(5, -9)
Step-by-step explanation:
Let's multiply the function out:
f(x) = (x-8)(x-2)
The vertex is (h, k), where
h = -b/2a
and
k is plugging in h into the equation
a is the number before the x^2 term, hence a = 1b is the number before x term, hence b = -10c is the constant , hence c = 16Plugging these into the formula for h, we get:
Now pluggin in 5 into the equation we get:
Hence, vertex is (5, -9)