Answer:
Percent yieldStep-by-step explanation:
Molar mass of NaHCO3 = 84 g
Molar mass of Na2CO3 = 106g
Molar mass of H2CO3 = 62 g
According to stoichiometry of the reaction
168 g of NaHCO3 producess = 106 g of sodium carbonate
1 g NaHCO3 produces = (106/168)g of Na2CO3
3.8 g of NaHCO3 producess =( 106/168)×3.8
= 2.40 g
168 g of NaHCO3 producess = 62 g of H2CO3
1 g of NaHCO3 producess = (62/168)
3.8 g NaHCO3 producess = (62/168)×3.8
= 1.40 g
B) according to calculation the amont 2.36 g will be of Sodium bicarbonate
The %yield = (actual /theoritical) ×100
=(2.34/2.40)×100
= 97.5 %