27.02.2021

Write the net ionic equation for the precipitation of calcium sulfide from aqueous solution

. 1

Step-by-step answer

24.06.2023, solved by verified expert
Unlock the full answer

Answer is Ca2+(aq)+S2-(aq)=>CaS(s)

Explanation:

I hope it's helpful!

It is was helpful?

Faq

Chemistry
Step-by-step answer
P Answered by PhD

Answer is Ca2+(aq)+S2-(aq)=>CaS(s)

Explanation:

I hope it's helpful!

Chemistry
Step-by-step answer
P Answered by Specialist

The net ionic equation is written below.

Explanation:

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of calcium iodide and chromium (III) sulfate is given as:

3CaI_2(aq.)+Cr_2(SO_4)_3(aq.)\rightarrow 3CaSO_4(s)+2CrI_3(aq.)

Ionic form of the above equation follows:

3Ca^{2+}(aq.)+6I^{-}(aq.)+2Cr^{3+}(aq.)+3SO_4^{2-}(aq.)\rightarrow 3CaSO_4(s)+2Cr^{3+}(aq.)+6I^-(aq.)

As, chromium and iodide ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

3Ca^{2+}(aq.)+3SO_4^{2-}(aq.)\rightarrow 3CaSO_4(s)

Hence, the net ionic equation is written above.

Chemistry
Step-by-step answer
P Answered by Master

The net ionic equation is written below.

Explanation:

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of calcium iodide and chromium (III) sulfate is given as:

3CaI_2(aq.)+Cr_2(SO_4)_3(aq.)\rightarrow 3CaSO_4(s)+2CrI_3(aq.)

Ionic form of the above equation follows:

3Ca^{2+}(aq.)+6I^{-}(aq.)+2Cr^{3+}(aq.)+3SO_4^{2-}(aq.)\rightarrow 3CaSO_4(s)+2Cr^{3+}(aq.)+6I^-(aq.)

As, chromium and iodide ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

3Ca^{2+}(aq.)+3SO_4^{2-}(aq.)\rightarrow 3CaSO_4(s)

Hence, the net ionic equation is written above.

Chemistry
Step-by-step answer
P Answered by Master

Explanation:

a ) 2FeCl₃ + 3Li₂S  = Fe₂S₃ ( s )  + 6 LiCl

2Fe⁺³ + 6Li ⁻ + 6Cl⁻ + 3S⁻² = 6Li + 6Cl⁻ + Fe₂S₃ ( s )

b  )

3CH₃COONa +( NH₄)₃PO₄ = 3CH₃COONH₄ + Na₃PO₄

3CH₃COO + 3Na⁺ +  3NH₄⁻  +  PO₄⁺³  = 3CH₃COO⁻ +3NH₄⁺ + Na₃PO₄

c )

HClO₄  + KOH = kClO₄ + H₂O

H ⁺ + ClO₄⁻ +  K⁺ + OH⁻  =  k⁺  ClO₄⁻  + H₂O

d )

NH₄OH + HNO₃ = NH₄NO₃  + H₂O

NH₄⁺ + OH⁻ + H⁺ + NO₃⁻ = NH₄⁺ + NO₃⁻ +  H₂O

e )

HNO₂ + KOH = KNO₂ + H₂O

H⁺ + NO₂⁻ + K⁺ + OH⁻ = K⁺ + NO₂⁻ + H₂O

f ) HIO₃ + CaCO₃ ( s ) = Ca( IO₃ )₂ + H₂CO₃

H⁺ + IO₃⁻ + CaCO₃ ( s ) = Ca( IO₃ )₂ + H₂CO₃

g )

c ) is strong acid and strong base

d ) is weak base and strong acid

e ) weak acid and strong base

f ) Strong acid and basic salt

Chemistry
Step-by-step answer
P Answered by Master

Explanation:

a ) 2FeCl₃ + 3Li₂S  = Fe₂S₃ ( s )  + 6 LiCl

2Fe⁺³ + 6Li ⁻ + 6Cl⁻ + 3S⁻² = 6Li + 6Cl⁻ + Fe₂S₃ ( s )

b  )

3CH₃COONa +( NH₄)₃PO₄ = 3CH₃COONH₄ + Na₃PO₄

3CH₃COO + 3Na⁺ +  3NH₄⁻  +  PO₄⁺³  = 3CH₃COO⁻ +3NH₄⁺ + Na₃PO₄

c )

HClO₄  + KOH = kClO₄ + H₂O

H ⁺ + ClO₄⁻ +  K⁺ + OH⁻  =  k⁺  ClO₄⁻  + H₂O

d )

NH₄OH + HNO₃ = NH₄NO₃  + H₂O

NH₄⁺ + OH⁻ + H⁺ + NO₃⁻ = NH₄⁺ + NO₃⁻ +  H₂O

e )

HNO₂ + KOH = KNO₂ + H₂O

H⁺ + NO₂⁻ + K⁺ + OH⁻ = K⁺ + NO₂⁻ + H₂O

f ) HIO₃ + CaCO₃ ( s ) = Ca( IO₃ )₂ + H₂CO₃

H⁺ + IO₃⁻ + CaCO₃ ( s ) = Ca( IO₃ )₂ + H₂CO₃

g )

c ) is strong acid and strong base

d ) is weak base and strong acid

e ) weak acid and strong base

f ) Strong acid and basic salt

Chemistry
Step-by-step answer
P Answered by Specialist
Answer : YES, the reaction will give a precipitate. 

Explanation : When ammonium sulfate and calcium acetate are mixed together the reaction that occurs  is given below :

(NH_{4}) _{2}  SO_{4}  + Ca ( C_{2}  H_{3}  O_{2}  )_{2}  -----\ \textgreater \  Ca  SO_{4}  + 2 [NH _{4}( C_{2}  H_{3}  O_{2}  ) ]

a simple displacement reaction occurs which yields Calcium Sulfate as the precipitate along with the Ammonium acetate as the by-product.

As we know calcium sulfate is a solid which is obtained, the major product will get precipitated. And rest other ions which are formed, remains in aqueous form.

The net ionic equation will be consisting of only the solid precipitate that is formed.
Ca  ^{2+}  _{(aq)} + SO _{4}  ^{2-} _{(aq)} ----\ \textgreater \   CaSO_{4}^{2-} _{(s)}
Chemistry
Step-by-step answer
P Answered by Master
Answer : YES, the reaction will give a precipitate. 

Explanation : When ammonium sulfate and calcium acetate are mixed together the reaction that occurs  is given below :

(NH_{4}) _{2}  SO_{4}  + Ca ( C_{2}  H_{3}  O_{2}  )_{2}  -----\ \textgreater \  Ca  SO_{4}  + 2 [NH _{4}( C_{2}  H_{3}  O_{2}  ) ]

a simple displacement reaction occurs which yields Calcium Sulfate as the precipitate along with the Ammonium acetate as the by-product.

As we know calcium sulfate is a solid which is obtained, the major product will get precipitated. And rest other ions which are formed, remains in aqueous form.

The net ionic equation will be consisting of only the solid precipitate that is formed.
Ca  ^{2+}  _{(aq)} + SO _{4}  ^{2-} _{(aq)} ----\ \textgreater \   CaSO_{4}^{2-} _{(s)}
Chemistry
Step-by-step answer
P Answered by PhD

Ca +  CO₃²⁻   → CaCO₃

Explanation:

Solution:

      Sodium carbonate  = Na₂CO₃

      Calcium chloride = CaCl₂

      Calcium carbonate is precipitated

Reaction equation:

           Na₂CO₃  +  CaCl₂  →  CaCO₃ + 2NaCl

The net ionic equation:

        2Na⁺ + CO₃²⁻   + Ca + 2Cl⁻  → CaCO₃ + 2Na⁺ + Cl⁻

the spectator ions which both appears on both sides will cancel out and leave behind the net ionic equation:

              Ca +  CO₃²⁻   → CaCO₃

Chemistry
Step-by-step answer
P Answered by PhD

H₂C₂O₄ + Ca²⁺ ⟶ CaC₂O₄ + 2H⁺

Explanation:

There are three steps you must follow to get the answer.

You must write the:

Molecular equation Ionic equation Net ionic equation

1. Molecular equation

H₂C₂O₄(aq) + CaCl₂(aq) ⟶ CaC₂O₄(s) + 2HCl(aq)

2. Ionic equation

You write the molecular formulas for the weak electrolytes and solids, and you write the soluble ionic substances as ions.

H₂C₂O₄(aq) + Ca²⁺(aq) + 2Cl⁻(aq) ⟶ CaC₂O₄(s) + 2H⁺(aq) + 2Cl⁻(aq)

3. Net ionic equation

To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.

H₂C₂O₄(aq) + Ca²⁺(aq) + 2Cl⁻(aq) ⟶ CaC₂O₄(s) + 2H⁺(aq) + 2Cl⁻(aq)

The net ionic equation is

H₂C₂O₄ + Ca²⁺ ⟶ CaC₂O₄ + 2H⁺

Chemistry
Step-by-step answer
P Answered by PhD

Ca +  CO₃²⁻   → CaCO₃

Explanation:

Solution:

      Sodium carbonate  = Na₂CO₃

      Calcium chloride = CaCl₂

      Calcium carbonate is precipitated

Reaction equation:

           Na₂CO₃  +  CaCl₂  →  CaCO₃ + 2NaCl

The net ionic equation:

        2Na⁺ + CO₃²⁻   + Ca + 2Cl⁻  → CaCO₃ + 2Na⁺ + Cl⁻

the spectator ions which both appears on both sides will cancel out and leave behind the net ionic equation:

              Ca +  CO₃²⁻   → CaCO₃

Try asking the Studen AI a question.

It will provide an instant answer!

FREE