A) What is the formula will you use to solve the problem
B) What is value for x
C) What are the dimensions of the base
D) What is the area of the base

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Step-by-step answer

02.12.2022, solved by verified expert
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Answer:

see below

Step-by-step explanation:

A) The formula for the volume of a pyramid is V=Bh where B is the base area and h is the height. 

B)

Therefore for the given prism 

Equation is 216 = x(x+3)*18

x(x+3) = 12 

x = 2.27

C) dimenstions are 2.27 x 5.27

d) Area of the base = x(x+3) =2.27x5.27=  11.96

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Mathematics
Step-by-step answer
P Answered by PhD

V(x) = 66.02\ \text{in}^3 \ \vert \ _x_=_1_._9_6

Step-by-step explanation:

Part (a)

The volume of a rectangular prism is found using the formula: V = lwh.

In order to write a formula in terms of the variable x, we need to write expressions for the length, width, and height of the rectangle.

We can say the length is the bottom of the base of the prism. To find this value, we can subtract x and x from 15 and divide this by 2, since there are two equal rectangles (base and lid).

Length: \frac{15-2x}{2} =7.5-x

We can say the width is the side of the base of the prism. To find this value, we can subtract 2x from 10.

Width: 10-2x

The height of the prism can be x, which is the labeled length of the rectangle next to the base and lid.

Height: x

Now we are able to write a formula for volume in terms of x.

V(x)=(7.5-x)(10-2x)(x)V(x)=x(75-25x+2x^2)V(x)=75x-25x^2+2x^3Part (b)

The domain of the volume is where x > 0, 2x < 10, and 2x < 15.

This is because our expressions for length (\frac{15-2x}{2}), width (10-2x), and height (x) cannot go below 0, because you cannot have a negative value for measurement - realistically.

Therefore, if we take into account all of these restrictions on x, the domain is where 0 < x < 5.

x cannot be > 5 since that would not satisfy 2x < 10.

The domain of V for this problem situation is D: (0, 5).

Part (c)

In order to find the maximum volume of the rectangular prism using our formula we derived, we can use the idea of optimization in calculus.

Start by taking the derivative of V(x).

V'(x)=75-50x+6x^2

Set the derivative equal to 0. This gives us the critical point(s) in order to determine the extreme values of the function, aka where the max and min occur.

0=75-50x+6x^20=6x^2-50x+75

Solve for x by using the quadratic formula.

x=\frac{-(-50)\pm\sqrt{(-50)^2-4(6)(75)} }{2(6)}x=\frac{50\pm\sqrt{2500-1800}}{12}x=\frac{50\pm\sqrt{700} }{12}

Input this into your calculator and you should get:

x=6.37, \ 1.96

We are going to use x = 1.96 since 6.37 is NOT in the domain of V(x).

\boxed{x=1.96}

Now, since this value of x is going to give the maximum volume of this rectangular prism, or cardboard box, we can plug it back into the V(x) equation for volume to determine the maximum volume of the box.

V(1.96)=75(1.96)-25(1.96)^2+2(1.96)^3V(1.96) = 66.02\ \text{in}^3 \ \vert \ _x_=_1_._9_6

The maximum volume of the cardboard box is 66.02 in³ and the value of x that gives this is 1.96.

Mathematics
Step-by-step answer
P Answered by PhD

V(x) = 66.02\ \text{in}^3 \ \vert \ _x_=_1_._9_6

Step-by-step explanation:

Part (a)

The volume of a rectangular prism is found using the formula: V = lwh.

In order to write a formula in terms of the variable x, we need to write expressions for the length, width, and height of the rectangle.

We can say the length is the bottom of the base of the prism. To find this value, we can subtract x and x from 15 and divide this by 2, since there are two equal rectangles (base and lid).

Length: \frac{15-2x}{2} =7.5-x

We can say the width is the side of the base of the prism. To find this value, we can subtract 2x from 10.

Width: 10-2x

The height of the prism can be x, which is the labeled length of the rectangle next to the base and lid.

Height: x

Now we are able to write a formula for volume in terms of x.

V(x)=(7.5-x)(10-2x)(x)V(x)=x(75-25x+2x^2)V(x)=75x-25x^2+2x^3Part (b)

The domain of the volume is where x > 0, 2x < 10, and 2x < 15.

This is because our expressions for length (\frac{15-2x}{2}), width (10-2x), and height (x) cannot go below 0, because you cannot have a negative value for measurement - realistically.

Therefore, if we take into account all of these restrictions on x, the domain is where 0 < x < 5.

x cannot be > 5 since that would not satisfy 2x < 10.

The domain of V for this problem situation is D: (0, 5).

Part (c)

In order to find the maximum volume of the rectangular prism using our formula we derived, we can use the idea of optimization in calculus.

Start by taking the derivative of V(x).

V'(x)=75-50x+6x^2

Set the derivative equal to 0. This gives us the critical point(s) in order to determine the extreme values of the function, aka where the max and min occur.

0=75-50x+6x^20=6x^2-50x+75

Solve for x by using the quadratic formula.

x=\frac{-(-50)\pm\sqrt{(-50)^2-4(6)(75)} }{2(6)}x=\frac{50\pm\sqrt{2500-1800}}{12}x=\frac{50\pm\sqrt{700} }{12}

Input this into your calculator and you should get:

x=6.37, \ 1.96

We are going to use x = 1.96 since 6.37 is NOT in the domain of V(x).

\boxed{x=1.96}

Now, since this value of x is going to give the maximum volume of this rectangular prism, or cardboard box, we can plug it back into the V(x) equation for volume to determine the maximum volume of the box.

V(1.96)=75(1.96)-25(1.96)^2+2(1.96)^3V(1.96) = 66.02\ \text{in}^3 \ \vert \ _x_=_1_._9_6

The maximum volume of the cardboard box is 66.02 in³ and the value of x that gives this is 1.96.

Mathematics
Step-by-step answer
P Answered by PhD

SI=(P*R*T)/100

P=2000

R=1.5

T=6

SI=(2000*1.5*6)/100

=(2000*9)/100

=180

Neil will earn interest of 180

Mathematics
Step-by-step answer
P Answered by PhD

The answer is in the image 

The answer is in the image 
Mathematics
Step-by-step answer
P Answered by PhD

The solution is in the following image

The solution is in the following image
Mathematics
Step-by-step answer
P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Mathematics
Step-by-step answer
P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Approximately it is aqual to 1300kg

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