110g/mol is the molar mass of compound A
Explanation:
The osmotic pressure of a solution could be obtained using the equation:
π = i*M*R*T -Solving molarity we can find the molar mass of the solute A-
Where π is osmotic pressure (7.38atm)
i is Van't Hoff's factor (1 for nonelectrolytes)
M is molarity (Our incognite)
R is gas constant (0.082atmL/molK)
T is absolute temperature (25°C + 273.15 = 298.15K)
Computing the values:
7.378atm = 1*M*0.082atmL/molK*298.15K
0.3018 mol/L is the concentration of the solution.
The volume of the solution is 15mL = 0.015L. Moles of the solute are:
0.3018 mol/L * 0.015L = 4.527x10⁻³ moles
Molar mass is the ratio between mass of the compound (0.50g) and the moles (4.527x10⁻³ moles). That is:
0.50g / 4.527x10⁻³ moles =
110g/mol is the molar mass of compound A