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27.02.2021

Write the net ionic equation for the precipitation of calcium sulfide from aqueous solution

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24.06.2023, solved by verified expert

Ranjana Bhatt

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Answer is Ca2+(aq)+S2-(aq)=>CaS(s)

Explanation:

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Chemistry

Write the net ionic equation for the precipitation of calcium sulfide from aqueous solution

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P Answered by PhD

Answer is Ca2+(aq)+S2-(aq)=>CaS(s)

Explanation:

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Chemistry

Write the net ionic equation for any precipitation reaction that may be predicted when aqueous solutions of calcium iodide and chromium(III) sulfate are combined. (Use the solubility rules provided in the OWL Preparation Page to determine the solubility of compounds.)

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P Answered by Specialist

The net ionic equation is written below.

Explanation:

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of calcium iodide and chromium (III) sulfate is given as:

$3CaI_2(aq.)+Cr_2(SO_4)_3(aq.)\rightarrow 3CaSO_4(s)+2CrI_3(aq.)$

Ionic form of the above equation follows:

$3Ca^{2+}(aq.)+6I^{-}(aq.)+2Cr^{3+}(aq.)+3SO_4^{2-}(aq.)\rightarrow 3CaSO_4(s)+2Cr^{3+}(aq.)+6I^-(aq.)$

As, chromium and iodide ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$3Ca^{2+}(aq.)+3SO_4^{2-}(aq.)\rightarrow 3CaSO_4(s)$

Hence, the net ionic equation is written above.

Chemistry

Step-by-step answer

P Answered by Master

The net ionic equation is written below.

Explanation:

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of calcium iodide and chromium (III) sulfate is given as:

$3CaI_2(aq.)+Cr_2(SO_4)_3(aq.)\rightarrow 3CaSO_4(s)+2CrI_3(aq.)$

Ionic form of the above equation follows:

$3Ca^{2+}(aq.)+6I^{-}(aq.)+2Cr^{3+}(aq.)+3SO_4^{2-}(aq.)\rightarrow 3CaSO_4(s)+2Cr^{3+}(aq.)+6I^-(aq.)$

As, chromium and iodide ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$3Ca^{2+}(aq.)+3SO_4^{2-}(aq.)\rightarrow 3CaSO_4(s)$

Hence, the net ionic equation is written above.

Chemistry

Write balanced, net ionic equations for the following precipitation, acidn base, or gasn forming reactions. Include states of matter. Hint: You should write the molecular equation first to predict the products. a) mixing aqueous solutions of iron (III) chloride and lithium sulfide b) mixing aqueous solutions of sodium acetate and ammonium phosphate c) mixing aqueous solutions of perchloric acid and potassium hydroxide d) mixing aqueous solutions of ammonia and nitric acid e) mixing aqueous solutions of nitrous acid and sodium hydroxide f) adding

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Explanation:

a ) 2FeCl₃ + 3Li₂S = Fe₂S₃ ( s ) + 6 LiCl

2Fe⁺³ + 6Li ⁻ + 6Cl⁻ + 3S⁻² = 6Li + 6Cl⁻ + Fe₂S₃ ( s )

b )

3CH₃COONa +( NH₄)₃PO₄ = 3CH₃COONH₄ + Na₃PO₄

3CH₃COO + 3Na⁺ + 3NH₄⁻ + PO₄⁺³ = 3CH₃COO⁻ +3NH₄⁺ + Na₃PO₄

c )

HClO₄ + KOH = kClO₄ + H₂O

H ⁺ + ClO₄⁻ + K⁺ + OH⁻ = k⁺ ClO₄⁻ + H₂O

d )

NH₄OH + HNO₃ = NH₄NO₃ + H₂O

NH₄⁺ + OH⁻ + H⁺ + NO₃⁻ = NH₄⁺ + NO₃⁻ + H₂O

e )

HNO₂ + KOH = KNO₂ + H₂O

H⁺ + NO₂⁻ + K⁺ + OH⁻ = K⁺ + NO₂⁻ + H₂O

f ) HIO₃ + CaCO₃ ( s ) = Ca( IO₃ )₂ + H₂CO₃

H⁺ + IO₃⁻ + CaCO₃ ( s ) = Ca( IO₃ )₂ + H₂CO₃

g )

c ) is strong acid and strong base

d ) is weak base and strong acid

e ) weak acid and strong base

f ) Strong acid and basic salt

Chemistry

Step-by-step answer

P Answered by Master

Explanation:

a ) 2FeCl₃ + 3Li₂S = Fe₂S₃ ( s ) + 6 LiCl

2Fe⁺³ + 6Li ⁻ + 6Cl⁻ + 3S⁻² = 6Li + 6Cl⁻ + Fe₂S₃ ( s )

b )

3CH₃COONa +( NH₄)₃PO₄ = 3CH₃COONH₄ + Na₃PO₄

3CH₃COO + 3Na⁺ + 3NH₄⁻ + PO₄⁺³ = 3CH₃COO⁻ +3NH₄⁺ + Na₃PO₄

c )

HClO₄ + KOH = kClO₄ + H₂O

H ⁺ + ClO₄⁻ + K⁺ + OH⁻ = k⁺ ClO₄⁻ + H₂O

d )

NH₄OH + HNO₃ = NH₄NO₃ + H₂O

NH₄⁺ + OH⁻ + H⁺ + NO₃⁻ = NH₄⁺ + NO₃⁻ + H₂O

e )

HNO₂ + KOH = KNO₂ + H₂O

H⁺ + NO₂⁻ + K⁺ + OH⁻ = K⁺ + NO₂⁻ + H₂O

f ) HIO₃ + CaCO₃ ( s ) = Ca( IO₃ )₂ + H₂CO₃

H⁺ + IO₃⁻ + CaCO₃ ( s ) = Ca( IO₃ )₂ + H₂CO₃

g )

c ) is strong acid and strong base

d ) is weak base and strong acid

e ) weak acid and strong base

f ) Strong acid and basic salt

Chemistry

Predict whether a precipitation reaction will occur when aqueous solutions of ammonium sulfate and calcium acetate are mixed write the net ionic equation

Step-by-step answer

P Answered by Specialist

Answer : YES, the reaction will give a precipitate.

Explanation : When ammonium sulfate and calcium acetate are mixed together the reaction that occurs is given below :

$(NH_{4}) _{2} SO_{4} + Ca ( C_{2} H_{3} O_{2} )_{2} -----\ \textgreater \ Ca SO_{4} + 2 [NH _{4}( C_{2} H_{3} O_{2} ) ]$

a simple displacement reaction occurs which yields Calcium Sulfate as the precipitate along with the Ammonium acetate as the by-product.

As we know calcium sulfate is a solid which is obtained, the major product will get precipitated. And rest other ions which are formed, remains in aqueous form.

The net ionic equation will be consisting of only the solid precipitate that is formed.
$Ca ^{2+} _{(aq)} + SO _{4} ^{2-} _{(aq)} ----\ \textgreater \ CaSO_{4}^{2-} _{(s)}$