4:1/2:3= : 2 :

Sure, but please understand that the process can look pretty complex when typed out in text. Here it goes:

Let's call the rows of the matrix as r1, r2, r3, r4 respectively.

The first step is to make the elements below the main diagonal as zeroes.

1) To make the first element of r2 as 0, we can subtract 3*r1 from r2. We get a new row:

New r2 = r2 - 3*r1 = [0, -10, -5, -3]

2) To make the first element of r3 as 0, we can add r1 to r3. We get a new row:

New r3 = r3 + r1 = [0, 4, 4, 5]

3) To make the first element of r4 as 0, we can subtract 2*r1 from r4. We get a new row:

New r4 = r4 - 2*r1 = [0, -7, 0, -6]

Now our transformed matrix looks like:

A = [[1, 4, 1, 2],
[0, -10, -5, -3],
[0, 4, 4, 5],
[0, -7, 0, -6]]

Now, let's make the second element of r3 and r4 as 0 using row operations.

1) To make the second element of r3 as 0, we can add 0.4*r2 to r3, because -10*0.4 = -4.

New r3 = r3 + 0.4*r2 = [0, 0, 2, 3]

2) To make the second element of r4 as 0, we can add 0.7*r2 to r4, because -10*0.7 = 7.

New r4 = r4 + 0.7*r2 = [0, 0, -3.5, -8.1]

Now, the matrix A looks like:

A = [[1, 4, 1, 2],
[0, -10, -5, -3],
[0, 0, 2, 3],
[0, 0, -3.5, -8.1]]

Lastly, let's turn the third element of r4 into 0. We can directly add 1.75*r3 to r4 here, because 2*1.75 = 3.5.

New r4 = r4 + 1.75*r3 = [0, 0, 0, -2.75]

Our final upper triangular matrix A looks like:

A = [[1, 4, 1, 2],
[0, -10, -5, -3],
[0, 0, 2, 3],
[0, 0, 0, -2.75]]

Finally, the determinant of a triangular matrix is the product of its diagonals.

So, the determinant(Det(A)) = 1*(-10)*2*(-2.75) = 55.

-Pay EXTRA attention when multiplying or adding fractions and follow the normal multiplication and addition rules for fractions.
-Lastly, ensure your work is accurate by verifying your work at each step!

Check photo for steps and details. if you think my answer is helpful please drop a like and mark me as brainliest!

Check photo for steps and details. if you think my answer is helpful please drop a like and mark me as brainliest!

1. The answer would be (D). This is because you will plug is the (x) of the ordered pair into the equation(y=-2x), so first off would be (y=-2(-2)). since your multiplying a negative time a negative, you will get your (y) which is 4. Now you do this with the rest. -2(1)=-2 and -2(3)=-6.
2. This would be (A). This answer is simple. First you will take one of the equations (y=-x-1) and plug x into it's place so, y=-3-1, getting your answer(y) as being -4. Now you do the same with the other pair. y=-5-1, getting -6, showing (A) as your answer.
3.The answer will be (A)y is 2 times x. this is because you wou would make out the equation from the answer (y=2x). Now knowing your equation, all thats left is plugging in your (x) factors. so y=2(1), getting your (y) value of 2 and you would do this with the rest of your x factors. 
4. y=5+x
    y=5+(2)= 7
    y=5+(3)= 8
    y=5+(4)= 9
5. (B)y is 3 times x
    y=3(x)
    y=3(3)=9
    y=3(4)=12
    y=3(5)=15
6. (C)y is 6 less than x
    y=6-(x)
    y=6-(8)=2
    y=6-(9)=3
    y=6-(10)=4

1. The answer would be (D). This is because you will plug is the (x) of the ordered pair into the equation(y=-2x), so first off would be (y=-2(-2)). since your multiplying a negative time a negative, you will get your (y) which is 4. Now you do this with the rest. -2(1)=-2 and -2(3)=-6.
2. This would be (A). This answer is simple. First you will take one of the equations (y=-x-1) and plug x into it's place so, y=-3-1, getting your answer(y) as being -4. Now you do the same with the other pair. y=-5-1, getting -6, showing (A) as your answer.
3.The answer will be (A)y is 2 times x. this is because you wou would make out the equation from the answer (y=2x). Now knowing your equation, all thats left is plugging in your (x) factors. so y=2(1), getting your (y) value of 2 and you would do this with the rest of your x factors. 
4. y=5+x
    y=5+(2)= 7
    y=5+(3)= 8
    y=5+(4)= 9
5. (B)y is 3 times x
    y=3(x)
    y=3(3)=9
    y=3(4)=12
    y=3(5)=15
6. (C)y is 6 less than x
    y=6-(x)
    y=6-(8)=2
    y=6-(9)=3
    y=6-(10)=4

To compare the mean rainfall between the two time periods, let's calculate the mean rainfall for each period and then compare the results.

For Period 1, we have the following rainfall data:
2.3, 2.1, 2.2, 2.2, 2.2, 2.1, 2.4, 2.5, 2.2, 2.0, 1.9, 1.9, 2.1, 2.2, 2.3

To find the mean, we need to add up all the values and divide the sum by the total number of values. Here's the step-by-step calculation:

Mean of Period 1 = (2.3 + 2.1 + 2.2 + 2.2 + 2.2 + 2.1 + 2.4 + 2.5 + 2.2 + 2.0 + 1.9 + 1.9 + 2.1 + 2.2 + 2.3) / 15

Using a calculator or by performing the addition manually, we get:

Mean of Period 1 = 33.1 / 15

Mean of Period 1 = 2.2067 (rounded to four decimal places)

Now let's calculate the mean rainfall for Period 2 using the provided data:
2.3, 2.1, 3.3, 1.5, 3.6, 1.6, 3.0, 1.1, 4.7, 2.1, 2.4, 1.9, 2.8, 0.5, 2.3

Mean of Period 2 = (2.3 + 2.1 + 3.3 + 1.5 + 3.6 + 1.6 + 3.0 + 1.1 + 4.7 + 2.1 + 2.4 + 1.9 + 2.8 + 0.5 + 2.3) / 15

Again, performing the addition:

Mean of Period 2 = 33.2 / 15

Mean of Period 2 = 2.2133 (rounded to four decimal places)

Now, comparing the means of Period 1 and Period 2, we can see that:

a. The mean in period 2 is higher than the mean in period 1.

Therefore, the correct answer is option a. The mean in period 2 is higher than the mean in period 1.

This conclusion is based on the calculations we performed and shows that the mean rainfall in Period 2 is slightly higher than the mean rainfall in Period 1.

To determine the agreement in the data sets, we need to compare the variability or spread of the data in each period. A commonly used measure of variability is the standard deviation. The smaller the standard deviation, the more agreement or consistency there is in the data.

Let's calculate the standard deviations for both periods:

Period 1 data: 2.3, 2.1, 2.2, 2.2, 2.2, 2.1, 2.4, 2.5, 2.2, 2.0, 1.9, 1.9, 2.1, 2.2, 2.3

Step 1: Calculate the mean of the data set:
Mean = (2.3 + 2.1 + 2.2 + 2.2 + 2.2 + 2.1 + 2.4 + 2.5 + 2.2 + 2.0 + 1.9 + 1.9 + 2.1 + 2.2 + 2.3) / 15
Mean ≈ 2.18

Step 2: Calculate the squared deviation of each data point from the mean:
(2.3 - 2.18)^2, (2.1 - 2.18)^2, (2.2 - 2.18)^2, (2.2 - 2.18)^2, (2.2 - 2.18)^2, (2.1 - 2.18)^2, (2.4 - 2.18)^2, (2.5 - 2.18)^2, (2.2 - 2.18)^2, (2.0 - 2.18)^2, (1.9 - 2.18)^2, (1.9 - 2.18)^2, (2.1 - 2.18)^2, (2.2 - 2.18)^2, (2.3 - 2.18)^2

Step 3: Calculate the sum of the squared deviations:
Sum ≈ 0.2156

Step 4: Calculate the variance:
Variance = Sum / (n - 1) where n is the number of data points
Variance ≈ 0.2156 / 14 ≈ 0.0154

Step 5: Calculate the standard deviation:
Standard Deviation = √Variance
Standard Deviation ≈ √0.0154 ≈ 0.124

Now let's calculate the standard deviation for Period 2:

Period 2 data: 2.3, 2.1, 3.3, 1.5, 3.6, 1.6, 3.0, 1.1, 4.7, 2.1, 2.4, 1.9, 2.8, 0.5, 2.3

Step 1: Calculate the mean of the data set:
Mean = (2.3 + 2.1 + 3.3 + 1.5 + 3.6 + 1.6 + 3.0 + 1.1 + 4.7 + 2.1 + 2.4 + 1.9 + 2.8 + 0.5 + 2.3) / 15
Mean ≈ 2.2467

Step 2: Calculate the squared deviation of each data point from the mean:
(2.3 - 2.2467)^2, (2.1 - 2.2467)^2, (3.3 - 2.2467)^2, (1.5 - 2.2467)^2, (3.6 - 2.2467)^2, (1.6 - 2.2467)^2, (3.0 - 2.2467)^2, (1.1 - 2.2467)^2, (4.7 - 2.2467)^2, (2.1 - 2.2467)^2, (2.4 - 2.2467)^2, (1.9 - 2.2467)^2, (2.8 - 2.2467)^2, (0.5 - 2.2467)^2, (2.3 - 2.2467)^2

Step 3: Calculate the sum of the squared deviations:
Sum ≈ 5.8233

Step 4: Calculate the variance:
Variance = Sum / (n - 1) where n is the number of data points
Variance ≈ 5.8233 / 14 ≈ 0.4167

Step 5: Calculate the standard deviation:
Standard Deviation = √Variance
Standard Deviation ≈ √0.4167 ≈ 0.645

Comparing the standard deviations, we can conclude that the standard deviation for Period 1 (0.124) is smaller than the standard deviation for Period 2 (0.645). This means that there is more agreement in the data in Period 1 than in Period 2.

Therefore, the correct answer is option (a): There is more agreement in the data in period 1 than in period 2.

The answer is A. president Bush didn't take any actions towards the terrorists until they attacked the U.S.

When numbers are divided, the integer portion is kept and the remainder is disregarded (meaning 10/9 would return 1). Following this format, we get the answer of 6 6 6 3 7 7 9 5 8 8. 
I also see that this program can be optimized because you use the same for loop twice, and both of them manipulate list elements in some way. A more optimized program would be:

int a [] = {64 , 66 , 67 , 37 , 73 , 70 , 95 , 52 , 81 , 82};

for (int i = 0; i < a.length; i++) {
  a[i] = a[i] / 10;
  System.out.print(a[i] + " ");
}

Or maybe you don't need to store the list values for later on. You could do:

for (int i = 0; i < a.length; i++) {
  System.out.print(a[i] / 10 + " ");
}

In any situation, your answer is choice 2.