Doug bought a new car for $25,000. he estimates his car will depreciate, or lose value, at a rate of 20% per year. the value of his car is modeled by the equation v = p(1 – r)t, where v is the value of the car, p is the price he paid, r is the annual rate of depreciation, and t is the number of years he has owned the car. according to the model, what will be the approximate value of his car after mc013-1.jpg years?
$2,500
$9,159
$22,827
$23,802

Step-by-step explanation:

The equation actually looks like this

and filling in the info given:

which simplifies to

Orders of operation tells us that we need to take care of the exponential stuff first, so

V = 25,000(.3663573) and

V = $9158.93 which rounds to what is shown as the second choice down: $9,159.

SI=(P*R*T)/100

P=2000

R=1.5

T=6

SI=(2000*1.5*6)/100

=(2000*9)/100

=180

Neil will earn interest of 180

The total nom of  code that can be used is equal to 5+3 = 8

For every 8 cars there are 7 trucks

Therefore,

Cars:Truck=8:7

Answer is B)8:7

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

The solution is given in the image below

The wood before starting =12 feet

Left wood=6 feet

Wood used till now=12-6=6 feet

Picture frame built till now= 6/(3/4)

=8 pieces

Therefore, till now 8 pieces have been made.