15.07.2020

# You cross two unicorns, one that is Rr / Ss with an individual that is rr/ss. The resulting progeny are in the following proportions: 7 Rr/Ss, 35 Rr/ss, 32 rr/Ss, 6 rr/ss. If you wanted to test whether these two loci were independently assorting, what would be the number of expected genotypes to compare your observed to?

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09.07.2023, solved by verified expert

Dihybrid crosses

Crossing RrSs with rrss will yield offspring with the following phenotype according to the attached Punnet's square:

Total offspring = 7+35+32+6 =

Thus instead of 7:35:32:6, it will be 1:1:1:1 if the two loci were independently assorting. The number of expected genotypes would be 20 RrSs, 20 Rrss, 20 rrSs and 20 rrss

More on independent assortment can be found here:

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Biology

Dihybrid crosses

Crossing RrSs with rrss will yield offspring with the following phenotype according to the attached Punnet's square:

Total offspring = 7+35+32+6 =

Thus instead of 7:35:32:6, it will be 1:1:1:1 if the two loci were independently assorting. The number of expected genotypes would be 20 RrSs, 20 Rrss, 20 rrSs and 20 rrss

More on independent assortment can be found here:

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