Answer:
CheckedStep-by-step explanation:
Average atomic mass
= f1M1 + f2M2
fnMn where, f is the fraction representing the natural abundance of the isotope and M is the mass number (weight) of the isotope.
According to question average atomic mass of iron is:-
f = 15.2℅ = 0.152 ( M=55)
84.8%= 0.848 (M= 56)
According to formula written above
= (0.152 ×55) + (0.848×56)
= 8.36+47.88
= 55.85 amu