Go to https://phet.colorado.edu/sims/html/energy-skate-park/latest/energy-skate-park_en.html />
1. Click the “Energy” box on the top left to view the changes in PE, KE and thermal energy.
2. Check the boxes for grid and reference height at the bottom left.
3. Check all of the boxes at the top right corner of the simulation including: Pie Chart, Grid, and
Speed.
4. Choose stick to track, none for friction, tiny for gravity, 100kg for mass.
5. Move the skateboarder to the top (maximum height, 6 meters) of one side of the skate
ramp. Release the skateboarder.
6. Spend a few minutes to make sure you understand how potential energy, kinetic energy,
and speed are affected during the simulation. You can pause the simulation, use the slow play button if you need to.


Question 1a: How high does the skater move as the skater goes back and forth from one side of the ramp to the other ?

2. Will the skater fall off the ramp when released at the maximum height of the ramp? Why or why not ?

3. Describe two different ways to increase the total energy in the system in this simulation?

4. As the skateboarder goes back and forth on the ramp, how does thermal energy change?

Create the skate paths as shown. Play the simulation with no friction and then with lots of friction.


Question 2
If the skater starts on the left side on a frictionless track, will the skater have enough energy to make it all the way to the right side? Why?

Question 3
If the skater starts on the left side on a track with friction, will the skater have enough energy to make it all the way to the right side? Why?

Independent variable: the best method to get rid of them.

Dependent variable: washing with soap and water.

Hypothesis: Organic oils

Control group: water

Answer:

Step-by-step explanation:

To solve this problem, we can use the conservation of energy and conservation of momentum principles.

Conservation of energy:

The total initial energy is the rest energy of the proton and neutron, which is given by:

Ei = (mp + mn)c^2

where mp and mn are the masses of the proton and neutron, respectively, and c is the speed of light.

The total final energy is the rest energy of the deuteron plus the energy of the gamma ray, which is given by:

Ef = (md)c^2 + Eg

where md is the mass of the deuteron and Eg is the energy of the gamma ray.

According to the conservation of energy principle, the initial energy and final energy must be equal, so we have:

Ei = Ef

(mp + mn)c^2 = (md)c^2 + Eg

Conservation of momentum:

The total initial momentum is zero because the proton and neutron are at rest. The total final momentum is the momentum of the deuteron and the momentum of the gamma ray. Since the gamma ray is massless, its momentum is given by:

pg = Eg/c

where pg is the momentum of the gamma ray.

According to the conservation of momentum principle, the total final momentum must be equal to zero, so we have:

0 = pd + pg

where pd is the momentum of the deuteron.

Solving for md and pd:

From the conservation of energy equation, we can solve for md:

md = (mp + mn - Eg/c^2)/c^2

Substituting this expression into the conservation of momentum equation, we get:

pd = -pg = -Eg/c

Substituting the given values, we have:

mp = 1.6726 × 10^-27 kg mn = 1.6749 × 10^-27 kg Eg = 2.2 × 10^6 eV = 3.52 × 10^-13 J

Using c = 2.998 × 10^8 m/s, we get:

md = (1.6726 × 10^-27 kg + 1.6749 × 10^-27 kg - 3.52 × 10^-13 J/(2.998 × 10^8 m/s)^2)/(2.998 × 10^8 m/s)^2 = 3.3435 × 10^-27 kg

pd = -Eg/c = -(3.52 × 10^-13 J)/(2.998 × 10^8 m/s) = -1.1723 × 10^-21 kg·m/s

Therefore, the mass of the deuteron is 3.3435 × 10^-27 kg, and its momentum is -1.1723 × 10^-21 kg·m/s.

Answer:

Step-by-step explanation:

Time taken by the tomatoes to each the ground

using h = 1/2 g t^2 

t^2 = 2h/g = 2 x 50/ 9.8 = 10.2

t = 3.2 sec 

horizontal ditance = speed x time = 3 x 3.2 = 9.6 meters

The question specifies the diameter of the screw, therefore the IMA of this screw is 0.812? / 0.318 = 8.02