Step-by-step explanation:
1. Slope = (y2-y1) / (x2-x1) = -3-0/ -1-4= -3/-5= 3/5 (d)
2.
Compare to the equation y= mx+b, where m is the slope
3y = 15x+9 divide by 3 each term
y = 15x/3 +9/3
y= 5x + 3 so slope is 5 ( a)
3.
use first the equation point- slope y-y1 =m (x-x1) and rearange it to be in slope-intercept form y=mx +b
y-y1 =m (x-x1)
y-2 = -3( x-1)
y = 2-3x+3
y= -3x +5 ( c)
4.
if the point y- intercept is at (0, 3) then the y-intercept is b=3
y= mx+b
y = 2x +3 (a)
5.
the equation point- slope y-y1 =m (x-x1), find the slope m= (y2-y1) / (x2-x1)
m= 3-12/ 1+2 = -9/3 = -3
y-1 = -3(x-3) is (a)
6.
y-intercept is at -4 ( yet the graph is off a bit -tell your teacher)
slope m = 1
so the equation is y=mx+b and here is y=x -4 (c)
7.
the slope is m= (y2-y1) / (x2-x1) si pich any two points from the table and calculate the slope
for example (0, 3) and (1, 0)
m = (3-0)/ (0-1) = 3/-1 = -3 (d)