Answer:
Empirical formulaStep-by-step explanation:
% of lead (Pb) = 59.37
% of chlorine = 100- 59.37 = 40.63
Moles of lead = 59.37/207.2 ( molar masa of 207.2g)
= 0.29
Moles of chlorine =40.63/35.5
= 1.15
Simple ration( Pb)= 0.29/0.29 =1
Simple ratio (Cl) 1.15/.29 =3.96 = 4
Hence , the compound is PbCl4 ( lead tetrachloride)