Chemistry: How many MOLECULES of calcium chloride are in 3CaCl2

How many MOLECULES of calcium chloride are in, №12567886, 12.03.2022 14:23

Chemistry

Moles/Mass/Molecules Practice Problem Worksheet Complete the following problems: 1. Convert 11.03 moles of calcium nitrate to grams. 2. How many molecules are contained in 103.4g of sulfuric acid? 3. 3.25 x 1024 molecules of dinitrogen pentoxide would be how many moles? 4. What would be the mass of 9.03 x 1021 molecules of hydrobromic acid? 5. A sample of iron (III) chloride has a mass of 26.29g. How many moles would this be?

Step-by-step answer

P Answered by PhD

8

1. Converting 11.03 moles of calcium nitrate to grams gives 1,809.89 grams.

2. The number of molecules that are contained in 103.4 g of sulfuric acid is $6.35 \times 10^{23}$ molecules.

3. Converting $3.25 \times 10^{24}$ molecules of dinitrogen pentoxide to moles is equal to 5.3987 moles.

4. The mass of $9.03 \times 10^{21}$ molecules of hydrobromic acid is 1.2135 grams.

5. The number of moles contained in 26.29 g of iron (III) chloride is 0.1621 moles.

Given the following data:

Number of moles of calcium nitrate = 11.03 molesMass of sulfuric acid = 103.4 gramsNumber of molecules of dinitrogen pentoxide = $3.25 \times 10^{24 }$ Number of molecules of hydrobromic acid = $9.03 \times 10^{21 }$ Mass of iron (III) chloride = 26.29 grams

Scientific data:

The molar mass of calcium nitrate = 46.07 g/mol.The molar mass of sulfuric acid = 98.079 g/mol.The molar mass of hydrobromic acid = 80.91 g/mol.The molar mass of iron (III) chloride = 162.2 g/mol.Avogadro's number = $6.02 \times 10^{23}$

1. To convert 11.03 moles of calcium nitrate to grams:

$Mass = Number\;of\;moles \times molar\;mass\\\\Mass = 11.03 \times 164.088$

Mass of calcium nitrate = 1,809.89 grams.

2. To calculate how many molecules are contained in 103.4 g of sulfuric acid:

First of all, we would determine the number of moles contained in 103.4 g of sulfuric acid.

$Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{103.4}{98.079}$

Number of moles = 1.0543 moles

By stoichiometry:

1 mole of sulfuric acid = $6.02 \times 10^{23}$ molecules

1.0543 mole of sulfuric acid = X molecules

Cross-multiplying, we have:

$X = 1.0543 \times 6.02 \times 10^{23}$

X = $6.35 \times 10^{23}$ molecules

3. To convert $3.25 \times 10^{24}$ molecules of dinitrogen pentoxide to moles:

By stoichiometry:

1 mole of dinitrogen pentoxide = $6.02 \times 10^{23}$ molecules

X mole of dinitrogen pentoxide = $3.25 \times 10^{24}$ molecules

Cross-multiplying, we have:

$X=\frac{3.25 \times 10^{24}}{6.02 \times 10^{23}}$

X = 5.3987 moles

4. To calculate the mass of $9.03 \times 10^{21}$ molecules of hydrobromic acid:

First of all, we would determine the number of moles contained in $9.03 \times 10^{21}$ molecules of hydrobromic acid.

By stoichiometry:

1 mole of hydrobromic acid = $6.02 \times 10^{23}$ molecules

X mole of hydrobromic acid = $9.03 \times 10^{21}$ molecules

Cross-multiplying, we have:

$X=\frac{9.03 \times 10^{21} }{6.02 \times 10^{23}}$

X = 0.015 moles

$Mass = Number\;of\;moles \times molar\;mass\\\\Mass = 0.015 \times 80.91$

Mass of hydrobromic acid = 1.2135 grams.

5. To calculate the number of moles contained in 26.29 g of iron (III) chloride:

$Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{26.29}{162.2}$

Number of moles = 0.1621 moles.

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Chemistry

Moles/Mass/Molecules Practice Problem Worksheet Complete the following problems: 1. Convert 11.03 moles of calcium nitrate to grams. 2. How many molecules are contained in 103.4g of sulfuric acid? 3. 3.25 x 1024 molecules of dinitrogen pentoxide would be how many moles? 4. What would be the mass of 9.03 x 1021 molecules of hydrobromic acid? 5. A sample of iron (III) chloride has a mass of 26.29g. How many moles would this be?

Step-by-step answer

P Answered by PhD

8

1. Converting 11.03 moles of calcium nitrate to grams gives 1,809.89 grams.

2. The number of molecules that are contained in 103.4 g of sulfuric acid is $6.35 \times 10^{23}$ molecules.

3. Converting $3.25 \times 10^{24}$ molecules of dinitrogen pentoxide to moles is equal to 5.3987 moles.

4. The mass of $9.03 \times 10^{21}$ molecules of hydrobromic acid is 1.2135 grams.

5. The number of moles contained in 26.29 g of iron (III) chloride is 0.1621 moles.

Given the following data:

Number of moles of calcium nitrate = 11.03 molesMass of sulfuric acid = 103.4 gramsNumber of molecules of dinitrogen pentoxide = $3.25 \times 10^{24 }$ Number of molecules of hydrobromic acid = $9.03 \times 10^{21 }$ Mass of iron (III) chloride = 26.29 grams

Scientific data:

The molar mass of calcium nitrate = 46.07 g/mol.The molar mass of sulfuric acid = 98.079 g/mol.The molar mass of hydrobromic acid = 80.91 g/mol.The molar mass of iron (III) chloride = 162.2 g/mol.Avogadro's number = $6.02 \times 10^{23}$

1. To convert 11.03 moles of calcium nitrate to grams:

$Mass = Number\;of\;moles \times molar\;mass\\\\Mass = 11.03 \times 164.088$

Mass of calcium nitrate = 1,809.89 grams.

2. To calculate how many molecules are contained in 103.4 g of sulfuric acid:

First of all, we would determine the number of moles contained in 103.4 g of sulfuric acid.

$Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{103.4}{98.079}$

Number of moles = 1.0543 moles

By stoichiometry:

1 mole of sulfuric acid = $6.02 \times 10^{23}$ molecules

1.0543 mole of sulfuric acid = X molecules

Cross-multiplying, we have:

$X = 1.0543 \times 6.02 \times 10^{23}$

X = $6.35 \times 10^{23}$ molecules

3. To convert $3.25 \times 10^{24}$ molecules of dinitrogen pentoxide to moles:

By stoichiometry:

1 mole of dinitrogen pentoxide = $6.02 \times 10^{23}$ molecules

X mole of dinitrogen pentoxide = $3.25 \times 10^{24}$ molecules

Cross-multiplying, we have:

$X=\frac{3.25 \times 10^{24}}{6.02 \times 10^{23}}$

X = 5.3987 moles

4. To calculate the mass of $9.03 \times 10^{21}$ molecules of hydrobromic acid:

First of all, we would determine the number of moles contained in $9.03 \times 10^{21}$ molecules of hydrobromic acid.

By stoichiometry:

1 mole of hydrobromic acid = $6.02 \times 10^{23}$ molecules

X mole of hydrobromic acid = $9.03 \times 10^{21}$ molecules

Cross-multiplying, we have:

$X=\frac{9.03 \times 10^{21} }{6.02 \times 10^{23}}$

X = 0.015 moles

$Mass = Number\;of\;moles \times molar\;mass\\\\Mass = 0.015 \times 80.91$

Mass of hydrobromic acid = 1.2135 grams.

5. To calculate the number of moles contained in 26.29 g of iron (III) chloride:

$Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{26.29}{162.2}$

Number of moles = 0.1621 moles.

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Chemistry

How many molecules are in 95.75 g of calcium chloride?

Step-by-step answer

P Answered by PhD

5.195 x 10²³ molecules ≅ 5.2 x 10²³ molecules.

Explanation:

It is known that every 1.0 mole of a molecule contains Avogadro's number of molecules (NA = 6.022 x 10²³).We need to calculate the no. of moles in 95.75 g of CaCl₂ using the relation:

n = mass/molar mass = (95.75 g)/(110.98 g/mol) = 0.86 mol.

Using cross multiplication:

1.0 mole of CaCl₂ contains → 6.022 x 10²³ molecules.

0.86 mole of CaCl₂ contains → ??? molecules.

∴ 95.75 g of CaCl₂ (0.86 mole) contain = (0.86 mol)(6.022 x 10²³) = 5.195 x 10²³ molecules ≅ 5.2 x 10²³ molecules.

Chemistry

How many molecules are in 95.75 g of calcium chloride?

Step-by-step answer

P Answered by PhD

5.195 x 10²³ molecules ≅ 5.2 x 10²³ molecules.

Explanation:

It is known that every 1.0 mole of a molecule contains Avogadro's number of molecules (NA = 6.022 x 10²³).We need to calculate the no. of moles in 95.75 g of CaCl₂ using the relation:

n = mass/molar mass = (95.75 g)/(110.98 g/mol) = 0.86 mol.

Using cross multiplication:

1.0 mole of CaCl₂ contains → 6.022 x 10²³ molecules.

0.86 mole of CaCl₂ contains → ??? molecules.

∴ 95.75 g of CaCl₂ (0.86 mole) contain = (0.86 mol)(6.022 x 10²³) = 5.195 x 10²³ molecules ≅ 5.2 x 10²³ molecules.

Biology

Question 2 options: which is an example of an ionic bond? calcium gives an electron to chlorine to form a stable bond ions in a bar of pure iron are surrounded by many valence electrons there are less than 16 valence electrons in two chlorine atoms. question 3 options: which is an example of a covalent bond? a.ions in a bar of pure iron are surrounded by a large number of valence electrons b. silver ions are surrounded by a sea of valence electrons c.some electrons in carbon dioxide function as valence electrons in both carbon and oxygen question

Step-by-step answer

P Answered by Master

4

For #1 The Answer is (A)Calcium gives an electron to chlorine to form a stable bond.

Hope that helps :D

Biology

Question 2 options: which is an example of an ionic bond? calcium gives an electron to chlorine to form a stable bond ions in a bar of pure iron are surrounded by many valence electrons there are less than 16 valence electrons in two chlorine atoms. question 3 options: which is an example of a covalent bond? a.ions in a bar of pure iron are surrounded by a large number of valence electrons b. silver ions are surrounded by a sea of valence electrons c.some electrons in carbon dioxide function as valence electrons in both carbon and oxygen question

Step-by-step answer

P Answered by Specialist

4

For #1 The Answer is (A)Calcium gives an electron to chlorine to form a stable bond.

Hope that helps :D

Chemistry

How many moles of HF are in 30.mL of 0.15MHF(aq) ?

Step-by-step answer

P Answered by Master

Answer: 0.0045 mol
Explanation: Convert 30 ml to l: 30 mL = 0.03 L
Molarity = mol/l
mol = molarity * L
mol = 0.15 * 0.03 = 0.0045 mol
Answer: 0.0045 mol
Explanation: Convert 30 ml to l: 30 mL = 0.03 L
Molarity = mol/l
mol = molarit

Chemistry

What elements combined with Strontium, St, in a 1:1 ratio?

Step-by-step answer

P Answered by PhD

Answer: chalcogens.
Explanation: Strontium is an alkaline earth metal, it always exhibits a degree of oxidation in its compounds +2.
Chalcogens are a group of 6 chemical elements (oxygen O, sulfur S, selenium se, tellurium te, polonium Po) that have an oxidation state of -2 => Chalcogens will combine with strontium in a ratio of 1:1.

Chemistry

Fiona claims that the diagram below shows simple machines, but Chad claims that it shows a compound machine. A man pushes a shopping cart up a ramp. Which statement best explains who is correct? Fiona is correct because less than three machines are shown in the diagram. Fiona is correct because the diagram shows two individual simple machines. Chad is correct because more than one machine is shown in the diagram. Chad is correct because the diagram shows two simple machines doing a job.

Step-by-step answer

P Answered by Specialist

Answer: b. Fiona is correct because the diagram shows two individual simple machines.

Explanation:
A mechanical device using which we can change the direction or magnitude of force applied is known as simple machine.
For example, in the given diagram there are two individual simple machines.
The machine helps in changing the direction or magnitude of force applied by the man. As a result, it becomes easy for him to carry different things easily from one place to another.
Thus, we can conclude that the statement Fiona is correct because the diagram shows two individual simple machines, is correct.
Answer: b. Fiona is correct because the diagram shows two individual simple machines.

Explanation

Chemistry

Based on the equation, how many grams of Br2 are required to react completely with 29.2 grams of AlCl3 (5 points)? 2AlCl3 + 3Br2 → 2AlBr3 + 3Cl2

Step-by-step answer

P Answered by PhD

1

Answer:

52.6 gram

Step-by-step explanation:

It is clear by the equation 2(27+3×35.5)= 267 gm of AlCl3 reacts with 6× 80 = 480 gm of Br2 . So 29.2 gm reacts = 480× 29.2/267= 52.6 gm

How many MOLECULES of calcium chloride are in 3CaCl2

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