The correct answer would be - 1/16 or 6.25% is the probability that their offspring has brown eyes, straight hair, and attached earlobes
Explanation:
In this question, it is given that-
1. Brown eyes (B) are dominant to blue eyes (b)
2. Straight hair (H) is dominant to curly hair (h)
3. Free earlobes (E) are dominant to attached earlobes (e)
Now the cross between BbHhEe (Brown eyes-straight hair-free earlobe) with bbhhEe (blue eyes-curly hair-free earlobe) takes place.
Gametes will be -
BbHhEe - BHE, BhE, Bhe, BHe, bHE, bHe, bhE, bhe
bbhhEe - bhE, bhe
cross would be -
BHE BhE Bhe BHe bHE bHe bhE bhe
bhE BbHhEE BbhhEE BbhhEe BbHhEe bbHhEE bbHhEe bbhhEE bbhhEe
bhe BbHhEe BbhhEe Bbhhee BbHhee bbHhEe bbHhEe bbhhEe bbhhee
By the Punnett cross, we get only one out of 16 offspring with brown eyes, straight hair, and attached earlobes
Thus, the correct answer would be - 1/16 or 6.25% is the probability that their offspring has brown eyes, straight hair, and attached earlobes