Match the pairs of values of f(x) and g(x) with, №15230584, 11.11.2021 14:56

Mathematics

Match the pairs of values of f(x) and g(x) with the corresponding values of h(x) if h(x) = f(x) ÷ g(x). tiles f(x) = x2 − 9, and g(x) = x − 3 f(x) = x2 − 4x + 3, and g(x) = x − 3 f(x) = x2 + 4x − 5, and g(x) = x − 1 f(x) = x2 − 16, and g(x) = x − 4 pairs h(x) = x + 5 arrowboth h(x) = x + 3 arrowboth h(x) = x + 4 arrowboth h(x) = x − 1 arrowboth

Step-by-step answer

P Answered by PhD

82

For this case we must solve each of the functions.
We have then:

f (x) = x2 - 9, and g (x) = x - 3
h (x) = (x2 - 9) / (x - 3)
h (x) = ((x-3) (x + 3)) / (x - 3)
h (x) = x + 3

f (x) = x2 - 4x + 3, and g (x) = x - 3
h (x) = (x2 - 4x + 3) / (x - 3)
h (x) = ((x-3) (x-1)) / (x - 3)
h (x) = x-1

f (x) = x2 + 4x - 5, and g (x) = x - 1
h (x) = (x2 + 4x - 5) / (x - 1)
h (x) = ((x + 5) (x-1)) / (x - 1)
h (x) = x + 5

f (x) = x2 - 16, and g (x) = x - 4
h (x) = (x2 - 16) / (x - 4)
h (x) = ((x-4) (x + 4)) / (x - 4)
h (x) = x + 4

Mathematics

Match the pairs of values of f(x) and g(x) with the corresponding values of h(x) if h(x) = f(x) ÷ g(x). tiles f(x) = x2 − 9, and g(x) = x − 3 f(x) = x2 − 4x + 3, and g(x) = x − 3 f(x) = x2 + 4x − 5, and g(x) = x − 1 f(x) = x2 − 16, and g(x) = x − 4 pairs h(x) = x + 5 arrowboth h(x) = x + 3 arrowboth h(x) = x + 4 arrowboth h(x) = x − 1 arrowboth

Step-by-step answer

P Answered by PhD

82

For this case we must solve each of the functions.
We have then:

f (x) = x2 - 9, and g (x) = x - 3
h (x) = (x2 - 9) / (x - 3)
h (x) = ((x-3) (x + 3)) / (x - 3)
h (x) = x + 3

f (x) = x2 - 4x + 3, and g (x) = x - 3
h (x) = (x2 - 4x + 3) / (x - 3)
h (x) = ((x-3) (x-1)) / (x - 3)
h (x) = x-1

f (x) = x2 + 4x - 5, and g (x) = x - 1
h (x) = (x2 + 4x - 5) / (x - 1)
h (x) = ((x + 5) (x-1)) / (x - 1)
h (x) = x + 5

f (x) = x2 - 16, and g (x) = x - 4
h (x) = (x2 - 16) / (x - 4)
h (x) = ((x-4) (x + 4)) / (x - 4)
h (x) = x + 4

Mathematics

Match the pairs of values of f(x) and g(x) with the corresponding values of h(x) if h(x) = f(x) ÷ g(x). f(x) = x2 − 9, and g(x) = x − 3 f(x) = x2 − 4x + 3, and g(x) = x − 3 f(x) = x2 + 4x − 5, and g(x) = x − 1 f(x) = x2 − 16, and g(x) = x − 4 h(x) = x + 5 arrowright h(x) = x + 3 arrowright h(x) = x + 4 arrowright h(x) = x − 1 arrowright reset next

Step-by-step answer

P Answered by PhD

11

1. x + 3

2. x - 1

3. x + 5

4. x + 4

Step-by-step explanation:

1. If f(x) = x² - 9 and g(x) = x - 3, then h(x) = f(x) ÷ g(x) = (x² - 9) ÷ (x - 3) = [(x + 3)(x - 3)] ÷ (x - 3) = x + 3

2. If f(x) = x² - 4x + 3 and g(x) = x - 3, then h(x) = f(x) ÷ g(x) = (x² - 4x + 3) ÷ (x - 3) = [(x - 1)(x - 3)] ÷ (x - 3) = x - 1

3. If f(x) = x² + 4x - 5 and g(x) = x - 1, then h(x) = f(x) ÷ g(x) = (x² + 4x - 5) ÷ (x - 1) = [(x - 1)(x + 5)] ÷ (x - 1) = x + 5

4. If f(x) = x² - 16 and g(x) = x - 4, then h(x) = f(x) ÷ g(x) = (x² - 16) ÷ (x - 4) = [(x - 4)(x + 4)] ÷ (x - 4) = x + 4. (Answer)

Mathematics

Match the pairs of values of f(x) and g(x) with the corresponding values of h(x) if h(x) = f(x) ÷ g(x). f(x) = x2 − 9, and g(x) = x − 3 f(x) = x2 − 4x + 3, and g(x) = x − 3 f(x) = x2 + 4x − 5, and g(x) = x − 1 f(x) = x2 − 16, and g(x) = x − 4 h(x) = x + 5 arrowright h(x) = x + 3 arrowright h(x) = x + 4 arrowright h(x) = x − 1 arrowright reset next

Step-by-step answer

P Answered by PhD

11

1. x + 3

2. x - 1

3. x + 5

4. x + 4

Step-by-step explanation:

1. If f(x) = x² - 9 and g(x) = x - 3, then h(x) = f(x) ÷ g(x) = (x² - 9) ÷ (x - 3) = [(x + 3)(x - 3)] ÷ (x - 3) = x + 3

2. If f(x) = x² - 4x + 3 and g(x) = x - 3, then h(x) = f(x) ÷ g(x) = (x² - 4x + 3) ÷ (x - 3) = [(x - 1)(x - 3)] ÷ (x - 3) = x - 1

3. If f(x) = x² + 4x - 5 and g(x) = x - 1, then h(x) = f(x) ÷ g(x) = (x² + 4x - 5) ÷ (x - 1) = [(x - 1)(x + 5)] ÷ (x - 1) = x + 5

4. If f(x) = x² - 16 and g(x) = x - 4, then h(x) = f(x) ÷ g(x) = (x² - 16) ÷ (x - 4) = [(x - 4)(x + 4)] ÷ (x - 4) = x + 4. (Answer)

Mathematics

Match the pairs of values of f(x) and g(x) with the corresponding values of h(x) if h(x) = f(x) ÷ g(x). screenshot of the tiles below ( )

Step-by-step answer

P Answered by Master

143

1)f(x)/g(x)=(x^2-9)/(x-3)=x+3
2)f(x)/g(x)=x^2-4x+3/x-3=x+1
3)f(x)/g(x)=x^2+4x-5/x-1=x+5
4)f(x)/g(x)=x^2-16/x-4=x+4

Mathematics

Match the pairs of values of f(x) and g(x) with the corresponding values of h(x) if h(x) = f(x) ÷ g(x). screenshot of the tiles below ( )

Step-by-step answer

P Answered by Specialist

143

1)f(x)/g(x)=(x^2-9)/(x-3)=x+3
2)f(x)/g(x)=x^2-4x+3/x-3=x+1
3)f(x)/g(x)=x^2+4x-5/x-1=x+5
4)f(x)/g(x)=x^2-16/x-4=x+4

Mathematics

Problem: a non-linear system consists of two functions: f(x)=x²+2x+1 and g(x)=3-x-x². solve this system in two different ways. your choices are: table, graph, or algebraically. a. make a table of values for the functions. the table may be horizontal or vertical but it must have a minimum of five x-values and the corresponding function values showing each solution, one value lower, one value higher, and one between the two solutions. indicate the solutions by marking the x-values and the corresponding function values that are equal. b. solve the

Step-by-step answer

P Answered by PhD

2

Part B. see the procedure

Part C. see the procedure

Step-by-step explanation:

we have

$f(x)=x^{2}+2x+1$ -----> equation A

$g(x)=3-x-x^{2}$ -----> equation B

Part B. Solve the system algebraically

equate the equation A and the equation B

$x^{2}+2x+1=3-x-x^{2}$

$2x^{2}+3x-2=0$

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$2x^{2}+3x-2=0$

so

$a=2\\b=3\\c=-2$

substitute in the formula

$x=\frac{-3(+/-)\sqrt{3^{2}-4a(2)(-2)}} {2(2)}$

$x=\frac{-3(+/-)\sqrt{25}} {4}$

$x=\frac{-3(+/-)5} {4}$

$x1=\frac{-3(+)5} {4}=0.5$

$x2=\frac{-3(-)5} {4}=-2$

Find the values of y

For x=0.5

$f(0.5)=0.5^{2}+2(0.5)+1=2.25$

For x=-2

$f(-2)=(-2)^{2}+2(-2)+1=1$

the solutions are the points

(0.5,2.25) and (-2,1)

Part C. Solve the system by graph

using a graphing tool

we know that

The solution of the non linear system is the intersection point both graphs

The intersection points are (0.5,2.25) and (-2,1)

therefore

The solutions are the points (0.5,2.25) and (-2,1)

see the attached figure

Mathematics

Problem: a non-linear system consists of two functions: f(x)=x²+2x+1 and g(x)=3-x-x². solve this system in two different ways. your choices are: table, graph, or algebraically. a. make a table of values for the functions. the table may be horizontal or vertical but it must have a minimum of five x-values and the corresponding function values showing each solution, one value lower, one value higher, and one between the two solutions. indicate the solutions by marking the x-values and the corresponding function values that are equal. b. solve the

Step-by-step answer

P Answered by PhD

2

Part B. see the procedure

Part C. see the procedure

Step-by-step explanation:

we have

$f(x)=x^{2}+2x+1$ -----> equation A

$g(x)=3-x-x^{2}$ -----> equation B

Part B. Solve the system algebraically

equate the equation A and the equation B

$x^{2}+2x+1=3-x-x^{2}$

$2x^{2}+3x-2=0$

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$2x^{2}+3x-2=0$

so

$a=2\\b=3\\c=-2$

substitute in the formula

$x=\frac{-3(+/-)\sqrt{3^{2}-4a(2)(-2)}} {2(2)}$

$x=\frac{-3(+/-)\sqrt{25}} {4}$

$x=\frac{-3(+/-)5} {4}$

$x1=\frac{-3(+)5} {4}=0.5$

$x2=\frac{-3(-)5} {4}=-2$

Find the values of y

For x=0.5

$f(0.5)=0.5^{2}+2(0.5)+1=2.25$

For x=-2

$f(-2)=(-2)^{2}+2(-2)+1=1$

the solutions are the points

(0.5,2.25) and (-2,1)

Part C. Solve the system by graph

using a graphing tool

we know that

The solution of the non linear system is the intersection point both graphs

The intersection points are (0.5,2.25) and (-2,1)

therefore

The solutions are the points (0.5,2.25) and (-2,1)

see the attached figure

Mathematics

If f(x) = 2x + 3 and g(x) = x2 − 1, find the values of combining these functions. match each combined function to its corresponding value. tiles (f + g)(2) (f − g)(4) (f ÷ g)(2) (f × g)(1) pairs -4 arrowboth arrowboth 10 arrowboth 0 arrowboth

Step-by-step answer

P Answered by Specialist

21

(f+g)(2)=10

(f-g)(4)=-4

(f÷ g)(2)= $\frac{7}{3}$

(f*g)(1)=0

Step-by-step explanation:

f(x) = 2x + 3 and g(x) = x^2 - 1

Lets find f(2) , f(4) , g(4) and g(2)

f(x) = 2x + 3[/tex[tex]f(2) = 2(2) + 3=7

f(4) = 2(4) + 3=11

f(1) = 2(1) + 3=5

g(x) = x^2 - 1

g(2) = 2^2 - 1=3

g(4) = 4^2 - 1=15

g(1) = 1^2 - 1=0

LEts find (f+g)(2)

(f+g)(2)= f(2) + g(2)=7+3=10

(f-g)(4)= f(4) - g(4)=11-15=-4

(f÷ g)(2)= $\frac{f(2)}{g(2)} =\frac{7}{3}$

(f*g)(1)= f(1) * g(1)=5*0=0

Mathematics

If f(x) = 2x + 3 and g(x) = x2 − 1, find the values of combining these functions. match each combined function to its corresponding value. tiles: 1) (f + g)(2) 2) (f − g)(4) 3) (f ÷ g)(2) (f × g)(1) pairs a) -4 b) 10 c) 0

Step-by-step answer

P Answered by Specialist

69

We determine the answers to these items by substituting the values before performing the operation.

1) (f + g)(2)
f(2) = 2(2) + 3 = 7
g(2) = 2² - 1 = 3
(f + g)(2) = 7 + 3 = 10 (Answer for 1 is B)

2) (f - g)(4)
f(4) = 2(4) + 3 = 11
g(4) = 4² - 1 = 15
(f - g)(4) = 11 - 15 = -4 (Answer for 2 is A)

3) (f ÷ g)(2) (f x g)(1)
We already have the values of f(2) and g(2) above (in number 1)
f(1) = 2(1) + 3 = 5
g(1) = 1² - 1 = 0
The answer to this item is zero because any number multiplied to zero is zero. Letter C.

Match the pairs of values of f(x) and g(x) with the corresponding values of h(x) if h(x)=f(x)+g(x)

Step-by-step answer

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