27.12.2020


Please answer questions number 2 and 3

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10.08.2023, solved by verified expert
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Answer:

Answer explained below.

Step-by-step explanation:

Note - Since you asked multiple questions, I will solve the first question for you. To get rest of the question solved please repost mentioning the question to be solved. 

Question 2.

Why do you think there is so much crime or violence in some neighborhoods and not others?

Answer :

The prevalence of crime or violence in specific neighborhoods can be attributed to a complex interplay of socioeconomic factors. Disadvantaged communities may experience higher crime rates due to limited access to quality education, employment opportunities, and social services. Poverty can breed desperation, leading some individuals to engage in criminal activities to meet basic needs. Additionally, systemic issues such as racial discrimination and unequal law enforcement practices can perpetuate crime cycles. Disinvestment and lack of community resources further exacerbate the problem, creating a vicious cycle of crime and poverty. In addition to these social factors, there are also some physical factors that can contribute to crime and violence. For example, communities with high levels of gang activity or drug trafficking are more likely to experience crime. Communities with poor lighting and few street cameras are also more likely to be targets for crime.

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Mathematics
Step-by-step answer
P Answered by Master
A. 2x+4y= 100

B. 2x +4(24)=100
2x+96=100
2x=4
x=2 (2 questions worth 2 pts a piece)

2. x= 5$ bills y= singles
a. 5x+y=36
b. 5(2)+y=36
10 + y=36
y=26 (26 singles)
3. x= sandwich cost y=salad cost
a. 4x+3y=24
b. 4(3.75)+3y = 24
15+3y=24
2y=9
y=4.50 (4.50$ per salad)
4: X = pounds of roast beef, y = pounds of shrimp Roast beef = $4 per pound
Shrimp = $10 per pound
a. Total $96
4 + 10 = 96 b. 4(0)+10=96
10 = 96
= 9.6
The most shrimp Andy can buy is 9.6 lbs
Mathematics
Step-by-step answer
P Answered by Specialist

65 two-point questions, and 5 four-point questions.

Emma answered 2 four-point questions.

Step-by-step explanation:

1. Assigning variables and writing equations

We will set the number of 2 point questions as "x" and number of 4 point questions as "y"

We know that:

x+y=70 (number of 2 point questions+number of 4 point questions=total number of questions)

2x+4y=150 (number of points that a two point question is worth*number of two point questions+number of points that a four point question is worth*number of four point questions=total points on test)

2. Combining equations

x+y=70, 2x+4y=150

We will solve one of these equations.

x+y=70

x=70-y

Next, we will substitute the other equation with this solution.

2*(70-y)+4y=150

140-2y+4y=150

2y=10

y=5

Use this solution to find x.

x+y=70

x+5=70

x=65

We found that there are 65 two-point questions, and 5 four-point questions.

3. Finding Emma's test results

In this case, we know how many two-point questions she answered. So, we will only be using one variable in this equation, which is y.

46*2+4y=100

92+4y=100

4y=8

y=2

So, she answered 2 questions correctly.

Mathematics
Step-by-step answer
P Answered by Specialist
A. 2x+4y= 100

B. 2x +4(24)=100
2x+96=100
2x=4
x=2 (2 questions worth 2 pts a piece)

2. x= 5$ bills y= singles
a. 5x+y=36
b. 5(2)+y=36
10 + y=36
y=26 (26 singles)
3. x= sandwich cost y=salad cost
a. 4x+3y=24
b. 4(3.75)+3y = 24
15+3y=24
2y=9
y=4.50 (4.50$ per salad)
4: X = pounds of roast beef, y = pounds of shrimp Roast beef = $4 per pound
Shrimp = $10 per pound
a. Total $96
4 + 10 = 96 b. 4(0)+10=96
10 = 96
= 9.6
The most shrimp Andy can buy is 9.6 lbs
Mathematics
Step-by-step answer
P Answered by Specialist

65 two-point questions, and 5 four-point questions.

Emma answered 2 four-point questions.

Step-by-step explanation:

1. Assigning variables and writing equations

We will set the number of 2 point questions as "x" and number of 4 point questions as "y"

We know that:

x+y=70 (number of 2 point questions+number of 4 point questions=total number of questions)

2x+4y=150 (number of points that a two point question is worth*number of two point questions+number of points that a four point question is worth*number of four point questions=total points on test)

2. Combining equations

x+y=70, 2x+4y=150

We will solve one of these equations.

x+y=70

x=70-y

Next, we will substitute the other equation with this solution.

2*(70-y)+4y=150

140-2y+4y=150

2y=10

y=5

Use this solution to find x.

x+y=70

x+5=70

x=65

We found that there are 65 two-point questions, and 5 four-point questions.

3. Finding Emma's test results

In this case, we know how many two-point questions she answered. So, we will only be using one variable in this equation, which is y.

46*2+4y=100

92+4y=100

4y=8

y=2

So, she answered 2 questions correctly.

Mathematics
Step-by-step answer
P Answered by PhD

there are 14 5point problems and 15 2point problems on the test.

Step-by-step explanation:

x represents number of 5 point questions and y represents questions worth 2 points.

The total number of questions in the test is 29. It means that

x + y = 29

x = 29 - y

Mr. Martin’s math test is worth 100 points. It means that

5x + 2y = 100 - - - - - - - - -1

Substituting x = 29 - y into equation 1, it becomes

5(29 - y) + 2y = 100

145 - 5y + 2y = 100

- 5y + 2y = 100 - 145

- 3y = - 45

y = - 45/-3

y = 15

x = 29 - y = 29 - 15

x = 14

Mathematics
Step-by-step answer
P Answered by PhD

there are 14 5point problems and 15 2point problems on the test.

Step-by-step explanation:

x represents number of 5 point questions and y represents questions worth 2 points.

The total number of questions in the test is 29. It means that

x + y = 29

x = 29 - y

Mr. Martin’s math test is worth 100 points. It means that

5x + 2y = 100 - - - - - - - - -1

Substituting x = 29 - y into equation 1, it becomes

5(29 - y) + 2y = 100

145 - 5y + 2y = 100

- 5y + 2y = 100 - 145

- 3y = - 45

y = - 45/-3

y = 15

x = 29 - y = 29 - 15

x = 14

Mathematics
Step-by-step answer
P Answered by PhD

C) The term 10E represents the total number of points earned from 10 extended-response questions

Step-by-step explanation:

From the question;

The expression 2T+3F+4M+10E =points a earns on a test

Number of true-false questions correctly answered=2T

Number of Fill-in -the blank questions correctly answered=3 F

Number of multiple choice questions correctly answered= 4M

Number of extended-resonse questions correctly answered =10 E

However, the question does not mention the number of qusetions in each category. Like how many true-false questions were there. It only tells you the number of correct true-false qusetions that were answered. So saying that there were 10 extended-response questions is incorrect.

Mathematics
Step-by-step answer
P Answered by PhD

C) The term 10E represents the total number of points earned from 10 extended-response questions

Step-by-step explanation:

From the question;

The expression 2T+3F+4M+10E =points a earns on a test

Number of true-false questions correctly answered=2T

Number of Fill-in -the blank questions correctly answered=3 F

Number of multiple choice questions correctly answered= 4M

Number of extended-resonse questions correctly answered =10 E

However, the question does not mention the number of qusetions in each category. Like how many true-false questions were there. It only tells you the number of correct true-false qusetions that were answered. So saying that there were 10 extended-response questions is incorrect.

Mathematics
Step-by-step answer
P Answered by Specialist

a. 2x+4y=100

b. 2 questions

Step-by-step explanation:

For a, you can write out hat equation, which can test if a specific combination will work, and once you have one variable, you can solve another

For b, you can plug 24 into the equation

2x+4(24)=100

2x+96=100

2x=4

x=2

Mathematics
Step-by-step answer
P Answered by Master

44

Step-by-step explanation:

Let x and y be the total number of questions in part 1 and part 2 exams respectively.

For part 1:

Number of correct question = 4/5 of the total number of question in part 1

\Rightarrow 16=\frac{4}{5}\times x

\Rightarrow x=20

For part 2:

Number of corrected question = 2/3 of total number of question in part 2

\Rightarrow 16=\frac{2}{3}\times x

\Rightarrow x=24

So, the total umbers of the questions on Stephanie's exam

=x+y

=20+24

=44

Hence, the total umbers of the questions on Stephanie's exam was 44.

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