Draw the structure of the isomers of c6h11br that contains a 5-membered ring and is least reactive in an sn1 reaction.

We have to know the structure of the isomer of C₆H₁₁Br which contains 5-membered ring and is least reactive in an SN¹ reaction.

The structure is: isomer (a) shown in figure where methyl group and Br atom connected to the adjacent carbons in the ring.

There are four isomers possible with molecular formula C₆H₁₁Br. Those are shown in figure as (a), (b), (c), (d).

SN¹ reaction takes place through carbocation  intermediate formation. If carbocation is more stable, SN¹ reaction will be more faster and if carbocation is not stable, SN¹ reaction will be slower.

The stability of carbocation depends on number of α-H atoms. If the number of α-H atom is more, hyperconjugation in the carbocation will be more; as a consequence, SN¹ reaction rate will be faster.

On the other hand, if the number of α-H atom is less, hyperconjugation in the carbocation will be less; as a consequence, SN¹ reaction rate will be slow.

The carbocation of isomer (a) contains  α-H atom= 3, all other isomers contain minimum 4 α-H atoms.

Answer:

Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P×V = n×R×T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.

Explanation:

In this case, you know:

P= 0.884 atm

V= ?

n= 0.857 moles (where 28 g/mole is the molar mass of N₂, that is, the amount of mass that the substance contains in one mole.)

R=0.082

T= 328 K

Replacing in the ideal gas law:

0.884 atm×V= 0.857 moles× 0.082 ×328 K

Solving:

V= 26.07 L

The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.