Michiko is right for this system of linear equations, and her method will also work for other systems of linear equations.
Step-by-step explanation:
Given infinite system of linear equations is ax + by = 0
when (a,b) moves along unit circle in plane.
a) system having unique system (0, 0)
Since two of equation in thus system will be
and
It is clear that x = 0, y= 0 is the only solution
b) Linear independent solution in this system gives some set of solutions
and
Vector form is
c) for this equation if add 0x +0y = 0 to system , Nothing will change
Because [0,0] satisfies that equation
d) If one of the equation is ax + by = 0.00001
where 0.00001 is small positive number
so, the system will be inconsistent
Therefore, the system will have no solution.
A. Yes, overdetermined systems can be consistent.
As, the system of equations below is consistent because it has a solution
, , .
Step-by-step explanation:
We have,
'Over-determined system is a system of linear equations, in which there are more equations than unknowns'.
For e.g. Let us consider the system,
2x - 3y = 1
3x - 2y = 4
x - y = 1
Plotting these equations, we see from the graph below that,
The only intersection point is (2,1). Thus, x= 2 and y= 1 is the solution of this system.
Thus, over-determined system can be consistent.
According to the options,
Option C is not correct as,
, implies .
Hence, option A is correct.
A. Yes, overdetermined systems can be consistent.
As, the system of equations below is consistent because it has a solution
, , .
Step-by-step explanation:
We have,
'Over-determined system is a system of linear equations, in which there are more equations than unknowns'.
For e.g. Let us consider the system,
2x - 3y = 1
3x - 2y = 4
x - y = 1
Plotting these equations, we see from the graph below that,
The only intersection point is (2,1). Thus, x= 2 and y= 1 is the solution of this system.
Thus, over-determined system can be consistent.
According to the options,
Option C is not correct as,
, implies .
Hence, option A is correct.
We need to find which of the given statements are true.
The system of linear equations has no solutions.
First let us find what type of solution does the system have
The equations are
So,
So,
This means the two lines do not intersect and are parallel.
Hence, the system of linear equations has no solutions.
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Different ways to solve a system of linear equations:
isolate one variable in one equation and replace it in the other equationmultiply/divide one equation by a constant and then add/subtract it to the other one, so that only one variable remainsgraph the equation and look at the intersection pointIf you graph the system:
there is only one solution if the lines intersects at only one pointthere is no solution if the lines don't intersect each other (they are parallel)there are infinitely many solutions if the lines overlap each other (they are the same equation multiplied by some constant)Step-by-step explanation:
1st system
y = -x – 7
y = 4/3 x – 7
solution: x= 0, y = 7
2nd system
y = -3x – 5
y = x + 3
solution: x = -2, y = 1
3rd system
y = -2x + 5
y = 1/3 x – 2
solution: x = 3, y = -1
4th system
3x + 2y = 2
x + 2y = -2
solution: x = 2, y = -2
5th system
x + 3y = -9
2x – y = -4
solution: x = -3, y = -2
6th system
x – 2y = 2
-x + 4y = -8
solution: x = -4, y = -3
7th system
5x + y = -2
x + y = 2
solution: x = -1, y = -3
Step-by-step explanation:
Given infinite system of linear equations is ax + by = 0
when (a,b) moves along unit circle in plane.
a) system having unique system (0, 0)
Since two of equation in thus system will be
and
It is clear that x = 0, y= 0 is the only solution
b) Linear independent solution in this system gives some set of solutions
and
Vector form is
c) for this equation if add 0x +0y = 0 to system , Nothing will change
Because [0,0] satisfies that equation
d) If one of the equation is ax + by = 0.00001
where 0.00001 is small positive number
so, the system will be inconsistent
Therefore, the system will have no solution.
It will provide an instant answer!