B
Step-by-step explanation:
Looking at the problem, we see that our constant rate is 999/1000 because the pressure is only nine hundred ninety-nine hundredths of the previous pressure. Since this is a rate, it can't be a linear function, so eliminate C.
Now, look at the rate. 999/1000 < 1, which means that the function is decreasing as the x values approach infinity or grow larger. That is an indication that this is an exponential decay.
The answer is thus B.
C. Linear
Step-by-step explanation:
The problem says that the quantity will increase each year, so we can definitely get rid of exponential decay because that indicates that the graph will decrease.
Now, the problem says the quantity increases 0.05 grams per year. It doesn't say anything about multiplication or how one year's quantity is k times the previous year's quantity. That means this must not be exponential at all, eliminating A.
Instead, this is actually linear because the common difference that you add each year is 0.05.
The answer is thus C.
A
Step-by-step explanation:
"Twice" as bright can translate into the mathematical expression "times 2", where for every year, you multiply the previous year's brightness by 2.
Since this is a rate (using multiplication) and not a common difference (not using addition), it must be an exponential something, so eliminate C.
Now, since 2 > 1, that means this is an exponential growth. Remember that if the rate r is less than 1, then it's decay; if r is greater than 1, then it's growth.
The answer is thus A.
C. Linear
Step-by-step explanation:
The problem says that the quantity will increase each year, so we can definitely get rid of exponential decay because that indicates that the graph will decrease.
Now, the problem says the quantity increases 0.05 grams per year. It doesn't say anything about multiplication or how one year's quantity is k times the previous year's quantity. That means this must not be exponential at all, eliminating A.
Instead, this is actually linear because the common difference that you add each year is 0.05.
The answer is thus C.
A
Step-by-step explanation:
"Twice" as bright can translate into the mathematical expression "times 2", where for every year, you multiply the previous year's brightness by 2.
Since this is a rate (using multiplication) and not a common difference (not using addition), it must be an exponential something, so eliminate C.
Now, since 2 > 1, that means this is an exponential growth. Remember that if the rate r is less than 1, then it's decay; if r is greater than 1, then it's growth.
The answer is thus A.
The answers to the question are
How long did it take the population to double? Answer = one weekHow long did it take the population to triple? Answer = 1.58 weeksWhen were there 10, 000 ants on board? Answer = 5.06 weeksHow long into the voyage were there 200 ants per anteater? Answer = 11.38 weeksStep-by-step explanation:
To solve the question we use a similar analogy of half life calculation
Therefore we have
where
Number of ants after time t
Starting number of ants
Therefore
600 = 300 ×
= 2
㏑ = ㏑2
㏑2 = ㏑2
= 1 and t = 1 week
It took one week for the population of the ants to double
For the population to triple, we have
3×300 = 300×
900 = 300×
=3
x㏑2 =㏑3 or x = = 1.58 weeks
There were 10000 ants onboard after
10000 = 300×
or = and x = (㏑ )/㏑2 = 5.06 weeks
For the anteaters we have
Time for the anteaters to double = 3.2 weeks
Therefore t in the equation = 3.2 weeks
and the length of time it took for the population of ant eaters to grow to 200 is given by
200 = 17× =17×
From which we have
㏑2 = ㏑(200/17)
x = 3.2×3.56 = 11.38 weeks
B
Step-by-step explanation:
Looking at the problem, we see that our constant rate is 999/1000 because the pressure is only nine hundred ninety-nine hundredths of the previous pressure. Since this is a rate, it can't be a linear function, so eliminate C.
Now, look at the rate. 999/1000 < 1, which means that the function is decreasing as the x values approach infinity or grow larger. That is an indication that this is an exponential decay.
The answer is thus B.
It takes 1 week for the ant population to double
It takes 1.58 weeks for the ant population to triple
It takes 5.06 weeks for the ant population to reach 10000
It takes 5.09 weeks for the ant population to be 200 times the ant eater population.
Step-by-step explanation:
It takes only 1 week for the population to double from 300 to 600
We can model the population of ant (or anteater) as the following:
Where a = 300 is the initial population at t = 0
When t = 1, P = 600
k = ln2 = 0.693
When the population tripled, p/a = 3
t = 1.1/k = 1.1/0.693 = 1.58 weeks.
When there are 10000 ants on board, p = 10000:
t = 3.51 / k = 3.51 / 0.693 = 5.06 weeks.
Similarly for anteater, at t = 0 there are 17 of them so A = 17. We can solve for their K parameter if the population doubled after 3.2 weeks
At the time there are 200 ants per anteater
weeks
It will provide an instant answer!