Chemistry : asked on marlesly87
 21.10.2022

At STP, which volume is made up of 60.0g atoms

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24.01.2022, solved by verified expert
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Given:

At Standard temperature pressure, (STP)

T=273 K.

P=1 atm.

The volume occupied by  1 mol of atoms = 22.4 L

As the gases contain different moles for different masses therefore the volume of the 60 g of atoms depends upon the gas of which the atoms are part.

                                       

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Given:

The pressure, (P)= 1 atm.

The temperature, (T)=273 K

At STP 1 mol of all the gases occupies volume = 22.4 L.

Therefore,

The 60 g atom of different gases will occupy different volumes. 

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Faq

Chemistry
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P Answered by Specialist

Standard pressure = 1.00 atm, so plug in to ideal gas. (1.00atm)(2.50L) ... How many moles of nitrogen gas will occupy a volume of 150 L at STP? n=pr 11.00atm) (150 ... A sample of neon is collected at 2.70 atm and 12.0°c. It has a volume of.

Explanation:

Chemistry
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P Answered by Specialist

Standard pressure = 1.00 atm, so plug in to ideal gas. (1.00atm)(2.50L) ... How many moles of nitrogen gas will occupy a volume of 150 L at STP? n=pr 11.00atm) (150 ... A sample of neon is collected at 2.70 atm and 12.0°c. It has a volume of.

Explanation:

English
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P Answered by PhD
Okay. So. First of all, rlly nice story =D I'm glad you got what you wanted. Now, to the point.. at first, I started to list every point where i thought you can change, but to be honest, and i mean no offense when i say this, but i think itll take me a very long time and a printed out version to mark it up so i think ill jjust give u a couple of tips. I hope they help. 
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-dont use the same word over and over again. try not to use it more than twice in one paragraph, it becomes repetitive, and a little annoying to read. An example: 'That battle was cemented in my head, all I could do was think about that battle.', I would change the second "battle" to "it"... you can do the same to other sentences, just look up synonyms and replce them, itll mean the same thing.
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- the tenses seem to change throughout the story you start out correctly. in the past tense, and then u use a verb in the future tense, such as "will happen" 
- don't add details you dont need or dont support the main idea... like the part about forgetting your brother. its just a side detail. or u can change how u introduce that detail. instead of the two or three sentences about forgetting him, u can just write " I was so anxious and excited to find out what the results were that i forgot to pick up my younger brother on my way back home from school, and ended up having to go all the way back to get him, prolonging the suspense."
If you want more specific details on where to change exactly what, i suggest you go to someone in person, they might be able to help you more. Best of luck! 
English
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P Answered by PhD
Okay. So. First of all, rlly nice story =D I'm glad you got what you wanted. Now, to the point.. at first, I started to list every point where i thought you can change, but to be honest, and i mean no offense when i say this, but i think itll take me a very long time and a printed out version to mark it up so i think ill jjust give u a couple of tips. I hope they help. 
- you dont exactly have  any main idea going... only after reading the entire thing did i understand what "the battle" was and why you were anxious to get the results. you should clarify in the beginning what it is youre talking abt. a sentence like " Sixth grade had just started, and already I had begun to lose focus. My brain seemed to constantly drift towards other, more important things; like the upcoming custody battle between my parents over my brother and I."
-dont use the same word over and over again. try not to use it more than twice in one paragraph, it becomes repetitive, and a little annoying to read. An example: 'That battle was cemented in my head, all I could do was think about that battle.', I would change the second "battle" to "it"... you can do the same to other sentences, just look up synonyms and replce them, itll mean the same thing.
- Also, words like "socializing" might be too strong a word to use you can put 'talking' lol... its important to remember that you dont always have to use big words, and especially  when youre writing a personal narrative, you should stick to ones you use on a day to day basis... save the big ones for formal essays :)
- the tenses seem to change throughout the story you start out correctly. in the past tense, and then u use a verb in the future tense, such as "will happen" 
- don't add details you dont need or dont support the main idea... like the part about forgetting your brother. its just a side detail. or u can change how u introduce that detail. instead of the two or three sentences about forgetting him, u can just write " I was so anxious and excited to find out what the results were that i forgot to pick up my younger brother on my way back home from school, and ended up having to go all the way back to get him, prolonging the suspense."
If you want more specific details on where to change exactly what, i suggest you go to someone in person, they might be able to help you more. Best of luck! 
Chemistry
Step-by-step answer
P Answered by Specialist
The formula of ozone is O3.
Hope this helps~
Chemistry
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P Answered by PhD
34 g/mol if using the post 1981 definition of STP 32 g/mol if using the pre 1982 definition of STP One minor complication is that the definition of STP changed in 1982 and some text books still use the old definition. So for this problem, I'll be giving two answers, but showing the work for only one of the results. Pre 1982, STP was defined as 273.15 K at exactly 1 atmosphere (101325. Pascals) Post 1981, STP was defined as 273.15 K at exactly 100 kPa (100000 Pascals) The result of this difference is that the volume of 1 mole of a gas at STP differs. Pre 1982, 1 mole of gas at STP has a volume of 22.414 liters. Post 1981, 1 mole of gas at STP has a volume of 22.71098 liters. First, determine the number of moles of gas molecules we have. 19.44 l / 22.71098 l/mol = 0.85597363 mol Now determine how many moles of Ar, and Ne we have. Look up the atomic weights. Atomic weight Argon = 39.948 Atomic weight Neon = 20.1797 Moles Argon = 8.2 / 39.948 = 0.205266847 mol Moles Neon = 8.2 / 20.1797 = 0.406348955 mol Calculate the number of moles of unknown gas by subtracting the number of moles of argon and neon we have from the number of moles of gas in total. So 0.85597363 mol - 0.205266847 mol - 0.406348955 mol = 0.244357829 mol Now that we know how many moles of the unknown gas we have, we can simply divide the mass by the number of moles, so 8.2 g / 0.244357829 mol = 33.55734514 g/mol Rounding to 2 significant figures gives a molar mass of 34 g/mol and since there isn't any element with a atomic weight of 17, I suspect that the textbook you're using is using the pre-1982 definition of STP. So repeating the calculations above with a volume of 22.414 liters per mole (pre-1982 definition of STP), the newly calculated molar mass becomes 32 g/mol which is a nice match for the unknown gas being oxygen. The differences using the older standard are: 19.44 l / 22.414 l/mol = 0.867315071 mol ; Number of moles in the volume of 19.44 l 0.867315071 mol - 0.205266847 mol - 0.406348955 mol = 0.255699269 mol ; moles of unknown gas. 8.2 g / 0.255699269 mol = 32.06892229 g/mol ; Molar mass of unknown gas.
Chemistry
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P Answered by Specialist

Molar mass of the unknown gas is 73.153 g/mol.

Explanation:

Given: Mass of each gas = 8.7 g

Volume = 17.28 L

Let us assume that the molar mass of gas is m g/mol.

Molar mass of Ar is 40 g/mol and Ne is 20 g/mol.

Hence, total moles of each gas are as follows.

(\frac{8.7}{40} + \frac{8.7}{20} + \frac{8.7}{m}) mol

At STP, the total volume of these gases is as follows.

(\frac{8.7}{40} + \frac{8.7}{20} + \frac{8.7}{m}) mol \times 22.4 L = 17.28 L\\(\frac{8.7}{40} + \frac{8.7}{20})22.4 L + \frac{8.7}{m} \times 22.4 L = 17.28 L\\14.616 + \frac{8.7}{m} \times 22.4 L = 17.28 L\\\frac{8.7}{m} \times 22.4 L = (17.28 L - 14.616)\\\frac{8.7}{m} \times 22.4 L = 2.664 \\m = 73.153 g/mol

Thus, we can conclude that molar mass of the unknown gas is 73.153 g/mol.

Chemistry
Step-by-step answer
P Answered by Master

The molar mass of unknown diatomic gas is 38 grams

Explanation:

At STP:

The temperature and pressure conditions are 273 K and 1 atm respectively.

To calculate the number of moles, we use the equation given by ideal gas equation:

PV = nRT

P = Pressure of the gas  = 1.00 atm

V = Volume of the gas = 12.88 L

n = number of moles of mixture = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = Temperature of the gas

Putting values in above equation, we get:

1.00atm\times 12.88L=n\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 273K\\\\n=\frac{1.00\times 12.88}{0.0821\times 273}=0.575mol

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

For Argon:

Given mass of argon = 5.7 g

Molar mass of argon = 39.95 g/mol

Putting values in equation 1, we get:

\text{Moles of argon}=\frac{5.7g}{39.95g/mol}=0.143mol

For neon:

Given mass of neon = 5.7 g

Molar mass of neon = 20.2 g/mol

Putting values in equation 1, we get:

\text{Moles of neon}=\frac{5.7g}{20.2g/mol}=0.282mol

Moles of unknown diatomic gas = [0.575 - (0.143 + 0.282)] = 0.150

Now, calculating the molar mass of unknown diatomic gas from equation 1, we get:

Given mass of unknown diatomic gas = 5.7 g

Moles of unknown diatomic gas = 0.150 moles

Putting values in equation 1, we get:

0.150mol=\frac{5.7g}{\text{Molar mass of unknown diatomic gas}}\\\\\text{Molar mass of unknown diatomic gas}=\frac{5.7g}{0.150mol}=38g

Hence, the molar mass of unknown diatomic gas is 38 grams

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