1. 50%
2. homozygous recessive
Explanation:
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Brainliest
1. 50%
2. homozygous recessive
Explanation:
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Brainliest
Unattached earlobes and cleft chin : 9
Unattached earlobes and no cleft : 3
Attached earlobes and cleft chin : 3
Attached earlobes and no cleft :1
Explanation:
Given -
Unattached earlobes are dominant to attached earlobes
Let the allele for attached ear lobe be represented by "l" and and unattached ear lobe be represented by "L"
Cleft chin is dominant to no cleft.
Let the allele for cleft chin be represented by "C" and no cleft chin be represented by "c"
Genotype of heterozygous parents
LlCc X LlCc
LC Lc lC lc
LCLLCCLlCc LlCCLlCc
LcLLCcLLcc LlCcLlcc
lCLlCCLlCc llCCllCc
lcLlCc Llcc llCcllcc
LLCC - 1
LlCc – 5
LlCC-2
LLCc – 1
LLcc-1
Llcc -2
llCC-3
llcc-1
Unattached earlobes and cleft chin : 9
Unattached earlobes and no cleft : 3
Attached earlobes and cleft chin : 3
Attached earlobes and no cleft :1
Unattached earlobes and cleft chin : 9
Unattached earlobes and no cleft : 3
Attached earlobes and cleft chin : 3
Attached earlobes and no cleft :1
Explanation:
Given -
Unattached earlobes are dominant to attached earlobes
Let the allele for attached ear lobe be represented by "l" and and unattached ear lobe be represented by "L"
Cleft chin is dominant to no cleft.
Let the allele for cleft chin be represented by "C" and no cleft chin be represented by "c"
Genotype of heterozygous parents
LlCc X LlCc
LC Lc lC lc
LCLLCCLlCc LlCCLlCc
LcLLCcLLcc LlCcLlcc
lCLlCCLlCc llCCllCc
lcLlCc Llcc llCcllcc
LLCC - 1
LlCc – 5
LlCC-2
LLCc – 1
LLcc-1
Llcc -2
llCC-3
llcc-1
Unattached earlobes and cleft chin : 9
Unattached earlobes and no cleft : 3
Attached earlobes and cleft chin : 3
Attached earlobes and no cleft :1
a)9:16 b)3:16 c)3:16 d)1:16
Explanation;To complete the table;
EeAAEEAaEEaaeeAAeeaaUnattached earlobes, will either be Ee (heterozygous) or ee (homozygous)
Cleft chin, will either be; AA (homozygous) or Aa (heterozygous)
Attached earlobes will be ee, while no cleft will be aa.
Therefore; the Unattached earlobes and cleft chin = 9/16
Unattached earlobes and no cleft = 3/16
Attached earlobes and no cleft = 3/16
Attached earlobes and no cleft = 1/16
A. 100 percent Ee
Explanation:
The genotype of the parent who is homozygous for unattached earlobe would be EE.
The genotype for the parent who is homozygous for attached earlobe would be ee.
When a cross is made between these two then ,
EE X ee ---> Ee Ee Ee Ee
The 4 offsprings produced as a result of this cross will all have the genotype Ee.
Since E (unattached earlobe) is dominant over attached earlobe (e) the heterozygous Ee will have unattached earlobe.
Therefore, the genotypic ration would be 100% Ee.
See the attached punnet diagram for the cross.
100 percent Ee
Explanation:
This is a cross involving a single gene coding for attachment or not of earlobes. The allele for unattached earlobes (E) is dominant over the allele for attached earlobe (e). This means that allele E will always mask the phenotypic expression of e in a heterozygous state.
A parent that has same alleles for unattached earlobes i.e. EE is crossed with a parent that has same alleles for attached earlobes i.e. ee. In this cross, all of the offsprings will have a heterozygous genotype, Ee because gametes E and e will be produced respectively by each parent.
Hence, since all of the offsprings will have an Ee genotype, it means 100% of their offsprings will have Ee (HETEROZYGOUS).
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