How many moles is 592.1 grams of LiCO3

8.84 mols LiCO3

Explanation:

We will have to find the molar mass of LiCO3, which we can use a periodic table.

Li: 6.97 g/mol

C: 12.01 g/mol

O: 48 g/mol (molar mass of O is 16, but we multiply it by 3)

Adding these values together will get our molar mass of LiCO3, which 66.98 g/mol.

Now we can use the molar mass of LiCO3 to convert the number of grams shown to the amount of mols we are trying to find.

Total moles of gas = 0.1225

Volume of gas produced : 6.7375 L

mass of Nitrogen : 0.588 g

Given

2 ml of Nitroglycerin(ρ=1.592 g/ml)

Required

Total moles of gas

Solution

Nitroglycerin detonated ⇒ decomposition reaction

4C₃H₅N₃O₉(s)⇒ 6N₂(g)+12CO(g)+10H₂O(g)+7O₂(g)

mass of Nitroglycerin :

moles of Nitroglycerin :

Total moles of gas:

Volume of gas produced :

moles of Nitrogen :

mass of Nitrogen :

Total moles of gas = 0.1225

Volume of gas produced : 6.7375 L

mass of Nitrogen : 0.588 g

Given

2 ml of Nitroglycerin(ρ=1.592 g/ml)

Required

Total moles of gas

Solution

Nitroglycerin detonated ⇒ decomposition reaction

4C₃H₅N₃O₉(s)⇒ 6N₂(g)+12CO(g)+10H₂O(g)+7O₂(g)

mass of Nitroglycerin :

moles of Nitroglycerin :

Total moles of gas:

Volume of gas produced :

moles of Nitrogen :

mass of Nitrogen :

Answer:

Step-by-step explanation:

It is clear by the equation 2(27+3×35.5)= 267 gm of AlCl3 reacts with 6× 80 = 480 gm of Br2 . So 29.2 gm reacts = 480× 29.2/267= 52.6 gm

Calcium (Ca)(On the periodic table, ionization energy increases as you go up and to the right of the periodic table)

glycoproteins

Explanation:

A positive reaction for Molisch's test is given by almost all carbohydrates (exceptions include tetroses & trioses). It can be noted that even some glycoproteins and nucleic acids give positive results for this test (since they tend to undergo hydrolysis when exposed to strong mineral acids and form monosaccharides).