SAT : asked on shanicar33500
 28.12.2021

find the range standard deviation and variance of 1.1,5.2,3.6,5.0,4.8,1.8,2.2,5.2,1.5 ,0.8

. 6

Faq

Mathematics
Step-by-step answer
P Answered by Master

1) Range = Max-Min= 5.2-0.8=4.4

The sample variance can be calculated with this formula:

s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

And we got:

s^2 = 3.324

And the sample deviation would be:

s= \sqrt{3.324}= 1.823

2) \bar X =\frac{\sum_{i=1}^n X_i}{n}

And we got:

\bar X= 3.12

The median since we have 10 values would be the average between the 5th and 6th observations from the dataset ordered and we got:

Median= \frac{2.2+3.6}{2}= 2.9

And finally the mode would be the most repated value and we got:

Mode= 5.2

3) Median

So then we can conclude that probably this distirbution is left skewed

Step-by-step explanation:

We have the following dataset given:

1.1, 5.2, 3.6, 5.0, 4.8, 1.8, 2.2, 5.2, 1.5, 0.8

Part 1

We can order the dataset on increasing way and we got:

0.8 1.1 1.5 1.8 2.2 3.6 4.8 5.0 5.2 5.2

The range can be calculated like this:

Range = Max-Min= 5.2-0.8=4.4

The sample variance can be calculated with this formula:

s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

And we got:

s^2 = 3.324

And the sample deviation would be:

s= \sqrt{3.324}= 1.823

Part 2

The mean can be calculated with this formula:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

And we got:

\bar X= 3.12

The median since we have 10 values would be the average between the 5th and 6th observations from the dataset ordered and we got:

Median= \frac{2.2+3.6}{2}= 2.9

And finally the mode would be the most repated value and we got:

Mode= 5.2

Part 3

For this case we know that:

Median

So then we can conclude that probably this distirbution is left skewed

Mathematics
Step-by-step answer
P Answered by Master

1) Range = Max-Min= 5.2-0.8=4.4

The sample variance can be calculated with this formula:

s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

And we got:

s^2 = 3.324

And the sample deviation would be:

s= \sqrt{3.324}= 1.823

2) \bar X =\frac{\sum_{i=1}^n X_i}{n}

And we got:

\bar X= 3.12

The median since we have 10 values would be the average between the 5th and 6th observations from the dataset ordered and we got:

Median= \frac{2.2+3.6}{2}= 2.9

And finally the mode would be the most repated value and we got:

Mode= 5.2

3) Median

So then we can conclude that probably this distirbution is left skewed

Step-by-step explanation:

We have the following dataset given:

1.1, 5.2, 3.6, 5.0, 4.8, 1.8, 2.2, 5.2, 1.5, 0.8

Part 1

We can order the dataset on increasing way and we got:

0.8 1.1 1.5 1.8 2.2 3.6 4.8 5.0 5.2 5.2

The range can be calculated like this:

Range = Max-Min= 5.2-0.8=4.4

The sample variance can be calculated with this formula:

s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

And we got:

s^2 = 3.324

And the sample deviation would be:

s= \sqrt{3.324}= 1.823

Part 2

The mean can be calculated with this formula:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

And we got:

\bar X= 3.12

The median since we have 10 values would be the average between the 5th and 6th observations from the dataset ordered and we got:

Median= \frac{2.2+3.6}{2}= 2.9

And finally the mode would be the most repated value and we got:

Mode= 5.2

Part 3

For this case we know that:

Median

So then we can conclude that probably this distirbution is left skewed

Mathematics
Step-by-step answer
P Answered by PhD

1)  Normal distribution A distribution that takes on the shape of                                                                                               a bell curve.

2) Standard Normal distributionA normal distribution with a mean                                                                                                                                                                                            0  and a standard deviation of 1.

3) deviation  difference between any value and the mean of

                                               the  set.

4) frequency distribution organizes data into categories called

                                                     classes.

5) range difference between the smallest term in the data and      

                          the  largest term in the data set.

6) standard deviation square root of variance.

7) Variance square of the standard deviation.

8) z-score deviation of a value x from the mean of the sample

                                    divided by the standard deviation.

Mathematics
Step-by-step answer
P Answered by PhD

1)  Normal distribution A distribution that takes on the shape of                                                                                               a bell curve.

2) Standard Normal distributionA normal distribution with a mean                                                                                                                                                                                            0  and a standard deviation of 1.

3) deviation  difference between any value and the mean of

                                               the  set.

4) frequency distribution organizes data into categories called

                                                     classes.

5) range difference between the smallest term in the data and      

                          the  largest term in the data set.

6) standard deviation square root of variance.

7) Variance square of the standard deviation.

8) z-score deviation of a value x from the mean of the sample

                                    divided by the standard deviation.

SAT
Step-by-step answer
P Answered by PhD
The graph tells us that Ralph's performance has gradually been getting worse, Jill's performance has been improving over time, Tina has overall been stable and good in her performance, that Ed's performance has been erratic and that Sam's performance has been inconsistent but improving.
SAT
Step-by-step answer
P Answered by Master

B. use a familiar concept to communicate an idea

Explanation:

Basically, Passage 2 states the hypothesis that spotted green pigeon is a descendant of an island hopping bird and throughot the article, it provides evidence for this statement.

The discovery is that, since the DNA found in a green pigeon's feather was fragmented and they had to analyze only parts of it, the bird had an unique sets of DNA which distinguish it from other members of the pigeon species.

These analyzed parts of DNA are refered to as "mini barcodes".

Since target audience for this article might not be fully familiar with the concept and functions od DNA, researchers used a more familiar concept of barcodes as an analogy to communicate their idea and explain their discovery.

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