Biology : asked on masad
 15.07.2020

You cross two unicorns, one that is Rr / Ss with an individual that is rr/ss. The resulting progeny are in the following proportions: 7 Rr/Ss, 35 Rr/ss, 32 rr/Ss, 6 rr/ss. If you wanted to test whether these two loci were independently assorting, what would be the number of expected genotypes to compare your observed to?

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09.07.2023, solved by verified expert
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The number of expected genotypes to compare the observation to would be 20 RrSs, 20 Rrss, 20 rrSs and 20 rrss

Dihybrid crosses

Crossing RrSs with rrss will yield offspring with the following phenotype according to the attached Punnet's square:

4RrSs

4Rrss

4rrSs

4rrss

Total offspring = 7+35+32+6 =

Thus instead of 7:35:32:6, it will be 1:1:1:1 if the two loci were independently assorting. The number of expected genotypes would be 20 RrSs, 20 Rrss, 20 rrSs and 20 rrss

More on independent assortment can be found here:


You cross two unicorns, one that is Rr / Ss with, №18010698, 15.07.2020 12:50
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The number of expected genotypes to compare the observation to would be 20 RrSs, 20 Rrss, 20 rrSs and 20 rrss

Dihybrid crosses

Crossing RrSs with rrss will yield offspring with the following phenotype according to the attached Punnet's square:

4RrSs

4Rrss

4rrSs

4rrss

Total offspring = 7+35+32+6 =

Thus instead of 7:35:32:6, it will be 1:1:1:1 if the two loci were independently assorting. The number of expected genotypes would be 20 RrSs, 20 Rrss, 20 rrSs and 20 rrss

More on independent assortment can be found here:


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