Physics
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01.12.2022 the following question

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Physics

Step-by-step answer

**Answer:**

**Step-by-step explanation:**

D.

Heat each cube to the same temperature, place each cube into different containers with 500 grams of water at the same temperature, and measure the temperature of the water.

Physics

Step-by-step answer

**Answer:**

**Step-by-step explanation:**

Time taken by the tomatoes to each the ground

using h = 1/2 g t^2

t^2 = 2h/g = 2 x 50/ 9.8 = 10.2

t = 3.2 sec

horizontal ditance = speed x time = 3 x 3.2 = 9.6 meters

Physics

Step-by-step answer

The question specifies the diameter of the screw, therefore the IMA of this screw is 0.812? / 0.318 = 8.02

Physics

Step-by-step answer

Answer:

7.25 secs.

Explanation:

First find the distance it takes to stop

s = [v^2-u^2]/2a = 0^2 - 8.7^2/2[-2.4] = 8.7^2/4.8

Next find the time it takes to go that distance , s = ut +[1/2] at^2

8.7^2/4.8 = 8.7t +[1/2] [ -2.4]t^2 , rearrange and

t^2 -[8.7/1.2]+ 8.7^2/[(1.2)(4.8)]=0 complete the square

[t - (8.7/2.4)]^2=0

t = 8.7/2.4 = 3.625 secs

At this stage the deceleration will push the object back in the direction it came from for another 3.625 secs when it will be 8.7 m/s again

Total time , T =2t = 7.25 secs.

Note:

The term differential is used in calculus to refer to an infinitesimal (infinitely small) change in some varying quantity. For example, if x is a variable, then a change in the value of x is often denoted Δx (pronounced delta x). The differential dx represents an infinitely small change in the variable x.

7.25 secs.

Explanation:

First find the distance it takes to stop

s = [v^2-u^2]/2a = 0^2 - 8.7^2/2[-2.4] = 8.7^2/4.8

Next find the time it takes to go that distance , s = ut +[1/2] at^2

8.7^2/4.8 = 8.7t +[1/2] [ -2.4]t^2 , rearrange and

t^2 -[8.7/1.2]+ 8.7^2/[(1.2)(4.8)]=0 complete the square

[t - (8.7/2.4)]^2=0

t = 8.7/2.4 = 3.625 secs

At this stage the deceleration will push the object back in the direction it came from for another 3.625 secs when it will be 8.7 m/s again

Total time , T =2t = 7.25 secs.

Note:

The term differential is used in calculus to refer to an infinitesimal (infinitely small) change in some varying quantity. For example, if x is a variable, then a change in the value of x is often denoted Δx (pronounced delta x). The differential dx represents an infinitely small change in the variable x.

Physics

Step-by-step answer

First sum applied the Newton's second law motion: F = ma

Force = mass* acceleration

This motion define force as the product of mass times Acceleration (vs.Velocity). Since acceleration is the change in velocity divided by time,

force=(mass*velocity)/time

such that, (mass*velocity)/time=momentum/time

Therefore we get mass*velocity=momentum

Momentum=mass*velocity

Elephant mass=6300 kg; velocity=0.11 m/s

Momentum=6300*0.11

P=693 kg (m/s)

Dolphin mass=50 kg; velocity=10.4 m/s

Momentum=50*10.4

P=520 kg (m/s)

The elephant has more momentum(P) because it is large.

Force = mass* acceleration

This motion define force as the product of mass times Acceleration (vs.Velocity). Since acceleration is the change in velocity divided by time,

force=(mass*velocity)/time

such that, (mass*velocity)/time=momentum/time

Therefore we get mass*velocity=momentum

Momentum=mass*velocity

Elephant mass=6300 kg; velocity=0.11 m/s

Momentum=6300*0.11

P=693 kg (m/s)

Dolphin mass=50 kg; velocity=10.4 m/s

Momentum=50*10.4

P=520 kg (m/s)

The elephant has more momentum(P) because it is large.

Physics

Step-by-step answer

The change in temperature is 9.52°CExplanation:Since, the heat supplied by the electric kettle is totally used to increase the temperature of the water.Thus, from the law of conservation of energy can be stated as:Heat Supplied by Electric Kettle = Heat Absorbed by WaterHeat Supplied by Electric Kettle = m C ΔTwhere,Heat Supplied by Electric Kettle = 20,000 JMass of water = m = 0.5 kgSpecific Heat Capacity of Water = C = 4200 J/kg.°CChange in Temperature of Water = ΔTTherefore,20,000 J = (0.5 kg)(4200 J/kg.°C) ΔTΔT = 20,000 J/(2100 J/°C)ΔT = 9.52°C

Physics

Step-by-step answer

Weight of barbell (m) = 100 kg

Uplifted to height (h) = 2m

Time taken= 1.5 s

Work done by Jordan = potential energy stored in barbell = mgh

= 100×2×9.8

= 1960J

Power = energy/time

= 1960/1.5

1306.67watts

Uplifted to height (h) = 2m

Time taken= 1.5 s

Work done by Jordan = potential energy stored in barbell = mgh

= 100×2×9.8

= 1960J

Power = energy/time

= 1960/1.5

1306.67watts

Physics

Step-by-step answer

Weight of jasmine (m) = 400 N

Height climbed on wall (h) = 5m

Total time taken in climbing = 5 sec

Work done in climbing the wall = rise in potential energy = mgh

= 400×9.8×51

= 19600J

Power generated by Jasmine = potential energy / time

= 19600/5

= 3920Watts

Height climbed on wall (h) = 5m

Total time taken in climbing = 5 sec

Work done in climbing the wall = rise in potential energy = mgh

= 400×9.8×51

= 19600J

Power generated by Jasmine = potential energy / time

= 19600/5

= 3920Watts

Physics

Step-by-step answer

The horizontal and vertical motions of balloons are independent from each other.

Let vertical component of initial velocity U' horizontal component of initial velocity U"

Time of landing (t) is found with the help of vertical motion.

Since vertical component of initial velocity of balloon is zero(U' = 0)

From equation h = U't + 1/2gt^2

h = 1/2gt^2

t = √(2h/g)

t = √( 2×150/9.8)

t = 5.53 sec

Horizontal velocity = 50m/s

Horizontal range of balloon, R = U"t

= 50× 5.53

= 27.65m

So the balloon will go 27.65 metre away from the bridge

Let vertical component of initial velocity U' horizontal component of initial velocity U"

Time of landing (t) is found with the help of vertical motion.

Since vertical component of initial velocity of balloon is zero(U' = 0)

From equation h = U't + 1/2gt^2

h = 1/2gt^2

t = √(2h/g)

t = √( 2×150/9.8)

t = 5.53 sec

Horizontal velocity = 50m/s

Horizontal range of balloon, R = U"t

= 50× 5.53

= 27.65m

So the balloon will go 27.65 metre away from the bridge

Physics

Step-by-step answer

Gravity acceleration (g) = 9.8m/s^2

Time (t) = 3sec

Acceleration = velocity/time

Velocity = acceleration×time

= 9.8×3

= 29.4m/s

Time (t) = 3sec

Acceleration = velocity/time

Velocity = acceleration×time

= 9.8×3

= 29.4m/s

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