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Chemistry

Step-by-step answer

glycoproteins

Explanation:

A positive reaction for Molisch's test is given by almost all carbohydrates (exceptions include tetroses & trioses). It can be noted that even some glycoproteins and nucleic acids give positive results for this test (since they tend to undergo hydrolysis when exposed to strong mineral acids and form monosaccharides).

Chemistry

Step-by-step answer

**Answer:**

Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.

**Explanation:**

In this case, you know:

P= 0.884 atm

V= ?

n= 0.857 moles (where 28 g/mole is the molar mass of N₂, that is, the amount of mass that the substance contains in one mole.)

R=0.082

T= 328 K

Replacing in the ideal gas law:

0.884 atm×V= 0.857 moles× 0.082 ×328 K

Solving:

*V= 26.07 L*

The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.

Chemistry

Step-by-step answer

15 moles.Explanation:Hello,In this case, the undergoing chemical reaction is:Clearly, since carbon and oxygen are in a 1:1 molar ratio, 15 moles of carbon will completely react with 15 moles of oxygen, therefore 15 moles of oxygen remain as leftovers. In such a way, since carbon and carbon dioxide are also in a 1:1 molar ratio, the theoretical yield of carbon dioxide is 15 moles based on the stoichiometry:Best regards.

Chemistry

Step-by-step answer

Answer: 25 g

Explanation: Given:

Original amount (N₀) = 100 g

Number of half-lives (n) = 11460/5730 = 2

Amount remaining (N) = ?

N = 1/2ⁿ × N₀

N = 1/2^2 × 100

N = 0.25 × 100

N = 25 g

Explanation: Given:

Original amount (N₀) = 100 g

Number of half-lives (n) = 11460/5730 = 2

Amount remaining (N) = ?

N = 1/2ⁿ × N₀

N = 1/2^2 × 100

N = 0.25 × 100

N = 25 g

Chemistry

Step-by-step answer

Answer: 7.8125 g

Explanation: Given:

Original amount (N₀) = 500 g

Number of half-lives (n) = 9612/1602 = 6

Amount remaining (N) = ?

N = 1/2ⁿ × N₀

N = 1/2^6 × 500

N = 0.015625 × 500

N = 7.8125 g

Explanation: Given:

Original amount (N₀) = 500 g

Number of half-lives (n) = 9612/1602 = 6

Amount remaining (N) = ?

N = 1/2ⁿ × N₀

N = 1/2^6 × 500

N = 0.015625 × 500

N = 7.8125 g

Chemistry

Step-by-step answer

Answer: The product formed is potassium chloride.

Explanation:

Precipitation reaction is defined as the chemical reaction in which an insoluble salt is formed when two solutions are mixed containing soluble substances. The insoluble salt settles down at the bottom of the reaction mixture.

The chemical equation for the reaction of potassium phosphate and magnesium chloride follows (look at the picture)

2 moles of aqueous solution of potassium phosphate reacts with 3 moles of aqueous solution of magnesium chloride to produce 1 mole of solid magnesium phosphate and 6 moles of aqueous solution of potassium chloride.

Explanation:

Precipitation reaction is defined as the chemical reaction in which an insoluble salt is formed when two solutions are mixed containing soluble substances. The insoluble salt settles down at the bottom of the reaction mixture.

The chemical equation for the reaction of potassium phosphate and magnesium chloride follows (look at the picture)

2 moles of aqueous solution of potassium phosphate reacts with 3 moles of aqueous solution of magnesium chloride to produce 1 mole of solid magnesium phosphate and 6 moles of aqueous solution of potassium chloride.

Chemistry

Step-by-step answer

Answer: B. carbon tetrachloride, CCI4

Explanation: The other options are incorrect. Let's write the correct formulas:

A. Diarsenic pentoxide - As2O5

C. Sodium dichromate - Na2Cr2O7

D. magnesium phosphide - Mg3P2

Explanation: The other options are incorrect. Let's write the correct formulas:

A. Diarsenic pentoxide - As2O5

C. Sodium dichromate - Na2Cr2O7

D. magnesium phosphide - Mg3P2

Chemistry

Step-by-step answer

Answer: a. basic

b. basic

c. acidic

d. neutral

Explanation: Acids and bases can be classified in terms of hydrogen ions or hydroxide ions, or in terms of electron pairs. (look at the picture)

Let us note that from the pH scale, a pH of;

0 - 6.9 is acidic

7 is neutral

8 - 14 is basic

But pH= - log [H^+]

pOH = -log [OH^-]

Then;

pH + pOH = 14

Hence;

pH = 14 - pOH

a. [H+] = 6.0 x 10-10M

pH= 9.22 is basic

b. [OH-] = 30 × 10-2M

pH = 13.5 is basic

C. IH+1 = 20× 10-7M

pH = 0.56 is acidic

d. [OH-] = 1.0 x 10-7M

pH = 7 is neutral

b. basic

c. acidic

d. neutral

Explanation: Acids and bases can be classified in terms of hydrogen ions or hydroxide ions, or in terms of electron pairs. (look at the picture)

Let us note that from the pH scale, a pH of;

0 - 6.9 is acidic

7 is neutral

8 - 14 is basic

But pH= - log [H^+]

pOH = -log [OH^-]

Then;

pH + pOH = 14

Hence;

pH = 14 - pOH

a. [H+] = 6.0 x 10-10M

pH= 9.22 is basic

b. [OH-] = 30 × 10-2M

pH = 13.5 is basic

C. IH+1 = 20× 10-7M

pH = 0.56 is acidic

d. [OH-] = 1.0 x 10-7M

pH = 7 is neutral

Chemistry

Step-by-step answer

Answer: 306 L

Explanation: Using the ideal gas law,

PV = nRT

where R = 0.08206 L•atm/(mol•°K), solving for n gives

n = PV/(RT)

n = (845 mmHg) (270 L) / ((0.08206 L•atm/(mol•°K)) (24 °C))

Convert the given temperature to °K and the given pressure to atm:

24 °C = (273.15 + 24) °K ≈ 297.2 °K

(845 mmHg) × (1/760 atm/mmHg) ≈ 1.11 atm

Then the balloon contains

n = (1.11 atm) (270 L) / ((0.08206 L•atm/(mol•°K)) (297.2 °K))

n ≈ 12.3 mol

of He.

Solve the same equation for V :

V = nRT/P

Convert the target temperature to °K:

-50 °C = (273.15 - 50) °K = 223.15 °K

Then the volume under the new set of conditions is

V = (12.3 mol) (0.08206 L•atm/(mol•°K)) (223.15 °K) / (0.735 atm)

V ≈ 306 L

Explanation: Using the ideal gas law,

PV = nRT

where R = 0.08206 L•atm/(mol•°K), solving for n gives

n = PV/(RT)

n = (845 mmHg) (270 L) / ((0.08206 L•atm/(mol•°K)) (24 °C))

Convert the given temperature to °K and the given pressure to atm:

24 °C = (273.15 + 24) °K ≈ 297.2 °K

(845 mmHg) × (1/760 atm/mmHg) ≈ 1.11 atm

Then the balloon contains

n = (1.11 atm) (270 L) / ((0.08206 L•atm/(mol•°K)) (297.2 °K))

n ≈ 12.3 mol

of He.

Solve the same equation for V :

V = nRT/P

Convert the target temperature to °K:

-50 °C = (273.15 - 50) °K = 223.15 °K

Then the volume under the new set of conditions is

V = (12.3 mol) (0.08206 L•atm/(mol•°K)) (223.15 °K) / (0.735 atm)

V ≈ 306 L

Chemistry

Step-by-step answer

Answer: -166.67 degrees Celsius.

Explanation: The equation of state of an ideal gas, also called the Mendeleev-Clapeyron equation, has the form: PV = nRT, where P is the density of the gas, V is the volume of the gas, n is the molar mass of the gas, T is the temperature of the gas, R is the universal gas constant = 8.314 J/(mol*K)

The gas temperature at a pressure of P = 978 mm. mercury column, molar mass n = 3.7 mol, and volume V = 25.12 liters is -166.67 degrees Celsius.

Explanation: The equation of state of an ideal gas, also called the Mendeleev-Clapeyron equation, has the form: PV = nRT, where P is the density of the gas, V is the volume of the gas, n is the molar mass of the gas, T is the temperature of the gas, R is the universal gas constant = 8.314 J/(mol*K)

The gas temperature at a pressure of P = 978 mm. mercury column, molar mass n = 3.7 mol, and volume V = 25.12 liters is -166.67 degrees Celsius.

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