Mathematics: Divide the difference between 1200 and 700 by 5

1200 minus 700=500 divided by 5=100...

Divide the difference between 1200 and 700 by, №15223105, 04.01.2020 13:27

History

A) Identify ONE similarity between the economic factors that encouraged trade on the Silk Road and the Indian Ocean trade networks in the period from 1200 to 1450 CE. b) Identify ONE difference between the technologies used to expand trade on the Silk Road and the Indian Ocean trade networks in the period from 1200 to 1450 CE. c) Identify ONE similarity between the cultural effects of the development of trade on the Silk Road and the Indian Ocean trade networks in the period from 1200 to 1450 CE.

Step-by-step answer

P Answered by PhD

A. One economic similarity between the Silk Roads and Indian Ocean trade has a lot to do with the ultimate benefits. In both of these trades, a lot of wealth was built up for countries involved, helping them thrive in such a way that they would continue to trade because of it.

B. A difference between the technology used to expand the trade on the Silk Road vs the Indian Ocean trade would be the different ways they had of travel. On the Silk Road, they would travel by land. This was primarily by wagon. On the other hand, the Indian Ocean trade mainly used ships to trade. They would sail on the ocean, making them reliant on something totally different than those involved with the Silk Road.

C. Some cultural similarities between the two trade networks would be the connection it helped build between countries. China and Europe were able to share ideas and inventions with one-another, thus helping create a bond. On the other hand, with the Indian Ocean trade, India began to convert to Islam as a religion, therefore creating more bonds with their counterparts. Ultimately, the two trade networks adopted ways of living and different inventions through those they were trading with.

History

A) Identify ONE similarity between the economic factors that encouraged trade on the Silk Road and the Indian Ocean trade networks in the period from 1200 to 1450 CE. b) Identify ONE difference between the technologies used to expand trade on the Silk Road and the Indian Ocean trade networks in the period from 1200 to 1450 CE. c) Identify ONE similarity between the cultural effects of the development of trade on the Silk Road and the Indian Ocean trade networks in the period from 1200 to 1450 CE.

Step-by-step answer

P Answered by Master

10

A) One economic similarity between the Indian Ocean Trade and the Silk Road was that everyone benefited from them. Because of the two trade networks, wealth was achieved by anyone who participated in trade. Trade led to new ideas, methods, and technologies, no one was at a disadvantage because of trade. Because of China’s isolationism famine was introduced, technological advances slowed down, and China lost its status as a global power.

B) One difference between the technologies used to expand trade were the methods of transportation. By the Indian Ocean Trade people used boats, and improved them. New types of ships called junks and dhows were used to use monsoons to their advantage, while the astrolabe and compass were able to help with directions out at sea. The Silk Road on the other hand traveled by use of wagons, which didn’t really have anything to improve upon.

C) One similarity between the cultural effects of the two trade networks was the spread and fusion of multiple cultures. Specifically Indian culture. Islam began to spread on the Silk Road and change the spiritual beliefs of people in Southeast Asia. (Ex: The Sailendra kingdom in central Java, built Buddhist monuments and Hindu temples between the eighth and tenth centuries.)

History

I NEED THESE ALL NOW PLEASE a) Explain ONE specific similarity between state systems in the Americas from 1200 to 1450. Use the maps and your reading to support your answer. b) Explain ONE specific difference between state systems in the Americas from 1200 to 1450. Use the maps and your reading to support your answer. c) Explain ONE reason state systems in the Americas from 1200 to 1450 developed differently. Use the maps and your reading to support your answer.

Step-by-step answer

P Answered by PhD

5

Hello. You did not present the map to which the question refers which can make it difficult for an efficient answer to be established, but I will try to help you in the best possible way.

a. The state systems in these two periods are the presence and influence of Native Americans in the management of the site, especially in relation to the distribution of resources. We cannot fail to mention that these state systems resembled their establishment close to regions close to rivers with bodies of water that would promote the establishment of agriculture, making people's lives easier.

b. Regarding the differences, we can mention that one of the state systems, the Hopewell region, presented a rapid expansion, encompassing a much larger territory in the Chaco region, allowing the state of Hopewell to be more relevant, but this does not mean that the state of Chaco was weak and small, it just did not show such a strong expansion.

c. The differences in the development of these states occurred mainly due to the geographical and environmental differences in which they were submitted, since these factors strongly influence the establishment of societies.

Mathematics

HELP ME PLS I m trying to pass Algebra 1 with A or my parents will be disappointed. 1. Adelle solved the equation 4x/7 - 6 = -20 as shown. Fill in the correct justification for each step. Step: Justification: 4x/7 - 6 = -20 Given 4x/7 = -14 4x = -98 x = -24.5 2. Graph 4x + y = 6x - 1 SHOW YOUR WORK and explain the method used to determine the graph. 3. Dr. Silas studies a culture of bacteria under a microscope. The function b_1 (t) = 1200(1.8)^t represents the number of bacteria t hours after Dr. Silas begins her study. What does the value 1200

Step-by-step answer

P Answered by Master

1

1. Step: Justification:

4x/7 - 6 = -20 Given.

4x/7 = -14 4x/7 = 26

4x = -98 7/4 * 4x/7 = 7/4 * 26

x = -24.5 x = 91/2 or 45.5

2. Graph 4x + y = 6x -1

4x + y = 6x – 1

y = 6x – 1 – 4x

y = 2x – 1

Slope = x

Y-intercept = (0,-1)

Attached photo below is the following graph. (Make sure you attach the graph to question 2 or you won't get credit).

3. (A) 1200 is the initial population of the bacterial population.

(B) 1.8 represents the rate at which the count of bacteria increases each hour.

(C) 1000 represents the initial number of bacteria in the 2nd study based on the exponential growth function f(x) = a (1 + r)^x 1000 = a in this function.

The difference between 1200 and 1000 is the difference between the two initial counts in the two studies.

Mathematics

HELP ME PLS I m trying to pass Algebra 1 with A or my parents will be disappointed. 1. Adelle solved the equation 4x/7 - 6 = -20 as shown. Fill in the correct justification for each step. Step: Justification: 4x/7 - 6 = -20 Given 4x/7 = -14 4x = -98 x = -24.5 2. Graph 4x + y = 6x - 1 SHOW YOUR WORK and explain the method used to determine the graph. 3. Dr. Silas studies a culture of bacteria under a microscope. The function b_1 (t) = 1200(1.8)^t represents the number of bacteria t hours after Dr. Silas begins her study. What does the value 1200

Step-by-step answer

P Answered by Specialist

1

1. Step: Justification:

4x/7 - 6 = -20 Given.

4x/7 = -14 4x/7 = 26

4x = -98 7/4 * 4x/7 = 7/4 * 26

x = -24.5 x = 91/2 or 45.5

2. Graph 4x + y = 6x -1

4x + y = 6x – 1

y = 6x – 1 – 4x

y = 2x – 1

Slope = x

Y-intercept = (0,-1)

Attached photo below is the following graph. (Make sure you attach the graph to question 2 or you won't get credit).

3. (A) 1200 is the initial population of the bacterial population.

(B) 1.8 represents the rate at which the count of bacteria increases each hour.

(C) 1000 represents the initial number of bacteria in the 2nd study based on the exponential growth function f(x) = a (1 + r)^x 1000 = a in this function.

The difference between 1200 and 1000 is the difference between the two initial counts in the two studies.

Mathematics

A nonprofit bank that provides loans to small entrepreneurs in developing countries is considering organizing a mandatory training on good financial practices for all its loan-takers. To verify whether attending the course affects the chance that borrowers repay their short-term debt, two years ago the bank randomly split 2400 loan applicants into a group of 1200 subjects that received the mandatory training and a group of 1200 subjects that didn t receive it. The repayments of these 2400 loans were due last month. The bank is now looking at the

Step-by-step answer

P Answered by Master

Step-by-step explanation:

From the given information:

For trained subjects:

sample size n_1 = 1200

The sample mean x_1 = 789

For non-trained subjects:

Sample size n_2 = 1200

The sample mean = 632

For trained subjects, the proportion who repaid the loan is:

$\hat p_1 = \dfrac{x_1}{n_1}$

$\hat p_1 = \dfrac{789}{1200}$

$\hat p_1 = 0.6575$

For non-trained loan takers, the proportion who repaid the loan was:

$\hat p_2 = \dfrac{x_2}{n_2}$

$\hat p_2 = \dfrac{632}{1200}$

$\hat p_2 = 0.5266$

The confidence interval for the difference between the given proportion is:

= $[ ( \hat p_1 - \hat p_2 ) - E \ , \ (\hat p_1 - \hat p_2 ) + E ]$

where;

Level of significance = 1 - C.I

= 1 - 0.95

= 0.05

Z - Critical value at ∝ = 0.05 is 1.96

The Margin of Error (E) = $Z_{\alpha/2} \times \sqrt{\dfrac{\hat p_1 (1- \hat p_1) }{n_1} + \dfrac{\hat p_2 (1- \hat p_2)}{n_2} }$

$=1.96 \times \sqrt{\dfrac{0.658 (1- 0.658) }{1200} + \dfrac{0.527 (1- 0.527)}{1200} }$

$= 1.96 \times \sqrt{\dfrac{0.658 (0.342) }{1200} + \dfrac{0.527 (0.473)}{1200} }$

$= 1.96 \times \sqrt{1.8753 \times 10^{-4}+2.07725833 \times 10^{-4} }$

= 1.96 × 0.019881

≅ 0.039

The lower limit = $( \hat p_1 - \hat p_2) - E$

= (0.658 - 0.527) - 0.0389

= 0.131 - 0.0389

= 0.092

The upper limit = $( \hat p_1 - \hat p_2) + E$

= (0.658 - 0.527) + 0.0389

= 0.131 + 0.0389

= 0.167

Thus, 95% C.I for the difference between the proportion of trained and non-trianed loan takers who repaired the loan is:

$=0.092 \le p_1-p_2 \le 0.167$

For this study;

The null hypothesis is:

H_o : p_1 -p_2 = 0

The alternative hypothesis is:

$H_a : p_1 -p_2 \ne 0$

Since the C.I lie between (0.092, 0.17);

And the null hypothesis value does not lie within the interval (0.092, 0.17).

∴

we reject the null hypothesis H_o at ∝(0.05).

Conclusion: We conclude that there is enough evidence to claim that the proportion of trained and non-trained loan takers who repaired the loan are different.

Mathematics

A nonprofit bank that provides loans to small entrepreneurs in developing countries is considering organizing a mandatory training on good financial practices for all its loan-takers. To verify whether attending the course affects the chance that borrowers repay their short-term debt, two years ago the bank randomly split 2400 loan applicants into a group of 1200 subjects that received the mandatory training and a group of 1200 subjects that didn t receive it. The repayments of these 2400 loans were due last month. The bank is now looking at the

Step-by-step answer

P Answered by Specialist

Step-by-step explanation:

From the given information:

For trained subjects:

sample size n_1 = 1200

The sample mean x_1 = 789

For non-trained subjects:

Sample size n_2 = 1200

The sample mean = 632

For trained subjects, the proportion who repaid the loan is:

$\hat p_1 = \dfrac{x_1}{n_1}$

$\hat p_1 = \dfrac{789}{1200}$

$\hat p_1 = 0.6575$

For non-trained loan takers, the proportion who repaid the loan was:

$\hat p_2 = \dfrac{x_2}{n_2}$

$\hat p_2 = \dfrac{632}{1200}$

$\hat p_2 = 0.5266$

The confidence interval for the difference between the given proportion is:

= $[ ( \hat p_1 - \hat p_2 ) - E \ , \ (\hat p_1 - \hat p_2 ) + E ]$

where;

Level of significance = 1 - C.I

= 1 - 0.95

= 0.05

Z - Critical value at ∝ = 0.05 is 1.96

The Margin of Error (E) = $Z_{\alpha/2} \times \sqrt{\dfrac{\hat p_1 (1- \hat p_1) }{n_1} + \dfrac{\hat p_2 (1- \hat p_2)}{n_2} }$

$=1.96 \times \sqrt{\dfrac{0.658 (1- 0.658) }{1200} + \dfrac{0.527 (1- 0.527)}{1200} }$

$= 1.96 \times \sqrt{\dfrac{0.658 (0.342) }{1200} + \dfrac{0.527 (0.473)}{1200} }$

$= 1.96 \times \sqrt{1.8753 \times 10^{-4}+2.07725833 \times 10^{-4} }$

= 1.96 × 0.019881

≅ 0.039

The lower limit = $( \hat p_1 - \hat p_2) - E$

= (0.658 - 0.527) - 0.0389

= 0.131 - 0.0389

= 0.092

The upper limit = $( \hat p_1 - \hat p_2) + E$

= (0.658 - 0.527) + 0.0389

= 0.131 + 0.0389

= 0.167

Thus, 95% C.I for the difference between the proportion of trained and non-trianed loan takers who repaired the loan is:

$=0.092 \le p_1-p_2 \le 0.167$

For this study;

The null hypothesis is:

H_o : p_1 -p_2 = 0

The alternative hypothesis is:

$H_a : p_1 -p_2 \ne 0$

Since the C.I lie between (0.092, 0.17);

And the null hypothesis value does not lie within the interval (0.092, 0.17).

∴

we reject the null hypothesis H_o at ∝(0.05).

Conclusion: We conclude that there is enough evidence to claim that the proportion of trained and non-trained loan takers who repaired the loan are different.

History

Question 1 1 pts Question # 1: STATE -BUILDING IN VARIOUS PARTS OF THE WORLD BETWEEN 1200 - 1450 . . Give One Example of how the process of State Building in Various parts of the World Betweeen 1200 - 1450 were Similar. Give One Example of how the process of State-Building in Various parts of the World Betweeen 1200 - 1450 were Different. . Give another example of how the process of State-Building in Various parts of the World Between 1200 - 1450 were Different. HTML Editor

Step-by-step answer

P Answered by PhD

The correct answer to this open question is the following.

One example of how the process of state-building in various parts of the World between 1200 - 1450 was similar is the case of the Aztec Empire in Mesoamerica and the Inca Empire in South America.

The Aztec Empire founded its capital city over the Texcoco Lake. It was called the Great City of Tenochtitlan. It was an impressive city that had water canals that connected the city with other close towns such as Tlalpan, Tlatelolco, Mixcoatl, and Coyoacan. They established their power and dominion over other regions and towns by conquering them. They forced these towns to pay tribute and worship their gods.

The most important figure of the Aztecas was the Emperor, as was the case in the Inca Empire too.

The Incas founded its city in the Andean Mountains of Perú, in Macchu Picchu, an impressive city settlement at the top of the mountains. There, they developed advanced agriculture techniques and prospered due to the power exerted by the Emperor over other regions.

History

Question 1 1 pts Question # 1: STATE -BUILDING IN VARIOUS PARTS OF THE WORLD BETWEEN 1200 - 1450 . . Give One Example of how the process of State Building in Various parts of the World Betweeen 1200 - 1450 were Similar. Give One Example of how the process of State-Building in Various parts of the World Betweeen 1200 - 1450 were Different. . Give another example of how the process of State-Building in Various parts of the World Between 1200 - 1450 were Different. HTML Editor

Step-by-step answer

P Answered by PhD

The correct answer to this open question is the following.

One example of how the process of state-building in various parts of the World between 1200 - 1450 was similar is the case of the Aztec Empire in Mesoamerica and the Inca Empire in South America.

The Aztec Empire founded its capital city over the Texcoco Lake. It was called the Great City of Tenochtitlan. It was an impressive city that had water canals that connected the city with other close towns such as Tlalpan, Tlatelolco, Mixcoatl, and Coyoacan. They established their power and dominion over other regions and towns by conquering them. They forced these towns to pay tribute and worship their gods.

The most important figure of the Aztecas was the Emperor, as was the case in the Inca Empire too.

The Incas founded its city in the Andean Mountains of Perú, in Macchu Picchu, an impressive city settlement at the top of the mountains. There, they developed advanced agriculture techniques and prospered due to the power exerted by the Emperor over other regions.

Mathematics

A telephone service representative believes that the proportion of customers completely satisfied with their local telephone service is different between the Northeast and the Midwest. The representative s belief is based on the results of a survey. The survey included a random sample of 1200 northeastern residents and 1280 midwestern residents. 44% of the northeastern residents and 36% of the midwestern residents reported that they were completely satisfied with their local telephone service. Find the 80% confidence interval for the difference

Step-by-step answer

P Answered by PhD

a) The 80 % of confidence interval for the difference in two proportions.

(0.055 ,0.105)

b)The critical value that should be used in constructing intervals.

z₀.₂ = 1.28 ( from z-table) at 80 % of level of significance

Step-by-step explanation:

Step :1

Given data the survey included a random sample of 1200 northeastern residents and 1280 midwestern residents.

n₁ = 1200

n₂ = 1280

Given 44% of the northeastern residents reported that they were completely satisfied with their local telephone service.

The first proportion 'p₁' = 0.44

q₁ = 1- p₁ = 1- 0.44 = 0.56

Given 36% of the midwestern residents reported that they were completely satisfied with their local telephone service.

The second proportion 'p₂' = 0.36

q₂ = 1- p₂ = 1- 0.36 = 0.64

Step 2:-

The 80% confidence interval of p₁- p₂ are

(p₁- p₂ ± zα S.E (p₁- p₂)

where standard error of p₁- p₂

$S.E (p_{1}-p_{2} ) = \sqrt{\frac{p_{1}q_{1} }{n_{1} }+\frac{p_{2}q_{2} }{n_{2} } }$

substitute all values ,

$S.E (p_{1}-p_{2} ) = \sqrt{\frac{0.44X0.56 }{1200 }+\frac{0.36X0.64 }{1280 } }$

on calculation , we get

standard error of (p₁- p₂ ) = 0.0196

Step 3:-

a) The critical value that should be used in constructing intervals.

z₀.₂ = 1.28 ( from z-table) at 80 % of level of significance

Now the 80 % of confidence interval for the difference in two proportions.

(p₁- p₂ ± zα S.E (p₁- p₂)

((0.44-0.36) - 1.28 (0.0196) , 0.44-0.36 + 1.28 (0.0196))

(0.08 - 0.0250 ,0.08 + 0.0250)

(0.055 ,0.105)

Conclusion:-

the 80 % of confidence interval for the difference in two proportions.

(0.055 ,0.105)

Divide the difference between 1200 and 700 by 5

Step-by-step answer

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