Physics : asked on PrestonTB
 09.02.2022

Inez is making a model of a sugar crystal. she wants her model to show how the sugar molecules move in the crystal. she is using plastic foams balls to represent the sugar molecules. how should she put the plastic foam balls together to make her model

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17.02.2022, solved by verified expert
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Options:

A. Connect them with stiff springs 

B. Fill a clear cube with them 

C. Glue them together 

D. Place a few of them in a plastic bag​

Answer:

B. Fill a clear cube with them

Explanation:

Sugar crystals, colloquially known as "rock candy", are conglomerates of sugar molecules that are formed when sugar-saturated water are cooled. Sugar crystals are arranged in a three dimensional repeating pattern, forming a cube like structure. Therefore, Inez could fill a clear cube with its plastic foam balls to represent sugar crystals. I attached an image of sugar crystals dissolving in water as reference.

Inez is making a model of a sugar crystal. she, №15222290, 09.02.2022 18:13

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Biology
Step-by-step answer
P Answered by Master

The correct answer is option B. "Fill a clear cube with them".

Explanation:

Sugar crystals, colloquially known as "rock candy", are conglomerates of sugar molecules that are formed when sugar-saturated water are cooled. Sugar crystals are arranged in a three dimensional repeating pattern, forming a cube like structure. Therefore, Juan could fill a clear cube with its plastic foam balls to represent sugar crystals. I attached an image of sugar crystals dissolving in water as reference.


Juan and his science class are constructing models of sugar crystals. He wants his model to show how
Biology
Step-by-step answer
P Answered by Master

The correct answer is option B. "Fill a clear cube with them".

Explanation:

Sugar crystals, colloquially known as "rock candy", are conglomerates of sugar molecules that are formed when sugar-saturated water are cooled. Sugar crystals are arranged in a three dimensional repeating pattern, forming a cube like structure. Therefore, Juan could fill a clear cube with its plastic foam balls to represent sugar crystals. I attached an image of sugar crystals dissolving in water as reference.


Juan and his science class are constructing models of sugar crystals. He wants his model to show how
Biology
Step-by-step answer
P Answered by PhD

Sugar Crystal model: she wants her model to show how sugar molecule move the crystal she is using plastic foam ball to represent the sugar molecule :

Sugar Crystal model: she wants her model to show how sugar molecule move the crystal she is using plSugar Crystal model: she wants her model to show how sugar molecule move the crystal she is using pl
Physics
Step-by-step answer
P Answered by Master

Answer:

see below.

Step-by-step explanation:

To solve this problem, we can use the conservation of energy and conservation of momentum principles.

Conservation of energy:

The total initial energy is the rest energy of the proton and neutron, which is given by:

Ei = (mp + mn)c^2

where mp and mn are the masses of the proton and neutron, respectively, and c is the speed of light.

The total final energy is the rest energy of the deuteron plus the energy of the gamma ray, which is given by:

Ef = (md)c^2 + Eg

where md is the mass of the deuteron and Eg is the energy of the gamma ray.

According to the conservation of energy principle, the initial energy and final energy must be equal, so we have:

Ei = Ef

(mp + mn)c^2 = (md)c^2 + Eg

Conservation of momentum:

The total initial momentum is zero because the proton and neutron are at rest. The total final momentum is the momentum of the deuteron and the momentum of the gamma ray. Since the gamma ray is massless, its momentum is given by:

pg = Eg/c

where pg is the momentum of the gamma ray.

According to the conservation of momentum principle, the total final momentum must be equal to zero, so we have:

0 = pd + pg

where pd is the momentum of the deuteron.

Solving for md and pd:

From the conservation of energy equation, we can solve for md:

md = (mp + mn - Eg/c^2)/c^2

Substituting this expression into the conservation of momentum equation, we get:

pd = -pg = -Eg/c

Substituting the given values, we have:

mp = 1.6726 × 10^-27 kg mn = 1.6749 × 10^-27 kg Eg = 2.2 × 10^6 eV = 3.52 × 10^-13 J

Using c = 2.998 × 10^8 m/s, we get:

md = (1.6726 × 10^-27 kg + 1.6749 × 10^-27 kg - 3.52 × 10^-13 J/(2.998 × 10^8 m/s)^2)/(2.998 × 10^8 m/s)^2 = 3.3435 × 10^-27 kg

pd = -Eg/c = -(3.52 × 10^-13 J)/(2.998 × 10^8 m/s) = -1.1723 × 10^-21 kg·m/s

Therefore, the mass of the deuteron is 3.3435 × 10^-27 kg, and its momentum is -1.1723 × 10^-21 kg·m/s.

Physics
Step-by-step answer
P Answered by PhD

Answer:

9.6 meters

Step-by-step explanation:

Time taken by the tomatoes to each the ground

using h = 1/2 g t^2 

t^2 = 2h/g = 2 x 50/ 9.8 = 10.2

t = 3.2 sec 

horizontal ditance = speed x time = 3 x 3.2 = 9.6 meters

Physics
Step-by-step answer
P Answered by PhD

The question specifies the diameter of the screw, therefore the IMA of this screw is 0.812? / 0.318 = 8.02

Physics
Step-by-step answer
P Answered by PhD
Answer:
7.25 secs.

Explanation:
First find the distance it takes to stop
s = [v^2-u^2]/2a = 0^2 - 8.7^2/2[-2.4] = 8.7^2/4.8
Next find the time it takes to go that distance , s = ut +[1/2] at^2
8.7^2/4.8 = 8.7t +[1/2] [ -2.4]t^2 , rearrange and
t^2 -[8.7/1.2]+ 8.7^2/[(1.2)(4.8)]=0 complete the square
[t - (8.7/2.4)]^2=0
t = 8.7/2.4 = 3.625 secs
At this stage the deceleration will push the object back in the direction it came from for another 3.625 secs when it will be 8.7 m/s again
Total time , T =2t = 7.25 secs.

Note:
The term differential is used in calculus to refer to an infinitesimal (infinitely small) change in some varying quantity. For example, if x is a variable, then a change in the value of x is often denoted Δx (pronounced delta x). The differential dx represents an infinitely small change in the variable x.
Physics
Step-by-step answer
P Answered by PhD
The change in temperature is 9.52°CExplanation:Since, the heat supplied by the electric kettle is totally used to increase the temperature of the water.Thus, from the law of conservation of energy can be stated as:Heat Supplied by Electric Kettle = Heat Absorbed by WaterHeat Supplied by Electric Kettle = m C ΔTwhere,Heat Supplied by Electric Kettle = 20,000 JMass of water = m = 0.5 kgSpecific Heat Capacity of Water = C = 4200 J/kg.°CChange in Temperature of Water = ΔTTherefore,20,000 J = (0.5 kg)(4200 J/kg.°C) ΔTΔT = 20,000 J/(2100 J/°C)ΔT = 9.52°C

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