1-a-Madame Magloire.
2-c. A single subject. (A single sentence is made up of one subject and one predicate).
3-b. Some plants growing at an angle can straighten themselves up. ( The underlined word is a present participle derived from " ..plants that are growing at...").
4-d. All of the above
5-d. The boy and his friends run every day.
6-c. That book is Laura's
7-a. Her brother Chris is on the basketball team.
8-c. Implication.
9-d. No particular person, place, or thing.
10-d. All of the above
11-d. Metaphor
12-a. The speaker sounds hoarse, as if he has a cold.
13-b. The letter will be written by her.
14-a. Who
15-c. seem
16-b. has
17-a. annoying ( The speaker is giving an opinion about Harry).
18-d. both b and c
19-b. Jack Smith
20-b. single sentence
21-a- angry
22-c-hard
1-a-Madame Magloire.
2-c. A single subject. (A single sentence is made up of one subject and one predicate).
3-b. Some plants growing at an angle can straighten themselves up. ( The underlined word is a present participle derived from " ..plants that are growing at...").
4-d. All of the above
5-d. The boy and his friends run every day.
6-c. That book is Laura's
7-a. Her brother Chris is on the basketball team.
8-c. Implication.
9-d. No particular person, place, or thing.
10-d. All of the above
11-d. Metaphor
12-a. The speaker sounds hoarse, as if he has a cold.
13-b. The letter will be written by her.
14-a. Who
15-c. seem
16-b. has
17-a. annoying ( The speaker is giving an opinion about Harry).
18-d. both b and c
19-b. Jack Smith
20-b. single sentence
21-a- angry
22-c-hard
So the p value obtained was a very low value and using the significance level given we have so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of students who will correctly identify the color is different than 0.5
Step-by-step explanation:
Data given and notation
n=121 represent the random sample taken
X=97 represent the people who identify the color of the gummy bear
estimated proportion of people who identify the color of the gummy bear
is the value that we want to test
represent the significance level
Confidence=99% or 0.99
z would represent the statistic (variable of interest)
represent the p value (variable of interest)
Part a
For this case the parameter that we want to test is 0.5 for the proportion of the population of students will correctly identify the color
Part b: Concepts and formulas to use
We need to conduct a hypothesis in order to test the claim that there is no relationship between color and gummy bear flavor (population proportion different from 0.5).:
Null hypothesis:
Alternative hypothesis:
When we conduct a proportion test we need to use the z statistic, and the is given by:
(1)
The One-Sample Proportion Test is used to assess whether a population proportion is significantly different from a hypothesized value .
Part c: Calculate the statistic
Since we have all the info requires we can replace in formula (1) like this:
Statistical decision
It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.
The significance level provided . The next step would be calculate the p value for this test.
Since is a right tailed test the p value would be:
So the p value obtained was a very low value and using the significance level given we have so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of students who will correctly identify the color is different than 0.5
Identifying the need
Explanation molly would like to design a dog collar that has a short
So the p value obtained was a very low value and using the significance level given we have so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of students who will correctly identify the color is different than 0.5
Step-by-step explanation:
Data given and notation
n=121 represent the random sample taken
X=97 represent the people who identify the color of the gummy bear
estimated proportion of people who identify the color of the gummy bear
is the value that we want to test
represent the significance level
Confidence=99% or 0.99
z would represent the statistic (variable of interest)
represent the p value (variable of interest)
Part a
For this case the parameter that we want to test is 0.5 for the proportion of the population of students will correctly identify the color
Part b: Concepts and formulas to use
We need to conduct a hypothesis in order to test the claim that there is no relationship between color and gummy bear flavor (population proportion different from 0.5).:
Null hypothesis:
Alternative hypothesis:
When we conduct a proportion test we need to use the z statistic, and the is given by:
(1)
The One-Sample Proportion Test is used to assess whether a population proportion is significantly different from a hypothesized value .
Part c: Calculate the statistic
Since we have all the info requires we can replace in formula (1) like this:
Statistical decision
It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.
The significance level provided . The next step would be calculate the p value for this test.
Since is a right tailed test the p value would be:
So the p value obtained was a very low value and using the significance level given we have so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of students who will correctly identify the color is different than 0.5
I'm not sure if I'm right, I'm a little rusty, but I think it's A. Identify Trends.
I'm not sure if I'm right, I'm a little rusty, but I think it's A. Identify Trends.
A. Online analytical processing
Explanation:
Online analytical processing will help James in the massive categorization of data.
Online analytical processing (OLAP) refers to a software that allows its users to analyze information from multiple database systems at the same time.
It saves time for users and it makes data analysis faster and accurate. It allows users to easily extract and select data for analysis from different kinds of perspective.
Online analytical processing can be used in such areas as sales forcasting, making budget, preparing financial report etc.
It will provide an instant answer!