Name and Title:
name, teacher's name, date, chemical components lab.
Objectives(s):
The purpose of this lab was to use elements and make chemical compounds.
Hypothesis:
If I use sodium, carbon, and hydrogen, then I can make at least 5 new compounds in 5 minutes.
Procedure:
The independent variable is the number and types of elements I picked for my compounds. The dependent variable is the types of compounds made.
Data:
Record the composition of each of your compounds below. Be sure to include the number of atoms for each element. An example has been supplied for you.
Compound Name
Sodium hydride
Chemical Formula
NaH
Sodium (Na) Atoms
1
Calcium (Ca) Atoms
0
Hydrogen (H) Atoms
1
Oxygen (O) Atoms
0
Carbon (C) Atoms
0
Chlorine (Cl) Atoms
0
Tricarbon (c3) Atoms (MY TEACHER TOLD ME TO ADD THIS ONE)
0
Compound Name
Methylene (carbene)
Chemical Formula
CH2
Sodium (Na) Atoms
0
Calcium (Ca) Atoms
0
Hydrogen (H) Atoms
2
Oxygen (O) Atoms
0
Carbon (C) Atoms
1
Chlorine (Cl) Atoms
0
Tricarbon (c3) Atoms (MY TEACHER TOLD ME TO ADD THIS ONE)
0
Compound Name
Sodium carbide
Chemical Formula
Na2C2
Sodium (Na) Atoms
2
Calcium (Ca) Atoms
0
Hydrogen (H) Atoms
0
Oxygen (O) Atoms
0
Carbon (C) Atoms
2
Chlorine (Cl) Atoms
0
Tricarbon (c3) Atoms (MY TEACHER TOLD ME TO ADD THIS ONE)
0
Compound Name
Diatomic carbon
Chemical Formula
C2
Sodium (Na) Atoms
0
Calcium (Ca) Atoms
0
Hydrogen (H) Atoms
0
Oxygen (O) Atoms
0
Carbon (C) Atoms
2
Chlorine (Cl) Atoms
0
Tricarbon (c3) Atoms (MY TEACHER TOLD ME TO ADD THIS ONE)
0
Compound Name
Hydrogen gas
Chemical Formula
H2
Sodium (Na) Atoms
0
Calcium (Ca) Atoms
0
Hydrogen (H) Atoms
2
Oxygen (O) Atoms
0
Carbon (C) Atoms
0
Chlorine (Cl) Atoms
0
Tricarbon (c3) Atoms (MY TEACHER TOLD ME TO ADD THIS ONE)
0
Compound Name
acetylene
Chemical Formula
C2H2
Sodium (Na) Atoms
0
Calcium (Ca) Atoms
0
Hydrogen (H) Atoms
2
Oxygen (O) Atoms
0
Carbon (C) Atoms
2
Chlorine (Cl) Atoms
0
Tricarbon (c3) Atoms (MY TEACHER TOLD ME TO ADD THIS ONE)
0
Compound Name
Tricarbon
Chemical Formula
C3
Sodium (Na) Atoms
0
Calcium (Ca) Atoms
0
Hydrogen (H) Atoms
0
Oxygen (O) Atoms
0
Carbon (C) Atoms
3
Chlorine (Cl) Atoms
0
Tricarbon (c3) Atoms (MY TEACHER TOLD ME TO ADD THIS ONE)
0
Compound Name
Diamond
Chemical Formula
C,Crystal
Sodium (Na) Atoms
0
Calcium (Ca) Atoms
0
Hydrogen (H) Atoms
0
Oxygen (O) Atoms
0
Carbon (C) Atoms
1
Chlorine (Cl) Atoms
0
Tricarbon (c3) Atoms (MY TEACHER TOLD ME TO ADD THIS ONE)
3
Name and Title:
name, teacher's name, date, chemical components lab.
Objectives(s):
The purpose of this lab was to use elements and make chemical compounds.
Hypothesis:
If I use sodium, carbon, and hydrogen, then I can make at least 5 new compounds in 5 minutes.
Procedure:
The independent variable is the number and types of elements I picked for my compounds. The dependent variable is the types of compounds made.
Data:
Record the composition of each of your compounds below. Be sure to include the number of atoms for each element. An example has been supplied for you.
Compound Name
Sodium hydride
Chemical Formula
NaH
Sodium (Na) Atoms
1
Calcium (Ca) Atoms
0
Hydrogen (H) Atoms
1
Oxygen (O) Atoms
0
Carbon (C) Atoms
0
Chlorine (Cl) Atoms
0
Tricarbon (c3) Atoms (MY TEACHER TOLD ME TO ADD THIS ONE)
0
Compound Name
Methylene (carbene)
Chemical Formula
CH2
Sodium (Na) Atoms
0
Calcium (Ca) Atoms
0
Hydrogen (H) Atoms
2
Oxygen (O) Atoms
0
Carbon (C) Atoms
1
Chlorine (Cl) Atoms
0
Tricarbon (c3) Atoms (MY TEACHER TOLD ME TO ADD THIS ONE)
0
Compound Name
Sodium carbide
Chemical Formula
Na2C2
Sodium (Na) Atoms
2
Calcium (Ca) Atoms
0
Hydrogen (H) Atoms
0
Oxygen (O) Atoms
0
Carbon (C) Atoms
2
Chlorine (Cl) Atoms
0
Tricarbon (c3) Atoms (MY TEACHER TOLD ME TO ADD THIS ONE)
0
Compound Name
Diatomic carbon
Chemical Formula
C2
Sodium (Na) Atoms
0
Calcium (Ca) Atoms
0
Hydrogen (H) Atoms
0
Oxygen (O) Atoms
0
Carbon (C) Atoms
2
Chlorine (Cl) Atoms
0
Tricarbon (c3) Atoms (MY TEACHER TOLD ME TO ADD THIS ONE)
0
Compound Name
Hydrogen gas
Chemical Formula
H2
Sodium (Na) Atoms
0
Calcium (Ca) Atoms
0
Hydrogen (H) Atoms
2
Oxygen (O) Atoms
0
Carbon (C) Atoms
0
Chlorine (Cl) Atoms
0
Tricarbon (c3) Atoms (MY TEACHER TOLD ME TO ADD THIS ONE)
0
Compound Name
acetylene
Chemical Formula
C2H2
Sodium (Na) Atoms
0
Calcium (Ca) Atoms
0
Hydrogen (H) Atoms
2
Oxygen (O) Atoms
0
Carbon (C) Atoms
2
Chlorine (Cl) Atoms
0
Tricarbon (c3) Atoms (MY TEACHER TOLD ME TO ADD THIS ONE)
0
Compound Name
Tricarbon
Chemical Formula
C3
Sodium (Na) Atoms
0
Calcium (Ca) Atoms
0
Hydrogen (H) Atoms
0
Oxygen (O) Atoms
0
Carbon (C) Atoms
3
Chlorine (Cl) Atoms
0
Tricarbon (c3) Atoms (MY TEACHER TOLD ME TO ADD THIS ONE)
0
Compound Name
Diamond
Chemical Formula
C,Crystal
Sodium (Na) Atoms
0
Calcium (Ca) Atoms
0
Hydrogen (H) Atoms
0
Oxygen (O) Atoms
0
Carbon (C) Atoms
1
Chlorine (Cl) Atoms
0
Tricarbon (c3) Atoms (MY TEACHER TOLD ME TO ADD THIS ONE)
3
Name and Title:
Colleen DeBruin, Hillary Mulkavits, 11/18/2020, compounds lab.
Objectives(s):
to build chemical compounds from known elements
Hypothesis:
if I use oxygen hydrogen and carbon then I can make five new compounds in four minutes
Procedure:
The materials and procedures are listed in your virtual lab. You do not need to repeat them here. However, you should note if you experienced any errors or other factors that might affect your outcome. Using your summary questions at the end of your virtual lab activity, please clearly define the dependent and independent variables of the experiment.
Data:
Record the composition of each of your compounds below. Be sure to include the number of atoms for each element. An example has been supplied for you.
Compound NameChemical FormulaSodium (Na) AtomsCalcium (Ca) AtomsHydrogen (H) AtomsOxygen (O) AtomsCarbon (C) AtomsChlorine (Cl) Atoms
Ex: Sodium
hypochloriteNaClO100101
Water H20 o 0 1 2 0 0
Glucose C6H12O6 0 0 12 6 6 0
Formic/methanoic acid HCOOH0 0 2 2 10
Butanoic Acid C3H7COOH0 0 8 2 40
Carbon Dioxide C020 0 0 2 10
Carbon Monoxide CO0 0 0 1 10
Fructose C6H12O60 0 12 6 60
0 0 0
0 0 0
0 0 0
Conclusion:
Your conclusion will include a summary of the lab results and an interpretation of the results. Please answer all questions in complete sentences using your own words.
I found as many combinations of carbon hydrogen and oxygen as possible
If there is a job that combines elements you would be doing that every day making it an every day matter
elements are like people, they are all different causing them to react differently and be more reactive
H20 has four because there are 2 oxygen and one hydrogen because of the numbers in the name of the compound
Yes because two elements can form two different types of bonds causing different outcomes
If this isn't right I'm sorry but I had it as an assignment so we will get it wrong together lol
Name and Title:
Colleen DeBruin, Hillary Mulkavits, 11/18/2020, compounds lab.
Objectives(s):
to build chemical compounds from known elements
Hypothesis:
if I use oxygen hydrogen and carbon then I can make five new compounds in four minutes
Procedure:
The materials and procedures are listed in your virtual lab. You do not need to repeat them here. However, you should note if you experienced any errors or other factors that might affect your outcome. Using your summary questions at the end of your virtual lab activity, please clearly define the dependent and independent variables of the experiment.
Data:
Record the composition of each of your compounds below. Be sure to include the number of atoms for each element. An example has been supplied for you.
Compound Name Chemical Formula Sodium (Na) Atoms Calcium (Ca) Atoms Hydrogen (H) Atoms Oxygen (O) Atoms Carbon (C) Atoms Chlorine (Cl) Atoms
Ex: Sodium
hypochlorite NaClO 1 0 0 1 0 1
Water H20 o 0 1 2 0 0
Glucose C6H12O6 0 0 12 6 6 0
Formic/methanoic acid HCOOH 0 0 2 2 1 0
Butanoic Acid C3H7COOH 0 0 8 2 4 0
Carbon Dioxide C02 0 0 0 2 1 0
Carbon Monoxide CO 0 0 0 1 1 0
Fructose C6H12O6 0 0 12 6 6 0
0 0 0
0 0 0
0 0 0
Conclusion:
Your conclusion will include a summary of the lab results and an interpretation of the results. Please answer all questions in complete sentences using your own words.
I found as many combinations of carbon hydrogen and oxygen as possible
If there is a job that combines elements you would be doing that every day making it an every day matter
elements are like people, they are all different causing them to react differently and be more reactive
H20 has four because there are 2 oxygen and one hydrogen because of the numbers in the name of the compound
Yes because two elements can form two different types of bonds causing different outcomes
Explanation:
Independent variable: the best method to get rid of them.
Dependent variable: washing with soap and water.
Hypothesis: Organic oils
Control group: water
Answer:
Option DStep-by-step explanation:
D.
Heat each cube to the same temperature, place each cube into different containers with 500 grams of water at the same temperature, and measure the temperature of the water.
Answer:
see below.Step-by-step explanation:
To solve this problem, we can use the conservation of energy and conservation of momentum principles.
Conservation of energy:
The total initial energy is the rest energy of the proton and neutron, which is given by:
Ei = (mp + mn)c^2
where mp and mn are the masses of the proton and neutron, respectively, and c is the speed of light.
The total final energy is the rest energy of the deuteron plus the energy of the gamma ray, which is given by:
Ef = (md)c^2 + Eg
where md is the mass of the deuteron and Eg is the energy of the gamma ray.
According to the conservation of energy principle, the initial energy and final energy must be equal, so we have:
Ei = Ef
(mp + mn)c^2 = (md)c^2 + Eg
Conservation of momentum:
The total initial momentum is zero because the proton and neutron are at rest. The total final momentum is the momentum of the deuteron and the momentum of the gamma ray. Since the gamma ray is massless, its momentum is given by:
pg = Eg/c
where pg is the momentum of the gamma ray.
According to the conservation of momentum principle, the total final momentum must be equal to zero, so we have:
0 = pd + pg
where pd is the momentum of the deuteron.
Solving for md and pd:
From the conservation of energy equation, we can solve for md:
md = (mp + mn - Eg/c^2)/c^2
Substituting this expression into the conservation of momentum equation, we get:
pd = -pg = -Eg/c
Substituting the given values, we have:
mp = 1.6726 × 10^-27 kg mn = 1.6749 × 10^-27 kg Eg = 2.2 × 10^6 eV = 3.52 × 10^-13 J
Using c = 2.998 × 10^8 m/s, we get:
md = (1.6726 × 10^-27 kg + 1.6749 × 10^-27 kg - 3.52 × 10^-13 J/(2.998 × 10^8 m/s)^2)/(2.998 × 10^8 m/s)^2 = 3.3435 × 10^-27 kg
pd = -Eg/c = -(3.52 × 10^-13 J)/(2.998 × 10^8 m/s) = -1.1723 × 10^-21 kg·m/s
Therefore, the mass of the deuteron is 3.3435 × 10^-27 kg, and its momentum is -1.1723 × 10^-21 kg·m/s.
Answer:
9.6 metersStep-by-step explanation:
Time taken by the tomatoes to each the ground
using h = 1/2 g t^2
t^2 = 2h/g = 2 x 50/ 9.8 = 10.2
t = 3.2 sec
horizontal ditance = speed x time = 3 x 3.2 = 9.6 meters
The question specifies the diameter of the screw, therefore the IMA of this screw is 0.812? / 0.318 = 8.02
It will provide an instant answer!