week number, y-axis is the # of dump loads)
Slope equation: (y₁ - y₂)/(x₁ - x₂), where two points are (x₁, y₁) and (x₂, y₂)
Plug in: (45 - 30)/(5 - 10)
Subtract: 15/(-5)
Divide: -3, representing the number of dumps removed/week
2. Find the y-intercept (when x = 0)
Since we found that 3 dumps are removed per week, we can find that at week 0, there were 60 dump loads.
3. Construct equation
Point-intercept equation: y = mx + b, where m = slope, b = y-intercept
Plug in: y = -3x + 60 (with the domain of x ≥ 0 and the range of y ≥ 0)
It will provide an instant answer!