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Answer:
103.32°CStep-by-step explanation:
The number of moles of a substance is given by :
Number of moles = Given mass/Molar mass
For magnesium nitrate,
Given mass = 34.3 g and Molar mass = 148.3 g/mol
So, number of moles (n) = 34.3/148.3 = 0.2313 moles
So, molality (m) = Number of moles of solute/mass of solvent in kg = 0.2313/0.107 = 2.16m
The elevation in boiling point of the solution is given by :
∆Tb = Kb × i × m
Here, Kb for water = 0.512°C/m and i is vanthu Hoff factor.
For Mg(NO3)2, i = 3
Thus,
∆Tb = 0.512 × 3 × 2.16 = 3.32°C
So,
Boiling point of the solution = Boling point of the solvent (water) + ∆Tb
= 100 + 3.32
= 103.32°C