1-Brown eyes (B) are dominant to blue eyes (b). Straight hair (H) is dominant to curly hair (h). Free earlobes (E) are dominant to attached earlobes (e). If individual one who has the genotype BbHhEe is crossed with individual two who has the genotype bbhhEe, what is the probability that their offspring has brown eyes, straight hair, and attached earlobes?(I asked last time but I didn't get a serious answer, please make your answers as one percentage.)

The correct answer would be - 1/16 or 6.25% is the probability that their offspring has brown eyes, straight hair, and attached earlobes

Explanation:

In this question, it is given that-

1. Brown eyes (B) are dominant to blue eyes (b)

2. Straight hair (H) is dominant to curly hair (h)

3. Free earlobes (E) are dominant to attached earlobes (e)

Now the cross between BbHhEe (Brown eyes-straight hair-free earlobe) with bbhhEe (blue eyes-curly hair-free earlobe) takes place.

Gametes will be -

BbHhEe - BHE, BhE, Bhe, BHe, bHE, bHe, bhE, bhe

bbhhEe - bhE, bhe

cross would be -

            BHE      BhE       Bhe        BHe        bHE        bHe        bhE       bhe

bhE   BbHhEE  BbhhEE BbhhEe BbHhEe bbHhEE  bbHhEe bbhhEE bbhhEe

bhe   BbHhEe  BbhhEe Bbhhee BbHhee bbHhEe  bbHhEe bbhhEe bbhhee

By the Punnett cross, we get only one out of 16 offspring with brown eyes, straight hair, and attached earlobes

Thus, the correct answer would be - 1/16 or 6.25% is the probability that their offspring has brown eyes, straight hair, and attached earlobes

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