Chemistry: how to find mass number of an element

Step-by-step explanation: To find out mass of an element we have to add no. Of protons and no. Of neutrons...

how to find mass number of an element, №15252383, 28.06.2020 10:14

Physics

Two equal forces act on two different objects, one of which has a mass ten times as large as the other. will the more massive object have a larger acceleration, an equal acceleration, or a smaller acceleration than the less massive object? a. the larger mass has a larger acceleration since the ratio of the accelerations will be proportional to the ratio of the masses. b. the larger mass has a smaller acceleration since the ratio of the accelerations will be the inverse of the ratio of the masses. c. the acceleration of the larger mass is equal

Step-by-step answer

P Answered by PhD

The larger mass has a smaller acceleration since the ratio of the accelerations will be the inverse of the ratio of the masses.

Explanation:

It is given that,

Mass of object 1 is 10 times larger than the others. We know that according to Newton's second law of motion, the force is given by the product of mass and acceleration. Its formula is given by :

$F=m\times a$

$m=\dfrac{F}{a}$

Mass of an object is inversely proportional to its acceleration. For two objects,

$\dfrac{m_1}{m_2}=\dfrac{a_2}{a_1}$

So, more massive object have a smaller acceleration than the less massive object. Hence, the correct option is (B).

Physics

Astronomers have observed a small, massive object at the center of our Milky Way Galaxy. A ring of material orbits this massive object; the ring has a diameter of about 15 light-years and an orbital speed of about 190 km/s. a. Determine the mass of the object at the center of the Milky Way galaxy. Give your answer both in kilograms and in solar masses (one solar mass is the mass of the sun). b. Observations of stars, as well as theories of the structure of stars, suggest that it is impossible for a single star to have a mass of more than about

Step-by-step answer

P Answered by PhD

2

A) In Kg, M = 3.84 x 10^(37) kg ; In solar masses, M = 1.931 x 10^(7) solar masses

B) No, it can't be a single ordinary star.

C)Schwarzschild Radius = 5.69 x 10^(10)m

- Yes, a black hole of the object size can fit into the earths orbital radius.

Explanation:

A) Let's assume that the ring shaped disk is circular and thus, to find the mass of the object at the centre of the milky way, we can use the circular orbit equation;

v = √(GM/r)

where;

G is the gravitational constant and has a value of 6.67 x 10^(-11) Nm²/kg²

R is the radius of the orbit,

M is the mass of the larger object

v = velocity = 190km/s = 190000 m/s

The question says it has a diameter of 15 light years. Thus, radius = 15/2 = 7.5 light years

Now, let's convert it to metres.

1 light year = 9.4605 x 10^(15) m

Thus,7.5 light years = 7.5 x 9.4605 x 10^(15) m

Making M the subject of the formula;

M = v²r/G

Plugging all the relevant values, we have;

M = [190000² x 7.5 x 9.4605 x 10^(15)]/6.67 x 10^(-11)

M = 3.84 x 10^(37) kg

The question says we should also express this value in solar mass.

To do this, we'll just divide this mass by the mass of the sun.

Now, mass of the sun generally has a value of 1.9891 x 10^(30) kg

Thus, value of mass of object in solar masses = 3.84 x 10^(37)/1.9891 x 10^(30) = 1.931 x 10^(7) solar masses

B) No, it cant be a single ordinary star because this object has a mass of 1.931 x 10^(7) solar masses and since it is impossible for a single star to have a mass of more than about 50 solar masses, the mass of the object is far greater than the minimum mass of a start and thus the object cannot be a single ordinary star.

C) The formula for Schwarzschild radius is given as;

R_s = 2GM/c²

Where c is speed of light = 3 x 10^(8) m/s

Thus,

R_s = 2 x 6.67 x 10^(-11) x 3.84 x 10^(37)/(3 x 10^(8))² = 5.69 x 10^(10)m

To find out if a black hole of this size fit inside the earth’s orbit around the sun.

Radius of Earths orbit (R_e) is given as;

R_e = 149.6 x 10^(6) km = 14.9 x 10^(10) m

Comparing R_s and R_e, we see that R_s is lesser than R_e and thus, the object can fit into the earths orbital radius.

Physics

Two equal forces act on two different objects, one of which has a mass ten times as large as the other. will the more massive object have a larger acceleration, an equal acceleration, or a smaller acceleration than the less massive object? a. the larger mass has a larger acceleration since the ratio of the accelerations will be proportional to the ratio of the masses. b. the larger mass has a smaller acceleration since the ratio of the accelerations will be the inverse of the ratio of the masses. c. the acceleration of the larger mass is equal

Step-by-step answer

P Answered by PhD

The larger mass has a smaller acceleration since the ratio of the accelerations will be the inverse of the ratio of the masses.

Explanation:

It is given that,

Mass of object 1 is 10 times larger than the others. We know that according to Newton's second law of motion, the force is given by the product of mass and acceleration. Its formula is given by :

$F=m\times a$

$m=\dfrac{F}{a}$

Mass of an object is inversely proportional to its acceleration. For two objects,

$\dfrac{m_1}{m_2}=\dfrac{a_2}{a_1}$

So, more massive object have a smaller acceleration than the less massive object. Hence, the correct option is (B).

Physics

Learning Goal: To learn the definition of the center of mass for systems of particles anda be able to locate it. Imagine throwing a rock upward and away from you. With neglible air resistance, the rock will follow a parabolic path before hitting the ground. Now imagine throwing a stick (or any other extended object). The stick will tend to rotate as it travels through the air, and the motion of each point of the stick (taken individually) will be fairly complex. However, there will be one point that will follow a simple parabolic path: the point

Step-by-step answer

P Answered by PhD

A) Xcm = m1 / (m1 + m2) 10 , B) Xcm = 2/3 L, C) Xcm = 2/3 L

Explanation:

Part A

Let's use the equation

Xcm = 1 / (m1 + m2) (m1 10 + m2 0)

Xcm = m1 / (m1 + m2) 10

The Reference System is placed in particule 2

Pate B

Xcm = 1 / (m + 2m + 3m) (2 L m + L 2m + 0 3m)

Xcm = 1 / 6m (4 Lm)

Xcm = 2/3 L

The center of mass eta between the particle 2m and 3m

The reference system is placed on the heaviest particle (3m)

Part c

Xcm = 2/3 L

Geography

The star HD 12661 is located at a distance of 121 light years, on the border of the constellation Aries near Triangulum. The planet s period is 250 days, with an average distance from its star of 0.80 AU. (One astronomical unit, or AU, is 93 million miles, the distance from the Earth to the Sun.) The lower limit on its mass is 2.8 Jupiter masses. The star HD 92788 is located 104 light years from Earth in the constellation Sextans. The planet s period is 341.7 days, and it orbits at an average distance of 0.98 AU. Its mass is at least 3.7 Jupiter

Step-by-step answer

P Answered by PhD

ms1 = 0.7475ms

ms2 = 1.0054ms

ms3 = 0.0561ms

b) mass of the sun is = 1989 x 10 ∧30kg

c) I feel it is interesting because of the planet's period that is 341.7 days, and it orbits at an average distance of o.98AU, and the mass of the star is almost very identical to the mass of our sun.

Explanation:

see attached file below for further explanation on how i got the answers.

The star HD 12661 is located at a distance of 121 light years, on the border of the constellation Ar

Chemistry

At stp how many liters of oxygen are required to react completely with 4.5 liters of hydrogen to form water? 2h2(g)+o2(g)— 2h2o(g) 1.8 l 3.0 l 9.0 l 2.0 l how many moles of aluminum are needed to react completely with 4.9 mol of feo? 2al(s)+3feo(s)— 3fe(s)*al2o3(s) 4.9 mol of al 0.8 mol of al 3.3 mol of al 7.4 mol of al you are required to use the molar mass in all of the following stoichiometric calculations except volume-volume problems mass-mass problems mass-particle problems mass-volume problems iron(lll) oxide is formed when iron combines

Step-by-step answer

P Answered by PhD

1

Do you have the answers i need help

Geography

The star HD 12661 is located at a distance of 121 light years, on the border of the constellation Aries near Triangulum. The planet s period is 250 days, with an average distance from its star of 0.80 AU. (One astronomical unit, or AU, is 93 million miles, the distance from the Earth to the Sun.) The lower limit on its mass is 2.8 Jupiter masses. The star HD 92788 is located 104 light years from Earth in the constellation Sextans. The planet s period is 341.7 days, and it orbits at an average distance of 0.98 AU. Its mass is at least 3.7 Jupiter

Step-by-step answer

P Answered by PhD

ms1 = 0.7475ms

ms2 = 1.0054ms

ms3 = 0.0561ms

b) mass of the sun is = 1989 x 10 ∧30kg

c) I feel it is interesting because of the planet's period that is 341.7 days, and it orbits at an average distance of o.98AU, and the mass of the star is almost very identical to the mass of our sun.

Explanation:

see attached file below for further explanation on how i got the answers.

Chemistry

At stp how many liters of oxygen are required to react completely with 4.5 liters of hydrogen to form water? 2h2(g)+o2(g)— 2h2o(g) 1.8 l 3.0 l 9.0 l 2.0 l how many moles of aluminum are needed to react completely with 4.9 mol of feo? 2al(s)+3feo(s)— 3fe(s)*al2o3(s) 4.9 mol of al 0.8 mol of al 3.3 mol of al 7.4 mol of al you are required to use the molar mass in all of the following stoichiometric calculations except volume-volume problems mass-mass problems mass-particle problems mass-volume problems iron(lll) oxide is formed when iron combines

Step-by-step answer

P Answered by PhD

1

Do you have the answers i need help

Physics

Two blocks of masses m and 3m are placed on a frictionless, horizontal surface. a light spring is attached to the more massive block, and the blocks are pushed together with the spring between them (fig. p9.9). a cord initially holding the blocks together is burned; after that happens, the block of mass 3mmoves to the right with a speed of 2.00 m/s. (a) what is the velocity of the block of mass m? (b) find the system’s original elastic potential energy, taking m = 0.350 kg. (c) is the original energy in the spring or in the cord? (d) explain your

Step-by-step answer

P Answered by PhD

5

Explanation:

a ) Conservation of momentum is followed

m₁ v₁ = m₂ v₂

3m x 2 = m v

v = 6 m/s

Total kinetic energy

= 1/2 x .35 x 6 ² + 1/2 x 1.05 x 2 ²

= 8.4 J

This energy must be stored as elastic energy in the spring which was released as kinetic energy on burning the cord.

Yes , the conservation of momentum will be followed in the bursting apart process. Only internal forces have been involved in the process. Two equal and opposite internal forces are created by spring which creates motion and generates kinetic energy.

Physics

(Mass vs. Weight) HELP PLZ!! Which of the following statements are FALSE? Select all that apply. a. On Earth, more massive objects weigh more than less massive ones. b. The mass of an object on the moon will be the same as its mass on Earth. c. The weight of an object on the moon will be the same as its weight on Earth. d. The weight of an object is its mass multiplied by the force of gravity. e. The mass and weight of an object are the same thing. f. The mass of an object is the force of gravity acting upon an object.

Step-by-step answer

P Answered by Specialist

$\huge \boxed { \sf{Answers}}$

c. The weight of an object on the moon will be the same as its weight on Earth. It is false because the weight of an on the moon will be 1/6 th times its weight on Earth.d. The weight of an object is its mass multiplied by the force of gravity. The statement is false because the formula of weight is mass × acceleration due to gravity, not force of gravity.e. The mass and weight of an object are the same thing. The statement is false because mass means a body of matter. While weight of an object is its mass multiplied by the force of gravity.f. The mass of an object is the force of gravity acting upon an object. It is false because it will be the weight of the object not mass.So, the answers are c, d, e and f.

Hope you could understand.

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how to find mass number of an element

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