The moon looks dark from earth
top view #1
top view #2
tanisha says that the moon looks dark from earth when the moon is in two
different places: always when it is closest to the sun, as in top view #1, and
always when it is furthest from the sun, as in top view #2.
is tanisha correct? if she is correct, explain why the moon always looks dark
from earth in both of these positions. if she is incorrect, explain when the
moon looks dark from earth and how light on the moon should look in each of
tanisha's diagrams.

Answer. The Moon always looks dark from Earth in Top View #1 because the illuminated half is facing towards Earth.

Answer:

She is wrong

Explanation:

She is wrong, this is because the moon is dark, meaning that the moon would have to be behind Earth and being blocked from sunlight. For example, if the sun is on the left, the Earth in the middle, the moon would have to be on the right, behind Earth. The moon is dark because the rays only are able to hit the Earth, due to the moon's position.

The moon gets its light from the sun and the closer the moon is to the sun the more light it gets and is has to be positioned in-between the sun and the earth to have such light rays as well.

When the moon is furthest from the sun it will be positioned behind the sun ( i.e. the earth is in-between the sun and the moon ). during this period  the moon will appear dark because the Earth been bigger than the moon sheds away light rays coming from the sun towards the moon.

Independent variable: the best method to get rid of them.

Dependent variable: washing with soap and water.

Hypothesis: Organic oils

Control group: water

Answer:

Step-by-step explanation:

D.
Heat each cube to the same temperature, place each cube into different containers with 500 grams of water at the same temperature, and measure the temperature of the water.

Answer:

Step-by-step explanation:

To solve this problem, we can use the conservation of energy and conservation of momentum principles.

Conservation of energy:

The total initial energy is the rest energy of the proton and neutron, which is given by:

Ei = (mp + mn)c^2

where mp and mn are the masses of the proton and neutron, respectively, and c is the speed of light.

The total final energy is the rest energy of the deuteron plus the energy of the gamma ray, which is given by:

Ef = (md)c^2 + Eg

where md is the mass of the deuteron and Eg is the energy of the gamma ray.

According to the conservation of energy principle, the initial energy and final energy must be equal, so we have:

Ei = Ef

(mp + mn)c^2 = (md)c^2 + Eg

Conservation of momentum:

The total initial momentum is zero because the proton and neutron are at rest. The total final momentum is the momentum of the deuteron and the momentum of the gamma ray. Since the gamma ray is massless, its momentum is given by:

pg = Eg/c

where pg is the momentum of the gamma ray.

According to the conservation of momentum principle, the total final momentum must be equal to zero, so we have:

0 = pd + pg

where pd is the momentum of the deuteron.

Solving for md and pd:

From the conservation of energy equation, we can solve for md:

md = (mp + mn - Eg/c^2)/c^2

Substituting this expression into the conservation of momentum equation, we get:

pd = -pg = -Eg/c

Substituting the given values, we have:

mp = 1.6726 × 10^-27 kg mn = 1.6749 × 10^-27 kg Eg = 2.2 × 10^6 eV = 3.52 × 10^-13 J

Using c = 2.998 × 10^8 m/s, we get:

md = (1.6726 × 10^-27 kg + 1.6749 × 10^-27 kg - 3.52 × 10^-13 J/(2.998 × 10^8 m/s)^2)/(2.998 × 10^8 m/s)^2 = 3.3435 × 10^-27 kg

pd = -Eg/c = -(3.52 × 10^-13 J)/(2.998 × 10^8 m/s) = -1.1723 × 10^-21 kg·m/s

Therefore, the mass of the deuteron is 3.3435 × 10^-27 kg, and its momentum is -1.1723 × 10^-21 kg·m/s.

The question specifies the diameter of the screw, therefore the IMA of this screw is 0.812? / 0.318 = 8.02