Theoretical fracture strength is; σ_m = 13,685 MPa
None of the options are correct
Explanation:
We are given;
Nominal applied stress;σ_o = 1060 MPa
Length of surface crack; a = 0.25 mm
Tip radius of curvature; ρ_t = 0.006 mm
Now, the formula for the theoretical fracture strength which is the maximum stress at the crack tip is given as;
σ_m = 2σ_o[a/ρ_t]^(½)
Plugging in the relevant values, we have;
σ_m = 2(1060)[0.25/0.006]^(½)
σ_m = 13,685 MPa
the theoretical fracture strength of the brittle material is 5.02 × 10⁶ psi
Explanation:
Given the data in the question;
Length of surface crack α = 0.25 mm
tip radius ρ = 1.2 × 10⁻³ mm
applied stress σ₀ = 1200 MPa
the theoretical fracture strength of a brittle material = ?
To determine the the theoretical fracture strength or maximum stress at crack tip, we use the following formula;
σ = 2σ₀ α / ρ
where α is the Length of surface crack,
ρ is the tip radius,
and σ₀ is the applied stress.
so we substitute
σ = (2 × 1200 MPa) 0.25 mm / ( 1.2 × 10⁻³ mm )
σ = 2400 MPa × 208.3333
σ = 2400 MPa × 14.43375
σ = 34641 MPa
σ = ( 34641 × 145 )psi
σ = 5.02 × 10⁶ psi
Therefore, the theoretical fracture strength of the brittle material is 5.02 × 10⁶ psi
critical stress = 17.899 MPa
Explanation:
given data
specific surface energy = 0.33 J/m²
flexural strength = 88.1 MPa
elastic modulus values E = 61 GPa
surface crack of length = 0.04 mm
to find out
critical stress (in MPa)
solution
we get here critical stress that is express as
critical stress = .....................1
here E is elastic modulus values and a is surface crack of length and γ is specific surface energy
put here value we get
critical stress =
critical stress = 1.7899 × N/m²
critical stress = 17.899 MPa
Theoretical fracture strength is; σ_m = 13,685 MPa
None of the options are correct
Explanation:
We are given;
Nominal applied stress;σ_o = 1060 MPa
Length of surface crack; a = 0.25 mm
Tip radius of curvature; ρ_t = 0.006 mm
Now, the formula for the theoretical fracture strength which is the maximum stress at the crack tip is given as;
σ_m = 2σ_o[a/ρ_t]^(½)
Plugging in the relevant values, we have;
σ_m = 2(1060)[0.25/0.006]^(½)
σ_m = 13,685 MPa
theoretical fracture strength is 9916.58 MPa
Explanation:
given data
surface crack of length L = 0.26 mm
radius of curvature r = 0.004 mm
stress So = 1230 MPa
solution
we get here theoretical fracture strength S that is express as
S = .................1
here So is stress and L is length and r is radius
put here value and we get
S =
solve it we get
S = 9916.58 MPa
so theoretical fracture strength is 9916.58 MPa
The theoretical fracture strength of the brittle material is 11864.5 MPa
Explanation:
Fracture strength is the ability of a material to withstand fracture. It is also known as the breaking stress, it is the stress at which the material fails as a result of fracture. It usually determined from the stress-strain curve after performing a tensile test.
Given that:
Length (L) = 0.15 mm = 0.15 × 10⁻³ m
radius of curvature (r) = 0.002 mm = 0.002 × 10⁻³ m
Stress (s₀) = 1370 MPa = 1370 × 10⁶ Pa
theoretical fracture strength (s) = ?
The theoretical fracture strength is given as:
Substituting values:
s = 11864.5 MPa
The theoretical fracture strength of the brittle material is 11864.5 MPa
critical stress = 17.899 MPa
Explanation:
given data
specific surface energy = 0.33 J/m²
flexural strength = 88.1 MPa
elastic modulus values E = 61 GPa
surface crack of length = 0.04 mm
to find out
critical stress (in MPa)
solution
we get here critical stress that is express as
critical stress = .....................1
here E is elastic modulus values and a is surface crack of length and γ is specific surface energy
put here value we get
critical stress =
critical stress = 1.7899 × N/m²
critical stress = 17.899 MPa
34.64Gpa
Explanation:
We can calculate the theoretical fracture strenght by,
Here we have,
Applied stress
Tip radius
lenght of surface crack or half of the lenght of internal crack
Replacing,
Therefore the maximum stress at the crack tip is 34.64Gpa
The theoretical fracture strength of a brittle material is 26465.29 MPa.
Explanation:
Given that,
Length = 0.54 mm
Radius curvature
Stress = 1050 MPa
We need to calculate the theoretical fracture strength of a brittle material
Using formula of strength
Where, l = length of the crack
= tip radius of curvature
Put the value into the formula
Hence, The theoretical fracture strength of a brittle material is 26465.29 MPa.
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